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This section includes 16 Mcqs, each offering curated multiple-choice questions to sharpen your Digital Signal Processing knowledge and support exam preparation. Choose a topic below to get started.
1. |
If X(k) is the N-point DFT of a sequence x(n), then what is the DFT of x*(n)? |
A. | X(N-k) |
B. | X*(k) |
C. | X*(N-k) |
D. | None of the mentioned |
Answer» D. None of the mentioned | |
2. |
If X(k) is the N-point DFT of a sequence x(n), then circular time shift property is that N-point DFT of x((n-l))N is X(k)e-j2πkl/N. |
A. | True |
B. | False |
Answer» B. False | |
3. |
What is the circular convolution of the sequences X1(n)={2,1,2,1} and x2(n)={1,2,3,4}, find using the DFT and IDFT concepts? |
A. | {16,16,14,14} |
B. | {14,16,14,16} |
C. | {14,14,16,16} |
D. | None of the mentioned |
Answer» C. {14,14,16,16} | |
4. |
What is the circular convolution of the sequences X1(n)={2,1,2,1} and x2(n)={1,2,3,4}? |
A. | {14,14,16,16} |
B. | {16,16,14,14} |
C. | {2,3,6,4} |
D. | {14,16,14,16} |
Answer» E. | |
5. |
If X1(n), x2(n) and x3(m) are three sequences each of length N whose DFTs are given as X1(k), X2(k) and X3(k) respectively and X3(k)=X1(k).X2(k), then what is the expression for x3(m)? |
A. | \(\sum_{n=0}^{N-1}x_1 (n) x_2 (m+n)\) |
B. | \(\sum_{n=0}^{N-1}x_1 (n) x_2 (m-n)\) |
C. | \(\sum_{n=0}^{N-1}x_1 (n) x_2 (m-n)_N \) |
D. | \(\sum_{n=0}^{N-1}x_1 (n) x_2 (m+n)_N \) |
Answer» D. \(\sum_{n=0}^{N-1}x_1 (n) x_2 (m+n)_N \) | |
6. |
If x(n) is real and odd, then what is the IDFT of the given sequence? |
A. | \(j \frac{1}{N} \sum_{k=0}^{N-1} x(k) sin\frac{2πkn}{N}\) |
B. | \(\frac{1}{N} \sum_{k=0}^{N-1} x(k) cos\frac{2πkn}{N}\) |
C. | \(-j \frac{1}{N} \sum_{k=0}^{N-1} x(k) sin\frac{2πkn}{N}\) |
D. | None of the mentioned |
Answer» B. \(\frac{1}{N} \sum_{k=0}^{N-1} x(k) cos\frac{2πkn}{N}\) | |
7. |
If x(n) is real and even, then what is the DFT of x(n)? |
A. | \(\sum_{n=0}^{N-1} x(n) sin\frac{2πkn}{N}\) |
B. | \(\sum_{n=0}^{N-1} x(n) cos\frac{2πkn}{N}\) |
C. | -j\(\sum_{n=0}^{N-1} x(n) sin\frac{2πkn}{N}\) |
D. | None of the mentioned |
Answer» C. -j\(\sum_{n=0}^{N-1} x(n) sin\frac{2πkn}{N}\) | |
8. |
If x(n) is a complex valued sequence given by x(n)=xR(n)+jxI(n), then what is the DFT of xR(n)? |
A. | \(\sum_{n=0}^N x_R (n) cos\frac{2πkn}{N}+x_I (n) sin\frac{2πkn}{N}\) |
B. | \(\sum_{n=0}^N x_R (n) cos\frac{2πkn}{N}-x_I (n) sin\frac{2πkn}{N}\) |
C. | \(\sum_{n=0}^{N-1} x_R (n) cos\frac{2πkn}{N}-x_I (n) sin\frac{2πkn}{N}\) |
D. | \(\sum_{n=0}^{N-1} x_R (n) cos\frac{2πkn}{N}+x_I (n) sin\frac{2πkn}{N}\) |
Answer» E. | |
9. |
WHAT_IS_THE_CIRCULAR_CONVOLUTION_OF_THE_SEQUENCES_X1(N)={2,1,2,1}_AND_X2(N)={1,2,3,4}??$ |
A. | {14,14,16,16} |
B. | {16,16,14,14} |
C. | {2,3,6,4} |
D. | {14,16,14,16} |
Answer» E. | |
10. |
If X(k) is the N-point DFT of a sequence x(n), then circular time shift property is that N-point DFT of x((n-l))N is X(k)e-j2πkl/N.$# |
A. | True |
B. | False |
Answer» B. False | |
11. |
What_is_the_circular_convolution_of_the_sequences_x1(n)={2,1,2,1}_and_x2(n)={1,2,3,4},_find_using_the_DFT_and_IDFT_concepts?$ |
A. | {16,16,14,14} |
B. | {14,16,14,16} |
C. | {14,14,16,16} |
D. | None of the mentioned |
Answer» C. {14,14,16,16} | |
12. |
If_X(k)_is_the_N-point_DFT_of_a_sequence_x(n),_then_what_is_the_DFT_of_x*(n)? |
A. | X(N-k) |
B. | X*(k) |
C. | X*(N-k) |
D. | None of the mentioned |
Answer» B. X*(k) | |
13. |
If x(n) is a real sequence and X(k) is its N-point DFT, then which of the following is true? |
A. | X(N-k)=X(-k) |
B. | X(N-k)=X*(k) |
C. | X(-k)=X*(k) |
D. | All of the mentioned |
Answer» E. | |
14. |
If X1(k) and X2(k) are the N-point DFTs of x1(n) and x2(n) respectively, then what is the N-point DFT of x(n)=ax1(n)+bx2(n)? |
A. | X1(ak)+X2(bk) |
B. | aX1(k)+bX2(k) |
C. | e<sup>ak</sup>X1(k)+e<sup>bk</sup>X2(k) |
D. | None of the mentioned |
Answer» C. e<sup>ak</sup>X1(k)+e<sup>bk</sup>X2(k) | |
15. |
If x(n) and X(k) are an N-point DFT pair, then X(k+N)=? |
A. | X(-k) |
B. | -X(k) |
C. | X(k) |
D. | None of the mentioned |
Answer» D. None of the mentioned | |
16. |
If x(n) and X(k) are an N-point DFT pair, then x(n+N)=x(n). |
A. | True |
B. | False |
Answer» B. False | |