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This section includes 194 Mcqs, each offering curated multiple-choice questions to sharpen your Electronics knowledge and support exam preparation. Choose a topic below to get started.
51. |
Open-loop gain of an op-amp is the voltage gain without feedback. |
A. | True |
B. | False |
Answer» B. False | |
52. |
All practical op-amps have input bias currents and voltages that produce output error voltages. |
A. | True |
B. | False |
Answer» B. False | |
53. |
A non-inverting amplifier has a higher input impedance and a lower output impedance than the op-amp itself (without feedback). |
A. | True |
B. | False |
Answer» B. False | |
54. |
An inverting amplifier has an input impedance equal to the feedback resistor Rf. |
A. | True |
B. | False |
Answer» C. | |
55. |
The common-mode rejection ratio (CMRR) is a measure of an op-amp's ability to reject common-mode input signals. |
A. | True |
B. | False |
Answer» B. False | |
56. |
A good op-amp has low voltage gain, low output impedance, and high input impedance. |
A. | True |
B. | False |
Answer» C. | |
57. |
A(n) ________ amplifier configuration has an input impedance approximately equal to the input resistor Ri and an output impedance approximately equal to the output impedance of the op-amp itself. |
A. | non-inverting |
B. | inverting |
C. | voltage-follower |
Answer» C. voltage-follower | |
58. |
The input offset voltage drift is a parameter directly related to VOS and ________. |
A. | ID |
B. | power dissipation |
C. | temperature |
D. | phase shift |
Answer» D. phase shift | |
59. |
Refer to the given figure. Calculate the bandwidth. |
A. | 8.33 MHz |
B. | 833 kHz |
C. | 83.3 kHz |
D. | 8.33 kHz |
Answer» D. 8.33 kHz | |
60. |
Refer to the given figure. The unity-gain bandwidth of this op-amp is 10.4 kHz. What is the bandwidth of the circuit? |
A. | 10.4 kHz |
B. | 15.5 kHz |
C. | 3 MHz |
D. | 16.7 kHz |
Answer» B. 15.5 kHz | |
61. |
Refer to the given figure. Determine the bandwidth. |
A. | 1 MHz |
B. | 1.5 MHz |
C. | 1 kHz |
D. | 1.5 kHz |
Answer» C. 1 kHz | |
62. |
Refer to the given figure. The op-amp has a unity-gain bandwidth of 1.7 MHz. Find the bandwidth of the circuit. |
A. | 155 MHz |
B. | 155 kHz |
C. | 155 Hz |
D. | 15.5 Hz |
Answer» C. 155 Hz | |
63. |
Refer to the given figure. The op-amp has a unity-gain bandwidth of 3 MHz. Determine the BW of the circuit. |
A. | 3 MHz |
B. | 30 kHz |
C. | 112.4 kHz |
D. | infinite in width |
Answer» D. infinite in width | |
64. |
Refer to the given figure. The midrange voltage gain of this amplifier is |
A. | 0.5. |
B. | 27.7. |
C. | –11. |
D. | 1 |
Answer» E. | |
65. |
Refer to the given figure. Find the midrange gain of this op-amp amplifier. |
A. | 10 |
B. | 11 |
C. | –10 |
D. | –11 |
Answer» C. –10 | |
66. |
Refer to the given figure. Find the midrange gain of this amplifier. |
A. | 26.7 |
B. | –26.7 |
C. | 27.7 |
D. | –27.7 |
Answer» C. 27.7 | |
67. |
An RC network has R = 500 k and C = 10 pF. Find the value of fc. |
A. | 31831 Hz |
B. | 31.831 kHz |
C. | 0.031831 MHz |
D. | all of the above |
E. | none of the above |
Answer» E. none of the above | |
68. |
A voltage-follower amplifier comes to you for service. You find the voltage gain to be 5.5 and the input impedance 22 k. The probable fault in this amplifier, if any, is |
A. | the gain is too low for this type of amplifier. |
B. | the input impedance is too high for this amplifier. |
C. | nothing is wrong. The trouble must be somewhere else. |
D. | none of these. |
Answer» E. | |
69. |
Refer to this figure. If the value of R1 decreases, the voltage gain will ________ and the input impedance will ________. |
A. | increase, increase |
B. | increase, decrease |
C. | decrease, decrease |
D. | decrease, increase |
Answer» C. decrease, decrease | |
70. |
Refer to this figure. The purpose of R3 is |
A. | for bias current compensation. |
B. | for input offset voltage compensation. |
C. | to set input impedance. |
D. | to set input impedance and voltage gain. |
Answer» B. for input offset voltage compensation. | |
71. |
Refer to this figure. The purpose of R4 is |
A. | for bias current compensation. |
B. | for input offset voltage compensation. |
C. | to set input impedance. |
D. | to set input impedance and voltage gain. |
Answer» C. to set input impedance. | |
72. |
Refer to this figure. The purpose of R1 and R2 is |
A. | for bias current compensation. |
B. | for input offset voltage compensation. |
C. | to set input impedance. |
D. | to set input impedance and voltage gain. |
Answer» E. | |
73. |
It takes an op-amp 22 s to change its output from –15 V to +15 V. Determine the slew rate. |
A. | 1.36 V/s |
B. | 0.68 V/s |
C. | –0.68 V/s |
D. | cannot determine |
Answer» B. 0.68 V/s | |
74. |
Refer to the given figure. A dc input signal of –50 mV is applied. You would measure ________ from the inverting input to ground. |
A. | 50 mV |
B. | 1.05 V |
C. | –1.05 V |
D. | –50 mV |
Answer» E. | |
75. |
Refer to the given figure. The input impedance of this circuit is |
A. | 500 k. |
B. | 10 k. |
C. | 50 k. |
D. | 5 k. |
Answer» D. 5 k. | |
76. |
Refer to the given figure. You need an amplifier with an input impedance of 12 k. You must not change the amplifier voltage gain. The new value of Ri would be ________ and the new value of Rf would be ________. |
A. | 10 k, 100 k |
B. | 13.3 k, 120 k |
C. | 12 k, 108 k |
D. | 12 k, 120 k |
Answer» E. | |
77. |
Refer to the given figure. If an input signal of –0.5 V were applied, determine the output voltage. |
A. | –5 V |
B. | 5 V |
C. | 10 V |
D. | –10 V |
Answer» C. 10 V | |
78. |
Refer to the given figure. The voltage gain of this amplifier is |
A. | 100 |
B. | 5 |
C. | 20 |
D. | 21 |
Answer» E. | |
79. |
Refer to the given figure. A dc voltage of –1.2 V is applied. VCC = ±12 V. What is the output voltage? |
A. | 1.2 V |
B. | –1.2 V |
C. | 0 V |
D. | 12 V |
Answer» C. 0 V | |
80. |
Refer to the given figure. This amplifier is known as |
A. | an inverting amplifier. |
B. | a non-inverting amplifier. |
C. | a voltage-follower. |
D. | a common-source amplifier. |
Answer» D. a common-source amplifier. | |
81. |
What is the use of the compensation capacitor in op-amp? |
A. | Improves the amplification of op-amp |
B. | Decreases the slew rate of op-amp |
C. | Increases the bandwidth of op-amp |
D. | Op-amp acts as all pass filter |
Answer» C. Increases the bandwidth of op-amp | |
82. |
Till what frequency do we get amplification from IC 741? |
A. | Unity gain bandwidth |
B. | 3-dB frequency |
C. | Infinity |
D. | UGB + fOL |
Answer» B. 3-dB frequency | |
83. |
Which of the following option is correct according to the below statements? |
A. | Both A and B are correct, and B is the correct reason for A |
B. | Both A and B are correct, but B is not the correct reason for A |
C. | A is correct and B is incorrect |
D. | A is incorrect and B is correctView Answer |
Answer» B. Both A and B are correct, but B is not the correct reason for A | |
84. |
The unity gain bandwidth for an op-amp having open loop gain 2×106 is 10 Mhz. Calculate the AC gain of op-amp at an input of 2000 Hz. |
A. | 2000 |
B. | 5000 |
C. | 10000 |
D. | 12.5 |
Answer» C. 10000 | |
85. |
Given that CMRR is 100dB. Input common-mode voltage is 12 V. Differential voltage gain is 4000. Calculate output common-mode voltage. |
A. | 48V |
B. | 0.48V |
C. | 20V |
D. | 11V |
Answer» C. 20V | |
86. |
Given that for an op-amp the gain is 103, the slew rate is 1.5V/μsec. Input is 5×10-3sinωt, calculate maximum frequency to prevent distortion. |
A. | 47.7 kHz |
B. | 0.3 MHz |
C. | 477 Hz |
D. | 3 kHz |
Answer» B. 0.3 MHz | |
87. |
A practical op-amp has a bandwidth of only 10 Hz. Gain is 106, and the required bandwidth is 100 kHz. How much feedback is required? |
A. | 0.99% negative feedback |
B. | 0.99% positive feedback |
C. | 1% negative feedback |
D. | 1% positive feedback |
Answer» B. 0.99% positive feedback | |
88. |
In an ideal op-amp, which is not true? |
A. | Open loop voltage gain is infinite |
B. | Input resistance is infinite |
C. | Slew rate is infinite |
D. | CMRR is zero |
Answer» E. | |
89. |
In the given block diagram of an op-amp. What are A, B, C and D? |
A. | A = Dual input and balanced output differential amplifier, B = Dual input and unbalanced output differential amplifier, C = Level shifter, D = Power amplifier |
B. | A = Dual input and balanced output differential amplifier, B = Dual input and balanced output differential amplifier, C = Dual input and unbalanced output differential amplifier, D = Normal amplifier |
C. | A = Dual input and unbalanced output differential amplifier, B = Dual input and balanced output differential amplifier, C = Voltage regulator, D = Power amplifier |
D. | A = Normal amplifier, B = Dual input and unbalanced output differential amplifier, C = Level shifter, D = Dual input and balanced output differential amplifier |
Answer» B. A = Dual input and balanced output differential amplifier, B = Dual input and balanced output differential amplifier, C = Dual input and unbalanced output differential amplifier, D = Normal amplifier | |
90. |
Which of these is incorrect for an operational amplifier? |
A. | It has a high voltage gain |
B. | It is a direct coupled amplifier |
C. | It is only useful for amplifying AC signals |
D. | It was originally designed to perform mathematical operations |
Answer» D. It was originally designed to perform mathematical operations | |
91. |
Current cannot flow to ground through a(n) ________. |
A. | mechanical ground |
B. | ac ground |
C. | virtual ground |
D. | virtual short |
Answer» D. virtual short | |
92. |
The voltage gain is ______ for the amplifier in the given circuit. |
A. | –4 |
B. | –5 |
C. | –6 |
D. | –7 |
Answer» D. ‚Äì7 | |
93. |
The TO-5 operational amplifier package can have 5 pins. |
A. | 1 |
B. | |
Answer» C. | |
94. |
If the two inputs to a differential amplifier are exactly the same, then the output is the signal multiplied by 2. |
A. | 1 |
B. | |
Answer» C. | |
95. |
An op-amp has very low open-loop gain. |
A. | 1 |
B. | |
Answer» C. | |
96. |
The Q of a crystal _________. |
A. | is extremely low |
B. | is about 40 or so in most cases |
C. | is extremely high |
D. | none of the above |
Answer» D. none of the above | |
97. |
A monostable multivibrator must be triggered. |
A. | 1 |
B. | |
Answer» B. | |
98. |
The difference between the upper and lower trigger points is called the Schmitt trigger. |
A. | 1 |
B. | |
Answer» C. | |
99. |
Changing the input voltage to an op-amp circuit will change its voltage gain. |
A. | 1 |
B. | |
Answer» C. | |
100. |
The inverting input is pin 2. |
A. | 1 |
B. | |
Answer» B. | |