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This section includes 137 Mcqs, each offering curated multiple-choice questions to sharpen your Network Theory knowledge and support exam preparation. Choose a topic below to get started.
| 101. |
The power absorbed by 2 resistor |
| A. | 450W |
| B. | 4W |
| C. | 225W |
| D. | None of these |
| Answer» B. 4W | |
| 102. |
Power delivered by 6A current source |
| A. | 6W |
| B. | 6W |
| C. | 24W |
| D. | 24W |
| Answer» C. 24W | |
| 103. |
The power delivered by 8A current source |
| A. | 208W |
| B. | 240W |
| C. | 208W |
| D. | None of these |
| Answer» B. 240W | |
| 104. |
Power absorbed by element F |
| A. | 20W |
| B. | 25W |
| C. | 20W |
| D. | 25W |
| Answer» D. 25W | |
| 105. |
For the circuit shown below, V |
| A. | 40V |
| B. | 30V |
| C. | 20V |
| D. | 10V |
| Answer» B. 30V | |
| 106. |
Norton s current in the circuit shown below is |
| A. | 2/5 i |
| B. | Zero |
| C. | Infinite |
| D. | None |
| Answer» C. Infinite | |
| 107. |
Thevenin voltage in the circuit shown below is |
| A. | 3V |
| B. | 2 5V |
| C. | 2V |
| D. | 4V |
| Answer» E. | |
| 108. |
The circuit shown in the figure above |
| A. | is reciprocal but not symmetrical |
| B. | is not reciprocal but symmetrical |
| C. | is both reciprocal and symmetrical |
| D. | is neither reciprocal nor symmetrical |
| Answer» B. is not reciprocal but symmetrical | |
| 109. |
The voltage V for the network shown below is |
| A. | 10V |
| B. | 15V |
| C. | 5V |
| D. | None of these |
| Answer» B. 15V | |
| 110. |
The average power delivered by the dependent current source for the circuit shown below |
| A. | 4 107W |
| B. | 7 107W |
| C. | 4 107W |
| D. | 7 107W |
| Answer» E. | |
| 111. |
Two AC sources feed a common variable resistive load as shown in figure. Under the maximum power transfer condition, the power absorbed by the load resistance R |
| A. | 2200W |
| B. | 1250W |
| C. | 500W |
| D. | 625W |
| Answer» D. 625W | |
| 112. |
In the AC network shown in the figure, the phasor voltage V |
| A. | 0 |
| B. | 5 30 |
| C. | 12 5 30 |
| D. | 17 30 |
| Answer» E. | |
| 113. |
The value of Z in figure which is most appropriate to cause parallel resonance at 500 Hz is |
| A. | 125 00 mH |
| B. | 304 20 F |
| C. | 2 0 F |
| D. | 0 05 F |
| Answer» E. | |
| 114. |
If a resistance R of 1 is connected across the terminals AB as shown in the given figure then the current flowing through R will be |
| A. | 1A |
| B. | 0 5A |
| C. | 0 25A |
| D. | 0 125A |
| Answer» D. 0 125A | |
| 115. |
For the circuit shown below, the value of I |
| A. | 2A |
| B. | 1A |
| C. | 3 6A |
| D. | None of these |
| Answer» D. None of these | |
| 116. |
The impedance matrices of two, two-port networks are given by |
| A. | <table><tr><td rowspan="2"><img src="https://www.indiabix.com/_files/images/data-interpretation/common/15-sym-obracket-h1.gif"></td><td><center>3</center></td><td><center>5</center></td><td rowspan="2"><img src="https://www.indiabix.com/_files/images/data-interpretation/common/15-sym-cbracket-h1.gif"></td></tr><tr><td style="text-align: center;">2</td><td style="text-align: center;">25</td></tr></table> |
| B. | <table><tr><td rowspan="2"><img src="https://www.indiabix.com/_files/images/data-interpretation/common/15-sym-obracket-h1.gif"></td><td><center>18</center></td><td><center>7</center></td><td rowspan="2"><img src="https://www.indiabix.com/_files/images/data-interpretation/common/15-sym-cbracket-h1.gif"></td></tr><tr><td style="text-align: center;">7</td><td style="text-align: center;">28</td></tr></table> |
| C. | <table><tr><td rowspan="2"><img src="https://www.indiabix.com/_files/images/data-interpretation/common/15-sym-obracket-h1.gif"></td><td><center>15</center></td><td><center>2</center></td><td rowspan="2"><img src="https://www.indiabix.com/_files/images/data-interpretation/common/15-sym-cbracket-h1.gif"></td></tr><tr><td style="text-align: center;">5</td><td style="text-align: center;">3</td></tr></table> |
| D. | Intermediate |
| Answer» C. <table><tr><td rowspan="2"><img src="https://www.indiabix.com/_files/images/data-interpretation/common/15-sym-obracket-h1.gif"></td><td><center>15</center></td><td><center>2</center></td><td rowspan="2"><img src="https://www.indiabix.com/_files/images/data-interpretation/common/15-sym-cbracket-h1.gif"></td></tr><tr><td style="text-align: center;">5</td><td style="text-align: center;">3</td></tr></table> | |
| 117. |
If the transmission parameters of the network shown below are A = C = 1, B = 2 and D = 3, then the value of Z |
| A. | 12/13 |
| B. | 13/12 |
| C. | 3 |
| D. | 4 |
| Answer» B. 13/12 | |
| 118. |
A linear resistive circuit has two inputs V |
| A. | 30V |
| B. | -30V |
| C. | 12V |
| D. | None of these |
| Answer» B. -30V | |
| 119. |
The circuit shown in figure 1 is replaced by that in figure 2. If current I remains the same, then R |
| A. | Zero |
| B. | R |
| C. | 2R |
| D. | 4R |
| Answer» E. | |
| 120. |
The effective resistance between terminals A and B in the circuit shown below is |
| A. | R |
| B. | R 1 |
| C. | R/2 |
| D. | <table><tr><td style="border-bottom:1px solid #000000;vertical-align:bottom;padding-bottom:2px;"><center>6</center></td><td rowspan="2">R</td></tr><tr><td style="text-align: center;">11</td></tr></table> |
| E. | |
| Answer» D. <table><tr><td style="border-bottom:1px solid #000000;vertical-align:bottom;padding-bottom:2px;"><center>6</center></td><td rowspan="2">R</td></tr><tr><td style="text-align: center;">11</td></tr></table> | |
| 121. |
For the circuit shown below, the current delivered by 24V source |
| A. | 1 142A |
| B. | 1 142A |
| C. | 2 200A |
| D. | 2 284A |
| Answer» D. 2 284A | |
| 122. |
For the circuit shown below, the power absorbed by the 4 resistor is |
| A. | 2500W |
| B. | 2578W |
| C. | 156 25W |
| D. | None of these |
| Answer» E. | |
| 123. |
Figure shown below is described by equation |
| A. | <table><tr><td style="border-bottom:1px solid #000000;vertical-align:bottom;padding-bottom:2px;"><center>3</center></td><td style="border-bottom:1px solid #000000;vertical-align:bottom;padding-bottom:2px;"><center>dv</center></td><td rowspan="2">+</td><td style="border-bottom:1px solid #000000;vertical-align:bottom;padding-bottom:2px;"><center>v</center></td><td rowspan="2">+</td><td style="border-bottom:1px solid #000000;vertical-align:bottom;padding-bottom:2px;"><center>i</center></td><td rowspan="2">= 0</td></tr><tr><td style="text-align: center;">4</td><td style="text-align: center;">dt</td><td style="text-align: center;">4</td><td style="text-align: center;">2</td></tr></table> |
| B. | <table><tr><td style="border-bottom:1px solid #000000;vertical-align:bottom;padding-bottom:2px;"><center>3</center></td><td style="border-bottom:1px solid #000000;vertical-align:bottom;padding-bottom:2px;"><center>dv</center></td><td rowspan="2">+</td><td style="border-bottom:1px solid #000000;vertical-align:bottom;padding-bottom:2px;"><center>v</center></td><td rowspan="2">-</td><td style="border-bottom:1px solid #000000;vertical-align:bottom;padding-bottom:2px;"><center>i</center></td><td rowspan="2">= 0</td></tr><tr><td style="text-align: center;">4</td><td style="text-align: center;">dt</td><td style="text-align: center;">4</td><td style="text-align: center;">2</td></tr></table> |
| C. | <table><tr><td style="border-bottom:1px solid #000000;vertical-align:bottom;padding-bottom:2px;"><center>4</center></td><td style="border-bottom:1px solid #000000;vertical-align:bottom;padding-bottom:2px;"><center>dv</center></td><td rowspan="2">+</td><td style="border-bottom:1px solid #000000;vertical-align:bottom;padding-bottom:2px;"><center>v</center></td><td rowspan="2">+</td><td style="border-bottom:1px solid #000000;vertical-align:bottom;padding-bottom:2px;"><center>i</center></td><td rowspan="2">= 0</td></tr><tr><td style="text-align: center;">3</td><td style="text-align: center;">dt</td><td style="text-align: center;">4</td><td style="text-align: center;">2</td></tr></table> |
| D. | <table><tr><td style="border-bottom:1px solid #000000;vertical-align:bottom;padding-bottom:2px;"><center>4</center></td><td style="border-bottom:1px solid #000000;vertical-align:bottom;padding-bottom:2px;"><center>dv</center></td><td rowspan="2">+</td><td style="border-bottom:1px solid #000000;vertical-align:bottom;padding-bottom:2px;"><center>v</center></td><td rowspan="2">-</td><td style="border-bottom:1px solid #000000;vertical-align:bottom;padding-bottom:2px;"><center>i</center></td><td rowspan="2">= 0</td></tr><tr><td style="text-align: center;">3</td><td style="text-align: center;">dt</td><td style="text-align: center;">4</td><td style="text-align: center;">2</td></tr></table> |
| Answer» C. <table><tr><td style="border-bottom:1px solid #000000;vertical-align:bottom;padding-bottom:2px;"><center>4</center></td><td style="border-bottom:1px solid #000000;vertical-align:bottom;padding-bottom:2px;"><center>dv</center></td><td rowspan="2">+</td><td style="border-bottom:1px solid #000000;vertical-align:bottom;padding-bottom:2px;"><center>v</center></td><td rowspan="2">+</td><td style="border-bottom:1px solid #000000;vertical-align:bottom;padding-bottom:2px;"><center>i</center></td><td rowspan="2">= 0</td></tr><tr><td style="text-align: center;">3</td><td style="text-align: center;">dt</td><td style="text-align: center;">4</td><td style="text-align: center;">2</td></tr></table> | |
| 124. |
The circuit shown in figure below is equivalent to a load of |
| A. | <table><tr><td style="border-bottom:1px solid #000000;vertical-align:bottom;padding-bottom:2px;"><center>4</center></td><td rowspan="2"> </td></tr><tr><td style="text-align: center;">3</td></tr></table> |
| B. | <table><tr><td style="border-bottom:1px solid #000000;vertical-align:bottom;padding-bottom:2px;"><center>8</center></td><td rowspan="2"> </td></tr><tr><td style="text-align: center;">3</td></tr></table> |
| C. | 4 |
| D. | 2 |
| Answer» C. 4 | |
| 125. |
In a two element series network, the voltage and current respectively given as, |
| A. | 0 9 |
| B. | 0 6 |
| C. | 0 3 |
| D. | 0 1 |
| Answer» C. 0 3 | |
| 126. |
For the circuit shown in the figure, the Thevenin voltage and resistance looking into X Y are |
| A. | 4/3V, 2 |
| B. | 4V, 3/2 |
| C. | 4/3V, 2/3 |
| D. | 4V, 2 |
| Answer» E. | |
| 127. |
The reading of high impedance voltmeter V in the bridge circuit shown in the given figure |
| A. | Zero |
| B. | 3 33V |
| C. | 4 20V |
| D. | 6 66V |
| Answer» C. 4 20V | |
| 128. |
For the circuit shown below, the V |
| A. | 6V |
| B. | 6V |
| C. | 4V |
| D. | 4V |
| Answer» B. 6V | |
| 129. |
For the circuit shown below, the current I |
| A. | 0 4A, 16W |
| B. | 0 4A, 16W |
| C. | 4A, 160W |
| D. | 4A, 160W |
| Answer» C. 4A, 160W | |
| 130. |
Two coils having self-inductances of 0 09H and 0 1H and a mutual inductance of 0 015H. The coefficient of coupling between the coils is |
| A. | 0 06 |
| B. | 0 5 |
| C. | 1 0 |
| D. | 0 05 |
| Answer» C. 1 0 | |
| 131. |
Calculate total current I |
| A. | 0 24 33 |
| B. | 2 4 33 |
| C. | 24 30 |
| D. | None of these |
| Answer» B. 2 4 33 | |
| 132. |
The effective inductance of the circuit shown below |
| A. | 12H |
| B. | 26H |
| C. | 20H |
| D. | None of these |
| Answer» C. 20H | |
| 133. |
The value of VA in the circuit shown in the given figure is |
| A. | 1V |
| B. | 2V |
| C. | 3V |
| D. | 4V |
| Answer» D. 4V | |
| 134. |
The phasor combination of resistive power and reactive power is called |
| A. | true power |
| B. | apparent power |
| C. | reactive power |
| D. | average power |
| Answer» C. reactive power | |
| 135. |
The phase angle between voltage and current |
| A. | 20 5 |
| B. | 20 5 |
| C. | 22 5 |
| D. | None of these |
| Answer» B. 20 5 | |
| 136. |
Current I? |
| A. | 0 77 20 5 |
| B. | 0 77 20 5 |
| C. | 2 77 20 5 |
| D. | 1 77 20 5 |
| Answer» B. 0 77 20 5 | |
| 137. |
The equivalent impedance? |
| A. | 15 82 20 |
| B. | 25 87 20 5 |
| C. | 25 87 20 5 |
| D. | None of these |
| Answer» C. 25 87 20 5 | |