MCQOPTIONS
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MCQOPTIONS
This section includes 14 Mcqs, each offering curated multiple-choice questions to sharpen your Physics knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
In a galvanometer 15% of the total current in the circuit passes through it. If the resistance of the galvanometer is G, then find out the shunt resistance S that is connected to the galvanometer. |
| A. | \(\frac {17G}{3}\) |
| B. | \(\frac {16G}{3}\) |
| C. | \(\frac {5G}{17}\) |
| D. | \(\frac {3G}{17}\) |
| Answer» E. | |
| 2. |
The current passing through a galvanometer is 30 mA, resistance of the galvanometer is 50 Ω and a shunt is 1 Ω is connected to the galvanometer. What is the maximum current that can be measured by this ammeter? |
| A. | 1.53 A |
| B. | 15.3 A |
| C. | 0.153 A |
| D. | 153 A |
| Answer» B. 15.3 A | |
| 3. |
What is the value of the shunt resistance (S) required if a galvanometer has a resistance f 50 Ω and a maximum of 0.05A current that can be passed through it? The ammeter range is changed to 20 A. |
| A. | 0.120 Ω |
| B. | 0.125 Ω |
| C. | 0.130 Ω |
| D. | 0.145 Ω |
| Answer» C. 0.130 Ω | |
| 4. |
A moving coil galvanometer has the following characteristics – Number of turns of coil = 50; Area of coil = 70 mm2; Resistance of coil = 30 Ω; Flux density of radial field = 0.1 T; Torsional constant of suspension wire = 7 × 10-8 N m/rad. Calculate the current and voltage sensitivity. |
| A. | 10 div/mA, 0.166 div/mV |
| B. | 15 div/mA, 0.115 div/mV |
| C. | 5 div/mA, 0.167 div/mV |
| D. | 20 div/mA, 0.100 div/mV |
| Answer» D. 20 div/mA, 0.100 div/mV | |
| 5. |
When 0.010A current flows through a moving coil galvanometer, it gives full deflection. Then, it is converted into a voltmeter which gives a reading of 10 V using an external resistance of 950 Ω. What is the resistance of the galvanometer (G)? |
| A. | 40 Ω |
| B. | 50 Ω |
| C. | 60 Ω |
| D. | 70 Ω |
| Answer» C. 60 Ω | |
| 6. |
A galvanometer has resistance of 10 ohms and a full scale deflection is produced by 5 milli amperes. What is the value of resistance that should be connected in series with it in order to enable it to read 2V? |
| A. | 20 Ω |
| B. | 10 Ω |
| C. | 40 Ω |
| D. | 30 Ω |
| Answer» E. | |
| 7. |
The galvanometer shown below has a resistance (RG) of 50.00 Ω. Now, this galvanometer is converted to an ammeter with the help of a shunt resistance (rS) of 0.05 Ω. Calculate the current passing through the galvanometer in both the cases. |
| A. | 0.0545 A, 0.594 A |
| B. | 0.0545 A, 0.05 A |
| C. | 0.0545 A, 0.06 A |
| D. | 0.07 A, 0.05 A |
| Answer» B. 0.0545 A, 0.05 A | |
| 8. |
An ideal ammeter has infinite resistance and an ideal voltmeter has zero resistance. |
| A. | True |
| B. | False |
| Answer» C. | |
| 9. |
What should be the value of shunt resistance of the ammeter in order to increase its range? |
| A. | S = (n – 1) G |
| B. | S = (n – 1)/G |
| C. | S = \(\frac {G}{(n – 1)}\) |
| D. | S = \(\frac {G}{(n + 1)}\) |
| Answer» D. S = \(\frac {G}{(n + 1)}\) | |
| 10. |
How is galvanometer converted into a voltmeter? |
| A. | By connecting a high resistance multiplier in parallel to the galvanometer |
| B. | By connecting a low resistance multiplier in parallel to the galvanometer |
| C. | By connecting a low resistance multiplier in series with the galvanometer |
| D. | By connecting a high resistance multiplier in series with the galvanometer |
| Answer» E. | |
| 11. |
How is a galvanometer converted into an ammeter? |
| A. | By connecting a high resistance shunt in parallel to the galvanometer |
| B. | By connecting a low resistance shunt in parallel to the galvanometer |
| C. | By connecting a high resistance shunt in series with the galvanometer |
| D. | By connecting a low resistance shunt in series with the galvanometer |
| Answer» C. By connecting a high resistance shunt in series with the galvanometer | |
| 12. |
Voltage sensitivity and current sensitivity are related. |
| A. | True |
| B. | False |
| Answer» B. False | |
| 13. |
Pick out the expression for galvanometer constant from the following? |
| A. | G = \(\frac {k}{NAB}\) |
| B. | G = k × NAB |
| C. | G = \(\frac {NAB}{k}\) |
| D. | \(\frac {1}{G} \, = \, \frac {k}{NAB}\) |
| Answer» B. G = k × NAB | |
| 14. |
What is moving coil galvanometer used for? |
| A. | Measurement of voltage only |
| B. | Measurement of resistance |
| C. | Measurement of small currents |
| D. | Measurement of electric field |
| Answer» D. Measurement of electric field | |