MCQOPTIONS
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| 1. |
The time period of a simple pendulum of length L as measured in an elevator descending with acceleration \[\frac{g}{3}\] is [CPMT 2000] |
| A. | \[2\pi \sqrt{\frac{3L}{g}}\] |
| B. | \[\pi \sqrt{\left( \frac{3L}{g} \right)}\] |
| C. | \[2\pi \sqrt{\left( \frac{3L}{2g} \right)}\] |
| D. | \[2\pi \sqrt{\frac{2L}{3g}}\] |
| Answer» D. \[2\pi \sqrt{\frac{2L}{3g}}\] | |