MCQOPTIONS
Saved Bookmarks
MCQOPTIONS
This section includes 16 Mcqs, each offering curated multiple-choice questions to sharpen your Network Theory Questions and Answers knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Find the voltage at node 2 of the circuit shown below. |
| A. | 13 |
| B. | 14 |
| C. | 15 |
| D. | 16 |
| Answer» C. 15 | |
| 2. |
Find the voltage at node 1 of the circuit shown below. |
| A. | 32.7 |
| B. | 33.7 |
| C. | 34.7 |
| D. | 35.7 |
| Answer» C. 34.7 | |
| 3. |
Find the voltage (V) at node 2 in the circuit shown below. |
| A. | 2.7 |
| B. | 3.7 |
| C. | 4.7 |
| D. | 5.7 |
| Answer» D. 5.7 | |
| 4. |
Find the voltage (V) at node 1 in the circuit shown. |
| A. | 5.32 |
| B. | 6.32 |
| C. | 7.32 |
| D. | 8.32 |
| Answer» C. 7.32 | |
| 5. |
Find the value of the resistor R2 (Ω) in the circuit shown below. |
| A. | 5 |
| B. | 6 |
| C. | 7 |
| D. | 8 |
| Answer» C. 7 | |
| 6. |
Find the resistor value R1(Ω) in the figure shown below. |
| A. | 10 |
| B. | 11 |
| C. | 12 |
| D. | 13 |
| Answer» D. 13 | |
| 7. |
Find the voltage at node P in the following figure. |
| A. | 8V |
| B. | 9V |
| C. | 10V |
| D. | 11V |
| Answer» C. 10V | |
| 8. |
Find the voltage Vab in the circuit shown below. |
| A. | 21.66∠-45.02⁰ |
| B. | 20.66∠-45.02⁰ |
| C. | 21.66∠45.02⁰ |
| D. | 20.66∠45.02⁰ |
| Answer» D. 20.66∠45.02⁰ | |
| 9. |
For the circuit shown below, find the voltage across the resistance RL if RL is infinite. |
| A. | 3 |
| B. | 2 |
| C. | 1 |
| D. | 0 |
| Answer» E. | |
| 10. |
In the following circuit. Find the power output of the source. |
| A. | 27 |
| B. | 28 |
| C. | 29 |
| D. | 30 |
| Answer» B. 28 | |
| 11. |
In the circuit shown below. Determine the power dissipated in 3Ω resistor. |
| A. | 7.77 |
| B. | 8.77 |
| C. | 9.77 |
| D. | 10.77 |
| Answer» C. 9.77 | |
| 12. |
In the circuit shown below find the power dissipated by 2Ω resistor. |
| A. | 16.24 |
| B. | 17.24 |
| C. | 18.24 |
| D. | 19.24 |
| Answer» D. 19.24 | |
| 13. |
Find the value of ‘y’ in the equation –(-1/j6)Va+(1/5+1/j5-1/j6)Vb=y obtained from the following circuit. |
| A. | (10∠30o)/5 |
| B. | -(10∠30o)/5 |
| C. | (5∠30o)/5 |
| D. | (-5∠30o)/5 |
| Answer» C. (5∠30o)/5 | |
| 14. |
In the circuit shown below we get a nodal equation as (1/3+1/j4-1/j6)Va—(-1/j6)Vb=x. Find the value of ‘x‘‘. |
| A. | (5∠0o)/3 |
| B. | – (5∠0o)/3 |
| C. | (10∠0o)/3 |
| D. | – (10∠0o)/3 |
| Answer» D. – (10∠0o)/3 | |
| 15. |
Determine the voltage at node ‘b’ in the circuit shown below. |
| A. | -1.34∠-180⁰ |
| B. | 1.34∠-180⁰ |
| C. | -0.34∠-180⁰ |
| D. | 0.34∠-180⁰ |
| Answer» B. 1.34∠-180⁰ | |
| 16. |
In the network shown below, find the voltage at node ‘a’. |
| A. | 5.22∠104.5⁰ |
| B. | 5.22∠-104.5⁰ |
| C. | 6.22∠104.5⁰ |
| D. | 6.22∠-104.5⁰ |
| Answer» C. 6.22∠104.5⁰ | |