MCQOPTIONS
Saved Bookmarks
MCQOPTIONS
This section includes 9 Mcqs, each offering curated multiple-choice questions to sharpen your Linear Integrated Circuit knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Calculate the value of reference current and input resistor for current mirror with IC=1.2 A & VCC=12v. Assume =50. |
| A. | 1.248mA, 9k |
| B. | 1.248mA, 9.6k |
| C. | 1.248mA, 9.2k |
| D. | 1.2mA, 9.6k |
| Answer» B. 1.248mA, 9.6k | |
| 2. |
When will be the mirror effect valid |
| A. | 1 |
| B. | =1 |
| C. | <1 |
| D. | 1 |
| Answer» B. =1 | |
| 3. |
Constant current source in differential amplifier is also called as |
| A. | Current Mirror |
| B. | Current Source |
| C. | Current Repeaters |
| D. | All of the mentioned |
| Answer» B. Current Source | |
| 4. |
Define total current (IQ) equation in differential amplifier with constant current bias current |
| A. | I<sub>Q</sub>=1/R<sub>3</sub> (VEE/R<sub>1</sub>+R<sub>2</sub>) |
| B. | I<sub>Q</sub> =(VEE R<sub>2</sub>)/(R<sub>1</sub>+R<sub>2</sub>) |
| C. | I<sub>Q</sub>=1/R<sub>3</sub> (VEE R<sub>2</sub>/R<sub>1</sub>+R<sub>2</sub>) |
| D. | I<sub>Q</sub>)=R<sub>3</sub> (VEE/R<sub>1</sub>+R<sub>2</sub>) |
| Answer» D. I<sub>Q</sub>)=R<sub>3</sub> (VEE/R<sub>1</sub>+R<sub>2</sub>) | |
| 5. |
How to improve CMRR value |
| A. | Increase common mode gain |
| B. | Decrease common mode gain |
| C. | Increase Differential mode gain |
| D. | Decrease differential mode gain |
| Answer» C. Increase Differential mode gain | |
| 6. |
In differential amplifier the input are given as V1=30sin (50t)+10sin (25t) , V2=30sin (50t)-10 sin (25t), 0 =200,RE =1k and RC = 15k . Find the output voltages V01, V02 & gm=4M -1 |
| A. | V<sub>01</sub>=-60[10 sin u2061 (25t) ]-6.637[30sin u2061 (50t) ], V<sub>02</sub>=60[10 sin u2061 (25t) ]-6.637[30sin u2061 (50t) ]. |
| B. | V<sub>01</sub>=-6.637[10 sin u2061 (25t) ]-60[30sin u2061 (50t) ], V<sub>02</sub>=6.637[10 sin u2061 (25t) ]-60[30sin u2061 (50t) ]. |
| C. | V<sub>01</sub>=-60[30 sin u2061 (50t) ]-6.637[10sin u2061 (25t) ], V<sub>02</sub>=60[30 sin u2061 (50t) ]-6.637[10sin u2061 (25t) ]. |
| D. | V<sub>01</sub>=-6.637[30 sin u2061 (50t) ]-60[10sin u2061 (25t) ], V<sub>02</sub>=6.637[30 sin u2061 (50t) ]-60[10sin u2061 (25t) ]. |
| Answer» B. V<sub>01</sub>=-6.637[10 sin u2061 (25t) ]-60[30sin u2061 (50t) ], V<sub>02</sub>=6.637[10 sin u2061 (25t) ]-60[30sin u2061 (50t) ]. | |
| 7. |
Find Common Mode Rejection Ration, given gm =16M -1, RE=25k |
| A. | 58 db |
| B. | 40 db |
| C. | 63 db |
| D. | 89 db |
| Answer» B. 40 db | |
| 8. |
How the differential mode gain is expressed using h parameter for a single ended output? |
| A. | h<sub>fe</sub>RC/h<sub>ie</sub> |
| B. | 1/2 (h<sub>fe</sub>RC)/h<sub>ie</sub> |
| C. | 1/2 h<sub>fe</sub>RC |
| D. | None of the mentioned |
| Answer» C. 1/2 h<sub>fe</sub>RC | |
| 9. |
How are the arbitrary signal represented, that are applied to the input of transistor? (Assume common mode signal and differential mode signal to be VCM & VDM respectively). |
| A. | Sum of V<sub>CM</sub> & V<sub>DM</sub> |
| B. | Difference of V<sub>CM</sub> & V<sub>DM</sub> |
| C. | Sum and Difference of V<sub>CM</sub> & V<sub>DM</sub> |
| D. | None of the mentioned |
| Answer» D. None of the mentioned | |