MCQOPTIONS
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| 1. |
Two simple harmonic motions are represented by the equations \[{{y}_{1}}=0.1\sin \left( 100\pi t+\frac{\pi }{3} \right)\]and \[{{y}_{2}}=0.1\cos \pi t.\] The phase difference of the velocity of particle 1 with respect to the velocity of particle 2 is [AIEEE 2005] |
| A. | \[\frac{-\pi }{3}\] |
| B. | \[\frac{\pi }{6}\] |
| C. | \[\frac{-\pi }{6}\] |
| D. | \[\frac{\pi }{3}\] |
| Answer» D. \[\frac{\pi }{3}\] | |