 
			 
			MCQOPTIONS
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				This section includes 9 Mcqs, each offering curated multiple-choice questions to sharpen your Linear Integrated Circuit knowledge and support exam preparation. Choose a topic below to get started.
| 1. | A square root circuit build from multiplier is given an input voltage of 11.5v. Find its corresponding output voltage? | 
| A. | 11v | 
| B. | 15v | 
| C. | 13v | 
| D. | Cannot be determined | 
| Answer» E. | |
| 2. | Find the output voltage of squarer circuit? | 
| A. | V<sub>o</sub> = ( V<sub>ref</sub>/|V<sub>in</sub>|) | 
| B. | V<sub>o</sub> = ( V<sub>ref</sub> |V<sub>in</sub>|) | 
| C. | V<sub>o</sub> = ( V<sub>ref</sub><sup>2</sup> |V<sub>in</sub>|) | 
| D. | V<sub>o</sub> = ( V<sub>ref</sub> |V<sub>in</sub>|<sup>2</sup>) | 
| Answer» C. V<sub>o</sub> = ( V<sub>ref</sub><sup>2</sup> |V<sub>in</sub>|) | |
| 3. | Which circuit can be used to take square root of a signal? | 
| A. | Divider circuit | 
| B. | Multiplier circuit | 
| C. | Squarer circuit | 
| D. | None of the mentioned | 
| Answer» B. Multiplier circuit | |
| 4. | Calculate the output voltage of a squarer circuit, if it input voltage is 3.5v. Assume Vref = 9.67v. | 
| A. | 2.86v | 
| B. | 1.27v | 
| C. | 10v | 
| D. | 4.3v | 
| Answer» C. 10v | |
| 5. | Find the voltage range at which the multiplier can be used as a squarer circuit? | 
| A. | 0 V<sub>in</sub> | 
| B. | V<sub>ref</sub> V<sub>in</sub> | 
| C. | 0 V<sub>ref</sub> | 
| D. | All of the mentioned | 
| Answer» D. All of the mentioned | |
| 6. | How to remove the dc term produced along with the output in frequency doubler? | 
| A. | Use a capacitor between load and output terminal | 
| B. | Use a resistor between load and output terminal | 
| C. | Use a Inductor between load and output terminal | 
| D. | Use a potentiometer between load and output terminal | 
| Answer» B. Use a resistor between load and output terminal | |
| 7. | Compute the output of frequency doubler. If the inputs Vx = Vsin t and Vy = Vsin( t+ ) are applied to a four quadrant multiplier? | 
| A. | V<sub>o</sub>= { V<sub>x</sub> V<sub>y</sub> [cos -(cos cos2 t)+(sin sin2 t)]}/ V<sub>ref</sub> | 
| B. | V<sub>o</sub>= { V<sub>x</sub> V<sub>y</sub> [cos -(cos cos2 t)+(sin sin2 t)]}/ 2 | 
| C. | V<sub>o</sub>= { V<sub>x</sub> V<sub>y</sub> [cos -(cos cos2 t)+(sin sin2 t)]}/(2 V<sub>ref</sub>) | 
| D. | V<sub>o</sub>= { V<sub>x</sub> V<sub>y</sub> [cos -(cos cos2 t)+(sin sin2 t)]}/(2 V<sub>ref</sub>) | 
| Answer» D. V<sub>o</sub>= { V<sub>x</sub> V<sub>y</sub> [cos -(cos cos2 t)+(sin sin2 t)]}/(2 V<sub>ref</sub>) | |
| 8. | Which circuit allows to double the frequency? | 
| A. | Frequency doubler | 
| B. | Square doubler | 
| C. | Double multiplier | 
| D. | All of the mentioned | 
| Answer» B. Square doubler | |
| 9. | Determine the relationship between log-antilog method. | 
| A. | lnV<sub>x</sub> lnV<sub>y</sub> = ln(V<sub>x</sub>+V<sub>y</sub>) | 
| B. | lnV<sub>x</sub> / lnV<sub>y</sub> = ln(V<sub>x</sub>-V<sub>y</sub>) | 
| C. | lnV<sub>x</sub> -lnV<sub>y</sub> = ln(V<sub>x</sub>/V<sub>y</sub>) | 
| D. | lnV<sub>x</sub>+ lnV<sub>y</sub> = ln(V<sub>x</sub> V<sub>y</sub>) | 
| Answer» E. | |