In the circuit shown below we get a nodal equation as (1/3+1/j4-1/j6)Va—(-1/j6)Vb=x. Find the value of ‘x‘‘.

In the circuit shown below we get a nodal equation as (1/3+1/j4-1/j6)V

1.	In the circuit shown below we get a nodal equation as (1/3+1/j4-1/j6)Va—(-1/j6)Vb=x. Find the value of ‘x‘‘.
A.	(5∠0o)/3
B.	– (5∠0o)/3
C.	(10∠0o)/3
D.	– (10∠0o)/3
Answer» D.