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This section includes 12583 Mcqs, each offering curated multiple-choice questions to sharpen your Joint Entrance Exam - Main (JEE Main) knowledge and support exam preparation. Choose a topic below to get started.
| 11451. |
A simple harmonic wave having an amplitude a and time period T is represented by the equation \[y=5\sin \pi (t+4)m.\]Then the value of amplitude (a) in (m) and time period (T) in second are [Pb. PET 2004] |
| A. | \[a=10,\,T=2\] |
| B. | \[a=5,\,T=1\] |
| C. | \[a=10,T=1\] |
| D. | \[a=5,\,T=2\] |
| Answer» E. | |
| 11452. |
The displacement x (in metre) of a particle in, simple harmonic motion is related to time t (in seconds) as \[x=0.01\cos \left( \pi \,t+\frac{\pi }{4} \right)\] The frequency of the motion will be [UPSEAT 2004] |
| A. | 0.5 Hz |
| B. | 1.0 Hz |
| C. | \[\frac{\pi }{2}Hz\] |
| D. | \[\pi \,Hz\] |
| Answer» B. 1.0 Hz | |
| 11453. |
The equation of motion of a particle is \[\frac{{{d}^{2}}y}{d{{t}^{2}}}+Ky=0\], where K is positive constant. The time period of the motion is given by [AIEEE 2005] |
| A. | \[\frac{2\pi }{K}\] |
| B. | \[2\pi K\] |
| C. | \[\frac{2\pi }{\sqrt{K}}\] |
| D. | \[2\pi \sqrt{K}\] |
| Answer» D. \[2\pi \sqrt{K}\] | |
| 11454. |
A particle moves such that its acceleration a is given by \[a=-bx\], where x is the displacement from equilibrium position and b is a constant. The period of oscillation is [NCERT 1984; CPMT 1991; MP PMT 1994; MNR 1995; UPSEAT 2000] |
| A. | \[2\pi \sqrt{b}\] |
| B. | \[\frac{2\pi }{\sqrt{b}}\] |
| C. | \[\frac{2\pi }{b}\] |
| D. | \[2\sqrt{\frac{\pi }{b}}\] |
| Answer» C. \[\frac{2\pi }{b}\] | |
| 11455. |
Amplitude of a wave is represented by \[A=\frac{c}{a+b-c}\] Then resonance will occur when [CPMT 1984] |
| A. | \[b=-c/2\] |
| B. | b = 0 and a = ? c |
| C. | \[b=-a/2\] |
| D. | None of these |
| Answer» C. \[b=-a/2\] | |
| 11456. |
In case of a forced vibration, the resonance wave becomes very sharp when the [CBSE PMT 2003] |
| A. | Restoring force is small |
| B. | Applied periodic force is small |
| C. | Quality factor is small |
| D. | Damping force is small |
| Answer» E. | |
| 11457. |
Resonance is an example of [CBSE PMT 1999; BHU 1999; 2005] |
| A. | Tuning fork |
| B. | Forced vibration |
| C. | Free vibration |
| D. | Damped vibration |
| Answer» C. Free vibration | |
| 11458. |
If the displacement equation of a particle be represented by \[y=A\sin PT+B\cos PT\], the particle executes [MP PET 1986] |
| A. | A uniform circular motion |
| B. | A uniform elliptical motion |
| C. | A S.H.M. |
| D. | A rectilinear motion |
| Answer» D. A rectilinear motion | |
| 11459. |
The S.H.M. of a particle is given by the equation\[y=3\sin \omega \,t+4\cos \omega \,t\]. The amplitude is [MP PET 1993] |
| A. | 7 |
| B. | 1 |
| C. | 5 |
| D. | 12 |
| Answer» D. 12 | |
| 11460. |
A mass m oscillates with simple harmonic motion with frequency \[f=\frac{\omega }{2\pi }\] and amplitude A on a spring with constant K , therefore |
| A. | The total energy of the system is \[\frac{1}{2}K{{A}^{2}}\] |
| B. | The frequency is \[\frac{1}{2\pi }\sqrt{\frac{K}{M}}\] |
| C. | The maximum velocity occurs, when x = 0 |
| D. | All the above are correct |
| Answer» E. | |
| 11461. |
A mass m is suspended from a spring of length l and force constant K. The frequency of vibration of the mass is \[{{f}_{1}}\]. The spring is cut into two equal parts and the same mass is suspended from one of the parts. The new frequency of vibration of mass is \[{{f}_{2}}\]. Which of the following relations between the frequencies is correct [NCERT 1983; CPMT 1986; MP PMT 1991; DCE 2002] |
| A. | \[{{f}_{1}}=\sqrt{2}{{f}_{2}}\] |
| B. | \[{{f}_{1}}={{f}_{2}}\] |
| C. | \[{{b}^{2}}<4ac\] |
| D. | \[{{f}_{2}}=\sqrt{2}{{f}_{1}}\] |
| Answer» E. | |
| 11462. |
If a body of mass 0.98 kg is made to oscillate on a spring of force constant 4.84 N/m, the angular frequency of the body is [CBSE PMT 2001] |
| A. | 1.22 rad/s |
| B. | 2.22 rad/s |
| C. | 3.22 rad/s |
| D. | 4.22 rad/s |
| Answer» C. 3.22 rad/s | |
| 11463. |
When a mass m is attached to a spring, it normally extends by 0.2 m. The mass m is given a slight addition extension and released, then its time period will be [MH CET 2001] |
| A. | \[\frac{1}{7}\]sec |
| B. | 1 sec |
| C. | \[\frac{2\pi }{7}\]sec |
| D. | \[\frac{2}{3\pi }\]sec |
| Answer» D. \[\frac{2}{3\pi }\]sec | |
| 11464. |
An object is attached to the bottom of a light vertical spring and set vibrating. The maximum speed of the object is 15 cm/sec and the period is 628 milli-seconds. The amplitude of the motion in centimeters is [EAMCET 2003] |
| A. | 3 |
| B. | 2 |
| C. | 1.5 |
| D. | 1 |
| Answer» D. 1 | |
| 11465. |
A mass M is suspended from a spring of negligible mass. The spring is pulled a little and then released so that the mass executes S.H.M. of time period T. If the mass is increased by m, the time period becomes 5T/3. Then the ratio of m/M is [AIEEE 2003] |
| A. | \[\frac{5}{3}\] |
| B. | \[\frac{3}{5}\] |
| C. | \[\frac{25}{9}\] |
| D. | \[\frac{16}{9}\] |
| Answer» E. | |
| 11466. |
If a spring extends by x on loading, then energy stored by the spring is (if T is the tension in the spring and K is the spring constant) [AFMC 2000] |
| A. | \[\frac{{{T}^{2}}}{2x}\] |
| B. | \[\frac{{{T}^{2}}}{2K}\] |
| C. | \[\frac{2K}{{{T}^{2}}}\] |
| D. | \[\frac{2{{T}^{2}}}{K}\] |
| Answer» C. \[\frac{2K}{{{T}^{2}}}\] | |
| 11467. |
Two springs with spring constants \[{{K}_{1}}=1500\,N/m\] and \[{{K}_{2}}=3000\,N/m\] are stretched by the same force. The ratio of potential energy stored in spring will be [RPET 2001] |
| A. | 2 : 1 |
| B. | 1 : 2 |
| C. | 4 : 1 |
| D. | 1 : 4 |
| Answer» B. 1 : 2 | |
| 11468. |
When a body of mass 1.0 kg is suspended from a certain light spring hanging vertically, its length increases by 5 cm. By suspending 2.0 kg block to the spring and if the block is pulled through 10 cm and released the maximum velocity in it in m/s is : (Acceleration due to gravity \[=10m/{{s}^{2}})\] [EAMCET 2003] |
| A. | 0.5 |
| B. | 1 |
| C. | 2 |
| D. | 4 |
| Answer» C. 2 | |
| 11469. |
A mass M is suspended by two springs of force constants K1 and K2 respectively as shown in the diagram. The total elongation (stretch) of the two springs is [MP PMT 2000; RPET 2001] |
| A. | \[\frac{Mg}{{{K}_{1}}+{{K}_{2}}}\] |
| B. | \[\frac{Mg\,({{K}_{1}}+{{K}_{2}})}{{{K}_{1}}{{K}_{2}}}\] |
| C. | \[\frac{Mg\,{{K}_{1}}{{K}_{2}}}{{{K}_{1}}+{{K}_{2}}}\] |
| D. | \[\frac{{{K}_{1}}+{{K}_{2}}}{{{K}_{1}}{{K}_{2}}Mg}\] |
| Answer» C. \[\frac{Mg\,{{K}_{1}}{{K}_{2}}}{{{K}_{1}}+{{K}_{2}}}\] | |
| 11470. |
The frequency of oscillation of the springs shown in the figure will be [AIIMS 2001; Pb. PET 2002] |
| A. | \[\frac{1}{2\pi }\sqrt{\frac{K}{m}}\] |
| B. | \[\frac{1}{2\pi }\sqrt{\frac{({{K}_{1}}+{{K}_{2}})m}{{{K}_{1}}{{K}_{2}}}}\] |
| C. | \[2\pi \sqrt{\frac{K}{m}}\] |
| D. | \[\frac{1}{2\pi }\sqrt{\frac{{{K}_{1}}{{K}_{2}}}{m({{K}_{1}}+{{K}_{2}})}}\] |
| Answer» E. | |
| 11471. |
A mass m attached to a spring oscillates every 2 sec. If the mass is increased by 2 kg, then time-period increases by 1 sec. The initial mass is [CBSE PMT 2000; AIIMS 2000; MP PET 2000; DPMT 2001; Pb. PMT 2003] |
| A. | 1.6 kg |
| B. | 3.9 kg |
| C. | 9.6 kg |
| D. | 12.6 kg |
| Answer» B. 3.9 kg | |
| 11472. |
A simple pendulum is vibrating in an evacuated chamber, it will oscillate with [Pb. PMT 2004] |
| A. | Increasing amplitude |
| B. | Constant amplitude |
| C. | Decreasing amplitude |
| D. | First (c) then (a) |
| Answer» C. Decreasing amplitude | |
| 11473. |
The time period of a simple pendulum of length L as measured in an elevator descending with acceleration \[\frac{g}{3}\] is [CPMT 2000] |
| A. | \[2\pi \sqrt{\frac{3L}{g}}\] |
| B. | \[\pi \sqrt{\left( \frac{3L}{g} \right)}\] |
| C. | \[2\pi \sqrt{\left( \frac{3L}{2g} \right)}\] |
| D. | \[2\pi \sqrt{\frac{2L}{3g}}\] |
| Answer» D. \[2\pi \sqrt{\frac{2L}{3g}}\] | |
| 11474. |
The period of a simple pendulum measured inside a stationary lift is found to be T. If the lift starts accelerating upwards with acceleration of \[g/3,\]then the time period of the pendulum is [RPMT 2000; DPMT 2000, 03] |
| A. | \[\frac{T}{\sqrt{3}}\] |
| B. | \[\frac{T}{3}\] |
| C. | \[\frac{\sqrt{3}}{2}T\] |
| D. | \[\sqrt{3}\,T\] |
| Answer» D. \[\sqrt{3}\,T\] | |
| 11475. |
The velocity of simple pendulum is maximum at [RPMT 2004] |
| A. | Extremes |
| B. | Half displacement |
| C. | Mean position |
| D. | Every where |
| Answer» D. Every where | |
| 11476. |
There is a simple pendulum hanging from the ceiling of a lift. When the lift is stand still, the time period of the pendulum is T. If the resultant acceleration becomes \[g/4,\] then the new time period of the pendulum is [DCE 2004] |
| A. | 0.8 T |
| B. | 0.25 T |
| C. | 2 T |
| D. | 4 T |
| Answer» D. 4 T | |
| 11477. |
A simple pendulum is taken from the equator to the pole. Its period [Kerala (PET/PMT) 2005] |
| A. | Decreases |
| B. | Increases |
| C. | Remains the same |
| D. | Decreases and then increases |
| Answer» B. Increases | |
| 11478. |
A pendulum of length 2m lift at P. When it reaches Q, it losses 10% of its total energy due to air resistance. The velocity at Q is [DCE 1998] |
| A. | 6 m/sec |
| B. | 1 m/sec |
| C. | 2 m/sec |
| D. | 8 m/sec |
| Answer» B. 1 m/sec | |
| 11479. |
A simple pendulum hanging from the ceiling of a stationary lift has a time period T1. When the lift moves downward with constant velocity, the time period is T2, then [Orissa JEE 2005] |
| A. | \[{{T}_{2}}\] is infinity |
| B. | \[{{T}_{2}}>{{T}_{1}}\] |
| C. | \[{{T}_{2}}<{{T}_{1}}\] |
| D. | \[{{T}_{2}}={{T}_{1}}\] |
| Answer» C. \[{{T}_{2}}<{{T}_{1}}\] | |
| 11480. |
If the length of a pendulum is made 9 times and mass of the bob is made 4 times then the value of time period becomes [BHU 2005] |
| A. | 3T |
| B. | 3/2T |
| C. | 4T |
| D. | 2T |
| Answer» B. 3/2T | |
| 11481. |
The periodic time of a simple pendulum of length 1 m and amplitude 2 cm is 5 seconds. If the amplitude is made 4 cm, its periodic time in seconds will be [MP PMT 1985] |
| A. | 2.5 |
| B. | 5 |
| C. | 10 |
| D. | \[5\sqrt{2}\] |
| Answer» C. 10 | |
| 11482. |
A simple pendulum hangs from the ceiling of a car. If the car accelerates with a uniform acceleration, the frequency of the simple pendulum will [Pb. PMT 2000] |
| A. | Increase |
| B. | Decrease |
| C. | Become infinite |
| D. | Remain constant |
| Answer» B. Decrease | |
| 11483. |
The time period of a simple pendulum when it is made to oscillate on the surface of moon [J & K CET 2004] |
| A. | Increases |
| B. | Decreases |
| C. | Remains unchanged |
| D. | Becomes infinite |
| Answer» B. Decreases | |
| 11484. |
A simple pendulum consisting of a ball of mass m tied to a thread of length l is made to swing on a circular arc of angle\[\theta \] in a vertical plane. At the end of this arc, another ball of mass m is placed at rest. The momentum transferred to this ball at rest by the swinging ball is [NCERT 1977] |
| A. | Zero |
| B. | \[m\theta \sqrt{\frac{g}{l}}\] |
| C. | \[\frac{m\theta }{l}\sqrt{\frac{l}{g}}\] |
| D. | \[\frac{m}{l}2\pi \sqrt{\frac{l}{g}}\] |
| Answer» B. \[m\theta \sqrt{\frac{g}{l}}\] | |
| 11485. |
A simple pendulum is attached to the roof of a lift. If time period of oscillation, when the lift is stationary is T. Then frequency of oscillation, when the lift falls freely, will be [DCE 2002] |
| A. | Zero |
| B. | T |
| C. | 1/T |
| D. | None of these |
| Answer» B. T | |
| 11486. |
In a seconds pendulum, mass of bob is 30 gm. If it is replaced by 90 gm mass. Then its time period will [Orissa PMT 2001] |
| A. | 1 sec |
| B. | 2 sec |
| C. | 4 sec |
| D. | 3 sec |
| Answer» C. 4 sec | |
| 11487. |
The acceleration due to gravity at a place is\[{{\pi }^{2}}\,m/se{{c}^{2}}\]. Then the time period of a simple pendulum of length one metre is [JIPMER 2002] |
| A. | \[\frac{2}{\pi }sec\] |
| B. | \[2\pi \,sec\] |
| C. | \[2\,sec\] |
| D. | \[\pi \,sec\] |
| Answer» D. \[\pi \,sec\] | |
| 11488. |
The time period of a simple pendulum in a lift descending with constant acceleration g is [DCE 1998; MP PMT 2001] |
| A. | \[T=2\pi \sqrt{\frac{l}{g}}\] |
| B. | \[T=2\pi \sqrt{\frac{l}{2g}}\] |
| C. | Zero |
| D. | Infinite |
| Answer» E. | |
| 11489. |
A chimpanzee swinging on a swing in a sitting position, stands up suddenly, the time period will [KCET (Engg./Med.) 2000; AIEEE 2002; DPMT 2004] |
| A. | Become infinite |
| B. | Remain same |
| C. | Increase |
| D. | Decrease |
| Answer» E. | |
| 11490. |
If the metal bob of a simple pendulum is replaced by a wooden bob, then its time period will [AIIMS 1998, 99] |
| A. | Increase |
| B. | Decrease |
| C. | Remain the same |
| D. | First increase then decrease |
| Answer» D. First increase then decrease | |
| 11491. |
The time period of a simple pendulum is 2 sec. If its length is increased 4 times, then its period becomes [CBSE PMT 1999; DPMT 1999] |
| A. | 16 sec |
| B. | 12 sec |
| C. | 8 sec |
| D. | 4 sec |
| Answer» E. | |
| 11492. |
A pendulum bob has a speed of 3 m/s at its lowest position. The pendulum is 0.5 m long. The speed of the bob, when the length makes an angle of \[{{60}^{o}}\] to the vertical, will be (If \[g=10m/{{s}^{2}}\]) [MP PET 1996] |
| A. | \[\frac{E}{4}\] |
| B. | \[\frac{3E}{4}\] |
| C. | \[\frac{\sqrt{3}}{4}E\] |
| D. | \[{{K}_{1}}\] |
| Answer» E. | |
| 11493. |
The period of a simple pendulum is doubled, when [CPMT 1974; MNR 1980; AFMC 1995; Pb. PET/PMT 2002] |
| A. | Its length is doubled |
| B. | The mass of the bob is doubled |
| C. | Its length is made four times |
| D. | The mass of the bob and the length of the pendulum are doubled |
| Answer» D. The mass of the bob and the length of the pendulum are doubled | |
| 11494. |
A simple pendulum is made of a body which a hollow sphere is containing mercury suspended by means of a wire. If a little mercury is drained off, the period of pendulum will [NCERT 1972; BHU 1979] |
| A. | Remains unchanged |
| B. | Increase |
| C. | Decrease |
| D. | Become erratic |
| Answer» C. Decrease | |
| 11495. |
The period of oscillation of a simple pendulum of constant length at earth surface is T. Its period inside a mine is [CPMT 1973; DPMT 2001] |
| A. | Greater than T |
| B. | Less than T |
| C. | Equal to T |
| D. | Cannot be compared |
| Answer» B. Less than T | |
| 11496. |
One end of a spring of force constant \[k\] is fixed to a vertical wall and the other to a block of mass \[m\] resting on a smooth horizontal surface. There is another wall at a distance \[{{x}_{0}}\] from the block. The spring is then compressed by \[2{{x}_{0}}\] and released. The time taken to strike the wall is |
| A. | \[\frac{1}{6}\pi \sqrt{\frac{k}{m}}\] |
| B. | \[\sqrt{\frac{k}{m}}\] |
| C. | \[\frac{2\pi }{3}\sqrt{\frac{k}{m}}\] |
| D. | \[\frac{\pi }{4}\sqrt{\frac{k}{m}}\] |
| Answer» D. \[\frac{\pi }{4}\sqrt{\frac{k}{m}}\] | |
| 11497. |
Initially cylindrical drums \[P\] and \[Q\] were placed at equal distance \[L\] from center of mass \[C\] of the rough rod \[AB\] in horizontal position. The drums were spinning in opposite directions with angular velocities. The rod is displaced by distance \[x\] towards left and released so that it performs SHM. If difference in reactions at \[Q\] and \[P\] is \[\frac{mgx}{L}\] where m is the mass of the rod, find the time period of oscillations, if m is the coefficient of friction: |
| A. | \[2\pi \sqrt{\frac{L}{g}}\] |
| B. | \[2\pi \sqrt{\frac{(L-x)}{g}}\] |
| C. | \[2\pi \sqrt{\frac{(L+x)}{\mu g}}\] |
| D. | \[2\pi \sqrt{\frac{L}{\mu g}}\] |
| Answer» E. | |
| 11498. |
Assertion : Resonance is special case of forced vibration in which the natural frequency of vibration of the body is the same as the impressed frequency of external periodic force and the amplitude of forced vibration is maximum. Reason : The amplitude of forced vibrations of a body increases with an increase in the frequency of the externally impressed periodic force. [AIIMS 1994] |
| A. | If both assertion and reason are true and the reason is the correct explanation of the assertion. |
| B. | If both assertion and reason are true but reason is not the correct explanation of the assertion. |
| C. | If assertion is true but reason is false. |
| D. | If the assertion and reason both are false. |
| Answer» D. If the assertion and reason both are false. | |
| 11499. |
Assertion : When a simple pendulum is made to oscillate on the surface of moon, its time period increases. Reason : Moon is much smaller as compared to earth. |
| A. | If both assertion and reason are true and the reason is the correct explanation of the assertion. |
| B. | If both assertion and reason are true but reason is not the correct explanation of the assertion. |
| C. | If assertion is true but reason is false. |
| D. | If the assertion and reason both are false. |
| Answer» C. If assertion is true but reason is false. | |
| 11500. |
A simple pendulum of length L and mass (bob) M is oscillating in a plane about a vertical line between angular limits \[-\varphi \] and\[+\varphi \]. For an angular displacement\[\theta (|\theta | |
| A. | \[T\cos \theta =Mg\] |
| B. | \[T-Mg\cos \theta =\frac{M{{v}^{2}}}{L}\] |
| C. | The magnitude of the tangential acceleration of the bob \[|{{a}_{T}}|\,=g\sin \theta \] |
| D. | \[T=Mg\cos \theta \] |
| Answer» C. The magnitude of the tangential acceleration of the bob \[|{{a}_{T}}|\,=g\sin \theta \] | |