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MCQOPTIONS
This section includes 12583 Mcqs, each offering curated multiple-choice questions to sharpen your Joint Entrance Exam - Main (JEE Main) knowledge and support exam preparation. Choose a topic below to get started.
| 7701. |
Due to Doppler's effect, the shift in wavelength observed is 0.1 Å for a star producing wavelength 6000 Å. Velocity of recession of the star will be |
| A. | 2.5 km/s |
| B. | 10 km/s |
| C. | 5 km/s |
| D. | 20 km/s |
| Answer» D. 20 km/s | |
| 7702. |
A star is moving towards the earth with a speed of \[4.5\times {{10}^{6}}\]m/s. If the true wavelength of a certain line in the spectrum received from the star is\[5890\,\,{AA}\], its apparent wavelength will be about \[[c=3\times {{10}^{8}}m/s]\] [MP PMT 1999] |
| A. | \[5890\,\,{AA}\] |
| B. | \[5978\,\,{AA}\] |
| C. | \[5802\,\,{AA}\] |
| D. | \[5896\,\,{AA}\] |
| Answer» D. \[5896\,\,{AA}\] | |
| 7703. |
A star is going away from the earth. An observer on the earth will see the wavelength of light coming from the star [MP PMT 1999] |
| A. | Decreased |
| B. | Increased |
| C. | Neither decreased nor increased |
| D. | Decreased or increased depending upon the velocity of the star |
| Answer» C. Neither decreased nor increased | |
| 7704. |
The wavelength of light observed on the earth, from a moving star is found to decrease by 0.05%. Relative to the earth the star is [MP PMT/PET 1998] |
| A. | Moving away with a velocity of \[1.5\times {{10}^{5}}m/s\] |
| B. | Coming closer with a velocity of \[1.5\times {{10}^{5}}m/s\] |
| C. | Moving away with a velocity of \[1.5\times {{10}^{4}}m/s\] |
| D. | Coming closer with a velocity of \[1.5\times {{10}^{4}}m/s\] |
| Answer» C. Moving away with a velocity of \[1.5\times {{10}^{4}}m/s\] | |
| 7705. |
In the spectrum of light of a luminous heavenly body the wavelength of a spectral line is measured to be 4747 Å while actual wavelength of the line is 4700 Å. The relative velocity of the heavenly body with respect to earth will be (velocity of light is \[3\times {{10}^{8}}m/s\]) [MP PMT/PET 1998] |
| A. | \[3\times {{10}^{5}}m/s\]moving towards the earth |
| B. | \[3\times {{10}^{5}}m/s\]moving away from the earth |
| C. | \[3\times {{10}^{6}}m/s\]moving towards the earth |
| D. | \[3\times {{10}^{6}}m/s\]moving away from the earth |
| Answer» E. | |
| 7706. |
A star moves away from earth at speed 0.8 c while emitting light of frequency\[6\times {{10}^{14}}Hz\]. What frequency will be observed on the earth (in units of 1014 Hz) (c = speed of light) [MP PMT 1995] |
| A. | 0.24 |
| B. | 1.2 |
| C. | 30 |
| D. | 3.3 |
| Answer» C. 30 | |
| 7707. |
A star emitting light of wavelength\[5896\,\,{AA}\]is moving away from the earth with a speed of 3600 km / sec. The wavelength of light observed on earth will [MP PET 1995, 2002] |
| A. | Decrease by\[5825.25\,\,{AA}\] |
| B. | Increase by\[5966.75\,\,{AA}\] |
| C. | Decrease by\[70.75\,\,{AA}\] |
| D. | Increase by \[70.75\,\,{AA}\] (\[c=3\times {{10}^{8}}m/\sec \]is the speed of light) |
| Answer» E. | |
| 7708. |
A star emitting radiation at a wavelength of \[5000\,{AA}\] is approaching earth with a velocity of\[1.5\times {{10}^{6}}m/s\]. The change in wavelength of the radiation as received on the earth, is [CBSE PMT 1995] |
| A. | \[25\,\,{AA}\] |
| B. | Zero |
| C. | \[100\,\,{AA}\] |
| D. | \[2.5\,\,{AA}\] |
| Answer» B. Zero | |
| 7709. |
If a source of light is moving away from a stationary observer, then the frequency of light wave appears to change because of [AFMC 1995] |
| A. | Doppler's effect |
| B. | Interference |
| C. | Diffraction |
| D. | None of these |
| Answer» B. Interference | |
| 7710. |
A star is moving away from the earth with a velocity of 100 km/s. If the velocity of light is \[3\times {{10}^{8}}m/s\] then the shift of its spectral line of wavelength\[5700\,\,{AA}\]due to Doppler's effect will be [MP PMT 1994] |
| A. | \[0.63\,\,{AA}\] |
| B. | \[1.90\,\,{AA}\] |
| C. | \[3.80\,\,{AA}\] |
| D. | \[5.70\,\,{AA}\] |
| Answer» C. \[3.80\,\,{AA}\] | |
| 7711. |
The sun is rotating about its own axis. The spectral lines emitted from the two ends of its equator, for an observer on the earth, will show [MP PMT 1994] |
| A. | Shift towards red end |
| B. | Shift towards violet end |
| C. | Shift towards red end by one line and towards violet end by other |
| D. | No shift |
| Answer» D. No shift | |
| 7712. |
In the context of Doppler effect in light, the term ?red shift? signifies [MP PET 1994] |
| A. | Decrease in frequency |
| B. | Increase in frequency |
| C. | Decrease in intensity |
| D. | Increase in intensity |
| Answer» B. Increase in frequency | |
| 7713. |
The velocity of light emitted by a source S observed by an observer O, who is at rest with respect to S is c. If the observer moves towards S with velocity v, the velocity of light as observed will be [NCERT 1980] |
| A. | c + v |
| B. | \[c-v\] |
| C. | c |
| D. | \[\sqrt{1-\frac{{{v}^{2}}}{{{c}^{2}}}}\] |
| Answer» D. \[\sqrt{1-\frac{{{v}^{2}}}{{{c}^{2}}}}\] | |
| 7714. |
A star emits light of\[5500\,\,{AA}\]wavelength. Its appears blue to an observer on the earth, it means [DPMT 2002] |
| A. | Star is going away from the earth |
| B. | Star is stationary |
| C. | Star is coming towards earth |
| D. | None of the above |
| Answer» D. None of the above | |
| 7715. |
The observed wavelength of light coming from a distant galaxy is found to be increased by 0.5% as compared with that coming from a terrestrial source. The galaxy is [MP PMT 1993, 2003] |
| A. | Stationary with respect to the earth |
| B. | Approaching the earth with velocity of light |
| C. | Receding from the earth with the velocity of light |
| D. | Receding from the earth with a velocity equal to \[1.5\times {{10}^{6}}m/s\] |
| Answer» E. | |
| 7716. |
A wheel of radius 1 meter rolls forward half a revolution on a horizontal ground. The magnitude of the displacement of the point of the wheel initially in contact with the ground is [BCECE 2005] |
| A. | \[2\pi \] |
| B. | \[\sqrt{2}\pi \] |
| C. | \[\sqrt{{{\pi }^{2}}+4}\] |
| D. | \[\pi \] |
| Answer» D. \[\pi \] | |
| 7717. |
A person moves 30 m north and then 20 m towards east and finally \[30\sqrt{2}\] m in south-west direction. The displacement of the person from the origin will be [J & K CET 2004] |
| A. | 10 m along north |
| B. | 10 m long south |
| C. | 10 m along west |
| D. | Zero |
| Answer» D. Zero | |
| 7718. |
An aeroplane flies 400 m north and 300 m south and then flies 1200 m upwards then net displacement is [AFMC 2004] |
| A. | 1200 m |
| B. | 1300 m |
| C. | 1400 m |
| D. | 1500 m |
| Answer» B. 1300 m | |
| 7719. |
A Body moves 6 m north. 8 m east and 10m vertically upwards, what is its resultant displacement from initial position [DCE 2000] |
| A. | \[10\sqrt{2}m\] |
| B. | \[10m\] |
| C. | \[\frac{10}{\sqrt{2}}m\] |
| D. | \[10\times 2m\] |
| Answer» B. \[10m\] | |
| 7720. |
Which of the following expressions represent simple harmonic motion [Roorkee 1999] |
| A. | \[x=A\sin (\omega \,t+\delta )\] |
| B. | \[x=B\cos (\omega \,t+\varphi )\] |
| C. | \[x=A\tan (\omega \,t+\varphi )\] |
| D. | \[x=A\sin \omega \,t\cos \omega \,t\] |
| Answer» B. \[x=B\cos (\omega \,t+\varphi )\] | |
| 7721. |
A simple harmonic oscillator has an amplitude a and time period T. The time required by it to travel from x = a to x = a / 2 is [CBSE PMT 1992; SCRA 1996; BHU 1997] |
| A. | T / 6 |
| B. | T / 4 |
| C. | T / 3 |
| D. | T / 2 |
| Answer» B. T / 4 | |
| 7722. |
A particle is oscillating according to the equation\[X=7\cos 0.5\pi t\], where t is in second. The point moves from the position of equilibrium to maximum displacement in time [CPMT 1989] |
| A. | 4.0 sec |
| B. | 2.0 sec |
| C. | 1.0 sec |
| D. | 0.5 sec |
| Answer» D. 0.5 sec | |
| 7723. |
The equation of S.H.M. is \[y=a\sin (2\pi nt+\alpha )\], then its phase at time t is [DPMT 2001] |
| A. | \[2\pi nt\] |
| B. | \[\alpha \] |
| C. | \[2\pi nt+\alpha \] |
| D. | \[2\pi t\] |
| Answer» D. \[2\pi t\] | |
| 7724. |
The amplitude and the time period in a S.H.M. is 0.5 cm and 0.4 sec respectively. If the initial phase is \[\pi /2\] radian, then the equation of S.H.M. will be |
| A. | \[y=0.5\sin 5\pi t\] |
| B. | \[y=0.5\sin 4\pi t\] |
| C. | \[y=0.5\sin 2.5\pi t\] |
| D. | \[y=0.5\cos 5\pi t\] |
| Answer» E. | |
| 7725. |
Two equations of two S.H.M. are \[y=a\sin \,(\omega \,t-\alpha )\] and\[y=b\cos (\omega \,t-\alpha )\]. The phase difference between the two is [MP PMT 1985] |
| A. | 0° |
| B. | a° |
| C. | 90° |
| D. | 180° |
| Answer» D. 180° | |
| 7726. |
If \[x=a\sin \left( \omega t+\frac{\pi }{6} \right)\] and \[{x}'=a\cos \omega t\], then what is the phase difference between the two waves [RPET 1996] |
| A. | p / 3 |
| B. | p / 6 |
| C. | p / 2 |
| D. | p |
| Answer» B. p / 6 | |
| 7727. |
The amplitude and the periodic time of a S.H.M. are 5cm and 6sec respectively. At a distance of 2.5cm away from the mean position, the phase will be |
| A. | \[5\pi /12\] |
| B. | \[\pi /4\] |
| C. | \[\pi /3\] |
| D. | \[\pi /6\] |
| Answer» E. | |
| 7728. |
A system exhibiting S.H.M. must possess [KCET 1994] |
| A. | Inertia only |
| B. | Elasticity as well as inertia |
| C. | Elasticity, inertia and an external force |
| D. | Elasticity only |
| Answer» C. Elasticity, inertia and an external force | |
| 7729. |
The periodic time of a body executing simple harmonic motion is 3 sec. After how much interval from time t = 0, its displacement will be half of its amplitude [BHU 1998] |
| A. | \[\frac{1}{8}\]sec |
| B. | \[\frac{1}{6}\]sec |
| C. | \[\frac{1}{4}\]sec |
| D. | \[\frac{1}{3}\]sec |
| Answer» D. \[\frac{1}{3}\]sec | |
| 7730. |
Two particles are executing S.H.M. The equation of their motion are \[{{y}_{1}}=10\sin \left( \omega \,t+\frac{\pi T}{4} \right),\]\[{{y}_{2}}=25\sin \,\left( \omega \,t+\frac{\sqrt{3}\pi T}{4} \right)\]. What is the ratio of their amplitude [DCE 1996] |
| A. | 1 : 1 |
| B. | 2 : 5 |
| C. | 1 : 2 |
| D. | None of these |
| Answer» C. 1 : 2 | |
| 7731. |
Two simple harmonic motions are represented by the equations \[{{y}_{1}}=0.1\sin \left( 100\pi t+\frac{\pi }{3} \right)\]and \[{{y}_{2}}=0.1\cos \pi t.\] The phase difference of the velocity of particle 1 with respect to the velocity of particle 2 is [AIEEE 2005] |
| A. | \[\frac{-\pi }{3}\] |
| B. | \[\frac{\pi }{6}\] |
| C. | \[\frac{-\pi }{6}\] |
| D. | \[\frac{\pi }{3}\] |
| Answer» D. \[\frac{\pi }{3}\] | |
| 7732. |
A particle is moving in a circle with uniform speed. Its motion is [CPMT 1978; CBSE PMT 2005] |
| A. | Periodic and simple harmonic |
| B. | Periodic but not simple harmonic |
| C. | A periodic |
| D. | None of the above |
| Answer» C. A periodic | |
| 7733. |
Which one of the following is a simple harmonic motion [CBSE PMT 1994] |
| A. | Wave moving through a string fixed at both ends |
| B. | Earth spinning about its own axis |
| C. | Ball bouncing between two rigid vertical walls |
| D. | Particle moving in a circle with uniform speed |
| Answer» B. Earth spinning about its own axis | |
| 7734. |
A particle starts S.H.M. from the mean position. Its amplitude is A and time period is T. At the time when its speed is half of the maximum speed, its displacement y is [Haryana CEE 1996; CBSE PMT 1996; MH CET 2002] |
| A. | \[\frac{A}{2}\] |
| B. | \[\frac{A}{\sqrt{2}}\] |
| C. | \[\frac{A\sqrt{3}}{2}\] |
| D. | \[\frac{2A}{\sqrt{3}}\] |
| Answer» D. \[\frac{2A}{\sqrt{3}}\] | |
| 7735. |
A particle executing S.H.M. of amplitude 4 cm and T = 4 sec. The time taken by it to move from positive extreme position to half the amplitude is [BHU 1995] |
| A. | 1 sec |
| B. | 1/3 sec |
| C. | 2/3 sec |
| D. | \[\sqrt{3/2}\]sec |
| Answer» D. \[\sqrt{3/2}\]sec | |
| 7736. |
A particle executes a simple harmonic motion of time period T. Find the time taken by the particle to go directly from its mean position to half the amplitude [UPSEAT 2002] |
| A. | T / 2 |
| B. | T / 4 |
| C. | T / 8 |
| D. | T / 12 |
| Answer» E. | |
| 7737. |
A particle executing simple harmonic motion along y-axis has its motion described by the equation \[y=A\sin (\omega \,t)+B\]. The amplitude of the simple harmonic motion is [Orissa JEE 2003] |
| A. | A |
| B. | B |
| C. | A + B |
| D. | \[\sqrt{A+B}\] |
| Answer» B. B | |
| 7738. |
A particle in S.H.M. is described by the displacement function \[x(t)=a\cos (\omega t+\theta )\]. If the initial \[(t=0)\] position of the particle is 1 cm and its initial velocity is \[\pi \,cm/s\]. The angular frequency of the particle is \[\pi \,rad/s\], then it?s amplitude is [AMU (Med.) 2002] |
| A. | 1 cm |
| B. | \[\sqrt{2}\,cm\] |
| C. | 2 cm |
| D. | 2.5 cm |
| Answer» C. 2 cm | |
| 7739. |
Which of the following equation does not represent a simple harmonic motion [Kerala (Med.) 2002] |
| A. | \[y=a\sin \omega \,t\] |
| B. | \[y=a\cos \omega \,t\] |
| C. | \[y=a\sin \omega \,t+b\cos \omega \,t\] |
| D. | \[y=a\tan \omega \,t\] |
| Answer» E. | |
| 7740. |
A simple harmonic motion is represented by \[F(t)=10\sin \,(20\,t+0.5)\]. The amplitude of the S.H.M. is [DPMT 1998; CBSE PMT 2000; MH CET 2001] |
| A. | a = 30 |
| B. | a = 20 |
| C. | a = 10 |
| D. | a = 5 |
| Answer» D. a = 5 | |
| 7741. |
A particle is moving with constant angular velocity along the circumference of a circle. Which of the following statements is true [AMU (Engg.) 1999] |
| A. | The particle so moving executes S.H.M. |
| B. | The projection of the particle on any one of the diameters executes S.H.M. |
| C. | The projection of the particle on any of the diameters executes S.H.M. |
| D. | None of the above |
| Answer» D. None of the above | |
| 7742. |
A particle is executing simple harmonic motion with a period of T seconds and amplitude a metre. The shortest time it takes to reach a point \[\frac{a}{\sqrt{2}}m\] from its mean position in seconds is [EAMCET (Med.) 2000] |
| A. | T |
| B. | T/4 |
| C. | T/8 |
| D. | T/16 |
| Answer» D. T/16 | |
| 7743. |
The phase (at a time t) of a particle in simple harmonic motion tells [AMU (Engg.) 1999] |
| A. | Only the position of the particle at time t |
| B. | Only the direction of motion of the particle at time t |
| C. | Both the position and direction of motion of the particle at time t |
| D. | Neither the position of the particle nor its direction of motion at time t |
| Answer» D. Neither the position of the particle nor its direction of motion at time t | |
| 7744. |
A \[1.00\times {{10}^{-20}}kg\] particle is vibrating with simple harmonic motion with a period of \[1.00\times {{10}^{-5}}sec\] and a maximum speed of \[1.00\times {{10}^{3}}m/s\]. The maximum displacement of the particle is [AMU (Med.) 1999] |
| A. | 1.59 mm |
| B. | 1.00 m |
| C. | 10 m |
| D. | None of these |
| Answer» B. 1.00 m | |
| 7745. |
The phase of a particle executing simple harmonic motion is \[\frac{\pi }{2}\] when it has [MP PET 1985] |
| A. | Maximum velocity |
| B. | Maximum acceleration |
| C. | Maximum energy |
| D. | Maximum displacement |
| Answer» E. | |
| 7746. |
The logic behind ?NOR? gate is that it gives [CPMT 1999, AFMC 1999] |
| A. | High output when both the inputs are low |
| B. | Low output when both the inputs are low |
| C. | High output when both the inputs are high |
| D. | None of these |
| Answer» B. Low output when both the inputs are low | |
| 7747. |
Boolean algebra is essentially based on [AIIMS 1999] |
| A. | Truth |
| B. | Logic |
| C. | Symbol |
| D. | Numbers |
| Answer» C. Symbol | |
| 7748. |
For the given combination of gates, if the logic states of inputs A, B, C are as follows A = B = C = 0 and A = B = 1, C = 0 then the logic states of output\[D\]are [AMU 1998] |
| A. | 0, 0 |
| B. | 0, 1 |
| C. | 1, 0 |
| D. | 1, 1 |
| Answer» E. | |
| 7749. |
The truth table shown in figure is for [Pb. CET 1998] A 0 0 1 1 B 0 1 0 1 Y 1 0 0 1 |
| A. | XOR |
| B. | AND |
| C. | XNOR |
| D. | OR |
| Answer» D. OR | |
| 7750. |
A truth table is given below. Which of the following has this type of truth table [CBSE PMT 1996; UPSEAT 2002] A 0 1 0 1 B 0 0 1 1 y 1 0 0 0 |
| A. | XOR gate |
| B. | NOR gate |
| C. | AND gate |
| D. | OR gate |
| Answer» C. AND gate | |