Explore topic-wise MCQs in Network Theory.

This section includes 16 Mcqs, each offering curated multiple-choice questions to sharpen your Network Theory knowledge and support exam preparation. Choose a topic below to get started.

1.

Find the Norton’s current in the circuit shown below.

A. 40∠30⁰
B. 40∠-30⁰
C. 30∠30⁰
D. 30∠-30⁰
Answer» D. 30∠-30⁰
Discussion
2.

Determine Norton’s equivalent impedance in the circuit shown below.

A. (5+j6) Ω
B. (5-j6) Ω
C. (6+j7) Ω
D. (6-j7) Ω
Answer» B. (5-j6) Ω
Discussion
3.

Find the load current in the circuit shown below.

A. 3.19∠166.61⁰
B. 3.19∠-166.61⁰
C. 4.19∠166.61⁰
D. 4.19∠-166.61⁰
Answer» C. 4.19∠166.61⁰
Discussion
4.

Find the Norton’s current passing through ‘ab’ in the circuit shown below.

A. 4.16∠126.8⁰
B. 5.16∠126.8⁰
C. 5.16∠-126.8⁰
D. 4.16∠-126.8⁰
Answer» E.
Discussion
5.

Determine the Norton’s impedance seen from terminals ‘ab’.

A. 6∠90⁰
B. 7∠90⁰
C. 6∠-90⁰
D. 7∠-90⁰
Answer» D. 7∠-90⁰
Discussion
6.

The Norton’s equivalent impedance in the circuit shown below.

A. 4.53∠9.92⁰
B. 4.53∠-9.92⁰
C. 5.53∠9.92⁰
D. 5.53∠-9.92⁰
Answer» B. 4.53∠-9.92⁰
Discussion
7.

Determine Norton’s equivalent current in the circuit shown below.

A. 5∠53.13⁰
B. 4∠53.13⁰
C. 4∠53.13⁰
D. 5∠-53.13⁰
Answer» E.
Discussion
8.

The expression of equivalent impedance (ZN) in the circuit shown below is?

A. (Z1+Z2)/Z1
B. (Z1+Z2)/Z2
C. Z1Z2/(Z1+Z2)
D. Z1+Z2
Answer» D. Z1+Z2
Discussion
9.

The expression of Norton’s current (IN) in the circuit shown below is?

A. V/Z1
B. V/Z2
C. V(Z2/(Z1+Z2))
D. VZ1/(Z1+Z2)
Answer» B. V/Z2
Discussion
10.

Norton’s current is equal to the current passing through the ___________ circuited ___________ terminals.

A. short, input
B. short, output
C. open, output
D. open, input
Answer» C. open, output
Discussion
11.

Find the Norton’s current in the circuit shown in the question 9.$#

A. 40∠30⁰
B. 40∠-30⁰
C. 30∠30⁰
D. 30∠-30⁰
Answer» D. 30‚Äö√Ñ√∂‚àö‚Ć‚Äö√тĆ-30‚Äö√Ñ√∂‚àö√ñ‚Äö√†√ª
Discussion
12.

Find the load current in the circuit shown in the question 6?

A. 3.19∠166.61⁰
B. 3.19∠-166.61⁰
C. 4.19∠166.61⁰
D. 4.19∠-166.61⁰
Answer» C. 4.19‚Äö√Ñ√∂‚àö‚Ć‚Äö√тĆ166.61‚Äö√Ñ√∂‚àö√ñ‚Äö√†√ª
Discussion
13.

Find the Norton’s current passing through ‘ab’ in the circuit shown in the question 6.$

A. 4.16∠126.8⁰
B. 5.16∠126.8⁰
C. 5.16∠-126.8⁰
D. 4.16∠-126.8⁰
Answer» E.
Discussion
14.

The Norton’s equivalent impedance in the circuit shown in the question 4.$

A. 4.53∠9.92⁰
B. 4.53∠-9.92⁰
C. 5.53∠9.92⁰
D. 5.53∠-9.92⁰
Answer» B. 4.53‚Äö√Ñ√∂‚àö‚Ć‚Äö√тĆ-9.92‚Äö√Ñ√∂‚àö√ñ‚Äö√†√ª
Discussion
15.

The expression of equivalent impedance (ZN) in the circuit shown in the question 2 is?

A. (Z<sub>1</sub>+Z<sub>2</sub>)/Z<sub>1</sub>
B. (Z<sub>1</sub>+Z<sub>2</sub>)/Z<sub>2</sub>
C. Z<sub>1</sub>Z<sub>2</sub>/(Z<sub>1</sub>+Z<sub>2</sub>)
D. Z<sub>1</sub>+Z<sub>2</sub>
Answer» D. Z<sub>1</sub>+Z<sub>2</sub>
Discussion
16.

Norton’s current is equal to the current passing through the ___________ circuited ___________ terminals.

A. short, input
B. short, output
C. open, output
D. open, input
Answer» C. open, output
Discussion