1.

The time period of a simple pendulum of length L as measured in an elevator descending with acceleration \[\frac{g}{3}\] is [CPMT 2000]

A. \[2\pi \sqrt{\frac{3L}{g}}\]
B. \[\pi \sqrt{\left( \frac{3L}{g} \right)}\]
C. \[2\pi \sqrt{\left( \frac{3L}{2g} \right)}\]
D. \[2\pi \sqrt{\frac{2L}{3g}}\]
Answer» D. \[2\pi \sqrt{\frac{2L}{3g}}\]


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