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MCQOPTIONS
This section includes 12583 Mcqs, each offering curated multiple-choice questions to sharpen your Joint Entrance Exam - Main (JEE Main) knowledge and support exam preparation. Choose a topic below to get started.
| 6151. |
Two wires of the same dimensions but resistivities \[{{\rho }_{1}}\text{ and }{{\rho }_{2}}\] are connected in series. The equivalent resistivity of the combination is [KCET 2003] |
| A. | \[{{\rho }_{1}}+{{\rho }_{2}}\] |
| B. | \[\frac{{{\rho }_{1}}+{{\rho }_{2}}}{2}\] |
| C. | \[\sqrt{{{\rho }_{1}}{{\rho }_{2}}}\] |
| D. | \[2({{\rho }_{1}}+{{\rho }_{2}})\] |
| Answer» C. \[\sqrt{{{\rho }_{1}}{{\rho }_{2}}}\] | |
| 6152. |
Three resistors each of 2 ohm are connected together in a triangular shape. The resistance between any two vertices will be [CPMT 1983; MP PET 1990; MP PMT 1993; DCE 2004] |
| A. | 4/3 ohm |
| B. | 3/4 ohm |
| C. | 3 ohm |
| D. | 6 ohm |
| Answer» B. 3/4 ohm | |
| 6153. |
. The equivalent resistance between the points P and Q of the circuit given is [Pb. PMT 2002] |
| A. | \[\frac{R}{4}\] |
| B. | \[\frac{R}{3}\] |
| C. | 4 R |
| D. | 2 R |
| Answer» C. 4 R | |
| 6154. |
The equivalent resistance between x and y in the circuit shown is [MP PMT 2002] |
| A. | 10 W |
| B. | 40 W |
| C. | 20 W |
| D. | \[\frac{5}{2}\,\,\Omega \] |
| Answer» B. 40 W | |
| 6155. |
Find the equivalent resistance across AB [Orissa JEE 2002] |
| A. | 1 W |
| B. | 2 W |
| C. | 3 W |
| D. | 4 W |
| Answer» B. 2 W | |
| 6156. |
Three resistors are connected to form the sides of a triangle ABC, the resistance of the sides AB, BC and CA are 40 ohms, 60 ohms and 100 ohms respectively. The effective resistance between the points A and B in ohms will be [JIPMER 2002] |
| A. | 32 |
| B. | 64 |
| C. | 50 |
| D. | 200 |
| Answer» B. 64 | |
| 6157. |
In the circuit, the potential difference across PQ will be nearest to [Kerala PET 2002] |
| A. | 9.6 V |
| B. | 6.6 V |
| C. | 4.8 V |
| D. | 3.2 V |
| Answer» E. | |
| 6158. |
Two resistance wires on joining in parallel the resultant resistance is \[\frac{6}{5}\,\,ohms\]. One of the wire breaks, the effective resistance is 2 ohms. The resistance of the broken wire is [MP PET 2001, 2002] |
| A. | \[\frac{3}{5}\,\,ohm\] |
| B. | 2 ohm |
| C. | \[\frac{6}{5}\,\,ohm\] |
| D. | 3 ohm |
| Answer» E. | |
| 6159. |
The effective resistance of two resistors in parallel is \[\frac{12}{7}\,\,\Omega \]. If one of the resistors is disconnected the resistance becomes 4 W. The resistance of the other resistor is [MH CET 2002] |
| A. | 4 W |
| B. | 3 W |
| C. | \[\frac{12}{7}\,\,\Omega \] |
| D. | \[\frac{7}{12}\Omega \] |
| Answer» C. \[\frac{12}{7}\,\,\Omega \] | |
| 6160. |
Effective resistance between A and B is [UPSEAT 2001] |
| A. | 15 W |
| B. | 5 W |
| C. | \[\frac{5}{2}\Omega \] |
| D. | 20 W |
| Answer» C. \[\frac{5}{2}\Omega \] | |
| 6161. |
The resistors of resistances 2 W, 4 W and 8 W are connected in parallel, then the equivalent resistance of the combination will be [KCET 2001] |
| A. | \[\frac{8}{7}\Omega \] |
| B. | \[\frac{7}{8}\Omega \] |
| C. | \[\frac{7}{4}\Omega \] |
| D. | \[\frac{4}{9}\Omega \] |
| Answer» B. \[\frac{7}{8}\Omega \] | |
| 6162. |
A uniform wire of resistance 9 W is cut into 3 equal parts. They are connected in the form of equilateral triangle ABC. A cell of e.m.f. 2 V and negligible internal resistance is connected across B and C. Potential difference across AB is [Kerala (Engg.) 2001] |
| A. | 1 V |
| B. | 2 V |
| C. | 3 V |
| D. | 0.5 V |
| Answer» B. 2 V | |
| 6163. |
The reading of the ammeter as per figure shown is |
| A. | \[\frac{1}{8}A\] |
| B. | \[\frac{3}{4}A\] |
| C. | \[\frac{1}{2}A\] |
| D. | 2 A |
| Answer» C. \[\frac{1}{2}A\] | |
| 6164. |
In the circuit shown here, what is the value of the unknown resistor R so that the total resistance of the circuit between points P and Q is also equal to R [MP PET 2001] |
| A. | 3 ohms |
| B. | \[\sqrt{39}\,ohms\] |
| C. | \[\sqrt{69}\,ohms\] |
| D. | 10 ohms |
| Answer» D. 10 ohms | |
| 6165. |
Two wires of the same material and equal length are joined in parallel combination. If one of them has half the thickness of the other and the thinner wire has a resistance of 8 ohms, the resistance of the combination is equal to [AMU (Engg.) 2000] |
| A. | \[\frac{5}{8}\,\,ohms\] |
| B. | \[\frac{8}{5}\,\,ohms\] |
| C. | \[\frac{3}{8}\,\,ohms\] |
| D. | \[\frac{8}{3}\,\,ohms\] |
| Answer» C. \[\frac{3}{8}\,\,ohms\] | |
| 6166. |
Four resistances of 100 W each are connected in the form of square. Then, the effective resistance along the diagonal points is [MH CET 2000] |
| A. | 200 W |
| B. | 400 W |
| C. | 100 W |
| D. | 150 W |
| Answer» D. 150 W | |
| 6167. |
Two wires of equal diameters, of resistivities \[{{\rho }_{1}}\]and \[{{\rho }_{2}}\] and lengths l1 and l2, respectively, are joined in series. The equivalent resistivity of the combination is [EAMCET (Engg.) 2000] |
| A. | \[\frac{{{\rho }_{1}}{{l}_{1}}+{{\rho }_{2}}{{l}_{2}}}{{{l}_{1}}+{{l}_{2}}}\] |
| B. | \[\frac{{{\rho }_{1}}{{l}_{2}}+{{\rho }_{2}}{{l}_{1}}}{{{l}_{1}}-{{l}_{2}}}\] |
| C. | \[\frac{{{\rho }_{1}}{{l}_{2}}+{{\rho }_{2}}{{l}_{1}}}{{{l}_{1}}+{{l}_{2}}}\] |
| D. | \[\frac{{{\rho }_{1}}{{l}_{1}}-{{\rho }_{2}}{{l}_{2}}}{{{l}_{1}}-{{l}_{2}}}\] |
| Answer» B. \[\frac{{{\rho }_{1}}{{l}_{2}}+{{\rho }_{2}}{{l}_{1}}}{{{l}_{1}}-{{l}_{2}}}\] | |
| 6168. |
Four resistances 10 W, 5 W, 7 W and 3 W are connected so that they form the sides of a rectangle AB, BC, CD and DA respectively. Another resistance of 10 W is connected across the diagonal AC. The equivalent resistance between A and B is [EAMCET (Med.) 2000] |
| A. | 2 W |
| B. | 5 W |
| C. | 7 W |
| D. | 10 W |
| Answer» C. 7 W | |
| 6169. |
If each resistance in the figure is of 9 W then reading of ammeter is [RPMT 2000] |
| A. | 5 A |
| B. | 8 A |
| C. | 2 A |
| D. | 9 A |
| Answer» B. 8 A | |
| 6170. |
In the given figure, potential difference between A and B is [RPMT 2000] |
| A. | 0 |
| B. | 5 volt |
| C. | 10 volt |
| D. | 15 volt |
| Answer» D. 15 volt | |
| 6171. |
The potential drop across the 3W resistor is [CPMT 2000] |
| A. | 1 V |
| B. | 1.5 V |
| C. | 2 V |
| D. | 3 V |
| Answer» B. 1.5 V | |
| 6172. |
A battery of emf 10 V and internal resistance \[3\,\Omega \] is connected to a resistor as shown in the figure. If the current in the circuit is 0.5 A. then the resistance of the resistor will be [MH CET 2000; Pb. PMT 2000] |
| A. | 19 W |
| B. | 17 W |
| C. | 10 W |
| D. | 12 W |
| Answer» C. 10 W | |
| 6173. |
The lowest resistance which can be obtained by connecting 10 resistors each of 1/10 ohm is [MP PMT 1984; EAMCET 1994] |
| A. | \[1/250\,\Omega \] |
| B. | \[1/200\,\Omega \] |
| C. | \[1/100\,\Omega \] |
| D. | \[1/10\,\Omega \] |
| Answer» D. \[1/10\,\Omega \] | |
| 6174. |
If all the resistors shown have the value 2 ohm each, the equivalent resistance over AB is [JIPMER 1999] |
| A. | 2 ohm |
| B. | 4 ohm |
| C. | \[1\frac{2}{3}\,\,ohm\] |
| D. | \[2\frac{2}{3}\,\,ohm\] |
| Answer» E. | |
| 6175. |
An infinite ladder network is arranged with resistances R and 2 R as shown. The effective resistance between terminals A and B is [AMU (Med.) 1999] |
| A. | ¥ |
| B. | R |
| C. | 2 R |
| D. | 3 R |
| Answer» D. 3 R | |
| 6176. |
In the given figure, the equivalent resistance between the points A and B is [AIIMS 1999] |
| A. | 8 W |
| B. | 6 W |
| C. | 4 W |
| D. | 2 W |
| Answer» C. 4 W | |
| 6177. |
The equivalent resistance of the circuit shown in the figure is [CPMT 1999] |
| A. | 8 W |
| B. | 6 W |
| C. | 5 W |
| D. | 4 W |
| Answer» D. 4 W | |
| 6178. |
10 wires (same length, same area, same material) are connected in parallel and each has 1W resistance, then the equivalent resistance will be [RPMT 1999] |
| A. | 10 W |
| B. | 1 W |
| C. | 0.1 W |
| D. | 0.001 W |
| Answer» D. 0.001 W | |
| 6179. |
The current in the following circuit is [CBSE PMT 1997] |
| A. | \[\frac{1}{8}A\] |
| B. | \[\frac{2}{9}A\] |
| C. | \[\frac{2}{3}A\] |
| D. | \[1A\] |
| Answer» E. | |
| 6180. |
What is the equivalent resistance between A and B [BHU 1997; MP PET 2001] |
| A. | \[\frac{2}{3}R\] |
| B. | \[\frac{3}{2}R\] |
| C. | \[\frac{R}{2}\] |
| D. | \[2R\] |
| Answer» D. \[2R\] | |
| 6181. |
What is the equivalent resistance between A and B in the figure below if \[R=3\,\Omega \] [SCRA 1996] |
| A. | \[9\,\Omega \] |
| B. | \[12\,\Omega \] |
| C. | \[15\,\Omega \] |
| D. | None of these |
| Answer» E. | |
| 6182. |
What will be the equivalent resistance between the two points A and D [CBSE PMT 1996] |
| A. | \[10\,\Omega \] |
| B. | \[20\,\Omega \] |
| C. | \[30\,\Omega \] |
| D. | \[40\,\Omega \] |
| Answer» D. \[40\,\Omega \] | |
| 6183. |
Three resistances of one ohm each are connected in parallel. Such connection is again connected with \[2/3\,\Omega \] resistor in series. The resultant resistance will be [MP PMT 1985] |
| A. | \[\frac{5}{3}\Omega \] |
| B. | \[\frac{3}{2}\Omega \] |
| C. | \[1\,\Omega \] |
| D. | \[\frac{2}{3}\Omega \] |
| Answer» D. \[\frac{2}{3}\Omega \] | |
| 6184. |
Three resistances \[4\,\Omega \] each of are connected in the form of an equilateral triangle. The effective resistance between two corners is [CBSE PMT 1993] |
| A. | \[8\,\Omega \] |
| B. | \[12\,\Omega \] |
| C. | \[\frac{3}{8}\Omega \] |
| D. | \[\frac{8}{3}\Omega \] |
| Answer» E. | |
| 6185. |
In the figure, current through the \[3\,\Omega \] resistor is 0.8 ampere, then potential drop through \[4\,\Omega \] resistor is [CBSE PMT 1993; AFMC 1999; MP PMT 2004] |
| A. | 9.6 V |
| B. | 2.6 V |
| C. | 4.8 V |
| D. | 1.2 V |
| Answer» D. 1.2 V | |
| 6186. |
For what value of R the net resistance of the circuit will be 18 ohms [RPET 1997] |
| A. | \[8\,\Omega \] |
| B. | \[10\,\Omega \] |
| C. | \[16\,\Omega \] |
| D. | \[24\,\Omega \] |
| Answer» D. \[24\,\Omega \] | |
| 6187. |
A uniform wire of \[16\,\Omega \] is made into the form of a square. Two opposite corners of the square are connected by a wire of resistance \[16\,\Omega \]. The effective resistance between the other two opposite corners is [EAMCET (Med.) 1995] |
| A. | \[32\,\Omega \] |
| B. | \[20\,\Omega \] |
| C. | \[8\,\Omega \] |
| D. | \[4\,\Omega \] |
| Answer» E. | |
| 6188. |
n equal resistors are first connected in series and then connected in parallel. What is the ratio of the maximum to the minimum resistance [KCET 1994] |
| A. | n |
| B. | \[\frac{1}{{{n}^{2}}}\] |
| C. | \[{{n}^{2}}\] |
| D. | \[\frac{1}{n}\] |
| Answer» D. \[\frac{1}{n}\] | |
| 6189. |
What is the current (i) in the circuit as shown in figure [AIIMS 1998] |
| A. | 2 A |
| B. | 1.2 A |
| C. | 1 A |
| D. | 0.5 A |
| Answer» B. 1.2 A | |
| 6190. |
The current in the given circuit is [CBSE PMT 1999] |
| A. | 8.31 A |
| B. | 6.82 A |
| C. | 4.92 A |
| D. | 2 A |
| Answer» E. | |
| 6191. |
The resistance between the terminal points A and B of the given infinitely long circuit will be [MP PMT/PET 1998] |
| A. | \[(\sqrt{3}-1)\] |
| B. | \[(1-\sqrt{3})\] |
| C. | \[(1+\sqrt{3})\] |
| D. | \[(2+\sqrt{3})\] |
| Answer» D. \[(2+\sqrt{3})\] | |
| 6192. |
A wire of resistance R is cut into ?n? equal parts. These parts are then connected in parallel. The equivalent resistance of the combination will be [MP PMT/PET 1998; BHU 2005] |
| A. | nR |
| B. | \[\frac{R}{n}\] |
| C. | \[\frac{n}{R}\] |
| D. | \[\frac{R}{{{n}^{2}}}\] |
| Answer» E. | |
| 6193. |
In the circuit shown below, the cell has an e.m.f. of 10 V and internal resistance of 1 ohm. The other resistances are shown in the figure. The potential difference \[{{V}_{A}}-{{V}_{B}}\] is [MP PMT 1997] |
| A. | 6 V |
| B. | 4 V |
| C. | 2 V |
| D. | \[-2\,V\] |
| Answer» E. | |
| 6194. |
There are 8 equal resistances R. Two are connected in parallel, such four groups are connected in series, the total resistance of the system will be [MP PMT 1987] |
| A. | R / 2 |
| B. | 2 R |
| C. | 4 R |
| D. | 8 R |
| Answer» C. 4 R | |
| 6195. |
Three resistors each of \[4\,\Omega \] are connected together to form a network. The equivalent resistance of the network cannot be |
| A. | \[1.33\,\Omega \] |
| B. | \[3.0\,\Omega \] |
| C. | \[6.0\,\Omega \] |
| D. | \[12.0\,\Omega \] |
| Answer» C. \[6.0\,\Omega \] | |
| 6196. |
In the circuit shown, the point ?B? is earthed. The potential at the point ?A? is |
| A. | 14 V |
| B. | 24 V |
| C. | 26 V |
| D. | 50 V |
| Answer» C. 26 V | |
| 6197. |
A wire has resistance \[12\,\Omega \]. It is bent in the form of a circle. The effective resistance between the two points on any diameter is equal to [JIPMER 1999] |
| A. | \[12\,\Omega \] |
| B. | \[6\,\Omega \] |
| C. | \[3\,\Omega \] |
| D. | \[24\,\Omega \] |
| Answer» D. \[24\,\Omega \] | |
| 6198. |
A copper wire of resistance R is cut into ten parts of equal length. Two pieces each are joined in series and then five such combinations are joined in parallel. The new combination will have a resistance [MP PET 1996] |
| A. | R |
| B. | \[\frac{R}{4}\] |
| C. | \[\frac{R}{5}\] |
| D. | \[\frac{R}{25}\] |
| Answer» E. | |
| 6199. |
The equivalent resistance between points A and B of an infinite network of resistances each of \[1\,\Omega \] connected as shown, is [Haryana CEE 1996] |
| A. | Infinite |
| B. | \[2\,\Omega \] |
| C. | \[\frac{1+\sqrt{5}}{2}\Omega \] |
| D. | Zero |
| Answer» D. Zero | |
| 6200. |
Three equal resistances each of value R are joined as shown in the figure. The equivalent resistance between M and N is [MP PET 1995] |
| A. | R |
| B. | 2R |
| C. | \[\frac{R}{2}\] |
| D. | \[\frac{R}{3}\] |
| Answer» E. | |