Explore topic-wise MCQs in Network Theory.

This section includes 15 Mcqs, each offering curated multiple-choice questions to sharpen your Network Theory knowledge and support exam preparation. Choose a topic below to get started.

1.

In the following circuit. Find the current through 4Ω resistor using Millman’s Theorem.

A. 0.5
B. 1
C. 1.5
D. 2
Answer» D. 2
Discussion
2.

Consider the circuit shown below. Find the current through 4Ω resistor.

A. 2
B. 1.5
C. 1
D. 0.5
Answer» C. 1
Discussion
3.

Find the current through 3Ω resistor in the circuit shown below using Millman’s Theorem.

A. 4
B. 3
C. 2
D. 1
Answer» C. 2
Discussion
4.

Calculate the current through 3Ω resistor in the circuit shown below.

A. 1
B. 2
C. 3
D. 4
Answer» D. 4
Discussion
5.

According to Millman’s Theorem, if there are n current sources with n internal conductances respectively, are in series, then the value of equivalent conductance is?

A. G’=R1+R2+⋯Rn
B. G’=1/(1/R1+1/R2+⋯1/Rn)
C. G’=1/((R1+R2+⋯Rn))
D. G’=1/R1+1/R2+⋯1/Rn
Answer» D. G’=1/R1+1/R2+⋯1/Rn
Discussion
6.

According to Millman’s Theorem, if there are n current sources with n internal conductances respectively, are in series, then the value of equivalent current source is?

A. I‘=((I1R1+I2R2+⋯.+InRn))/(R1+R2+⋯Rn)
B. I’=I1R1+I2R2+⋯.+InRn
C. I’=((I1/R1+I2/R2+⋯.+In/Rn))/(R1+R2+⋯Rn)
D. I’=I1/R1+I2/R2+⋯.+In/Rn
Answer» B. I’=I1R1+I2R2+⋯.+InRn
Discussion
7.

According to Millman’s Theorem, if there are n current sources with n internal conductances respectively, are in series, then these sources are replaced by?

A. single voltage source V’ in parallel with G’
B. single current source I’ in series with G’
C. single current source I’ in parallel with G’
D. single voltage source V’ in series with G’
Answer» D. single voltage source V’ in series with G’
Discussion
8.

According to Millman’s Theorem, if there are n voltage sources with n internal resistances respectively, are in parallel, then the value of equivalent resistance is?

A. R’=G1+G2+⋯Gn
B. R’=1/G1+1/G2+⋯1/Gn
C. R’=1/((G1+G2+⋯Gn))
D. R’=1/(1/G1+1/G2+⋯1/Gn)
Answer» D. R’=1/(1/G1+1/G2+⋯1/Gn)
Discussion
9.

According to Millman’s Theorem, if there are n voltage sources with n internal resistances respectively, are in parallel, then the value of equivalent voltage source is?

A. V‘=(V1G1+V2G2+⋯.+VnGn)
B. V‘=((V1G1+V2G2+⋯.+VnGn))/((1/G1+1/G2+⋯1/Gn))
C. V‘=((V1G1+V2G2+⋯.+VnGn))/(G1+G2+⋯Gn)
D. V‘=((V1/G1+V2/G2+⋯.+Vn/Gn))/( G1+G2+⋯Gn)
Answer» D. V‘=((V1/G1+V2/G2+⋯.+Vn/Gn))/( G1+G2+⋯Gn)
Discussion
10.

According to Millman’s Theorem, if there are n voltage sources with n internal resistances respectively, are in parallel, then these sources are replaced by?

A. single current source I’ in series with R’
B. single voltage source V’ in series with R’
C. single current source I’ in parallel to R’
D. single voltage source V’ in parallel to R’
Answer» C. single current source I’ in parallel to R’
Discussion
11.

In_the_circuit_shown_in_the_question_9_find_the_current_through_4Ω_resistor_using_Millman’s_Theorem.$#

A. 0.5
B. 1
C. 1.5
D. 2
Answer» D. 2
Discussion
12.

Find the current through 3Ω resistor in the circuit shown above using Millman’s Theorem?#

A. 4
B. 3
C. 2
D. 1
Answer» C. 2
Discussion
13.

According to Millman’s Theorem, if there are n current sources with n internal conductances respectively, are in series, then these sources are replaced by?$

A. single voltage source V’ in parallel with G’
B. single current source I’ in series with G’
C. single current source I’ in parallel with G’
D. single voltage source V’ in series with G’
Answer» D. single voltage source V‚Äö√Ñ√∂‚àö√ë‚àö¬• in series with G‚Äö√Ñ√∂‚àö√ë‚àö¬•
Discussion
14.

In the question above, the value of equivalent voltage source is?

A. V<sup>‘</sup>=(V<sub>1</sub>G<sub>1</sub>+V<sub>2</sub>G<sub>2</sub>+⋯.+V<sub>n</sub>G<sub>n</sub>)
B. V<sup>‘</sup>=((V<sub>1</sub>G<sub>1</sub>+V<sub>2</sub>G<sub>2</sub>+⋯.+V<sub>n</sub>G<sub>n</sub>))/((1/G<sub>1</sub>+1/G<sub>2</sub>+⋯1/G<sub>n</sub>))
C. V<sup>‘</sup>=((V<sub>1</sub>G<sub>1</sub>+V<sub>2</sub>G<sub>2</sub>+⋯.+V<sub>n</sub>G<sub>n</sub>))/(G<sub>1</sub>+G<sub>2</sub>+⋯G<sub>n</sub>)
D. V<sup>‘</sup>=((V<sub>1</sub>/G<sub>1</sub>+V<sub>2</sub>/G<sub>2</sub>+⋯.+V<sub>n</sub>/G<sub>n</sub>))/( G<sub>1</sub>+G<sub>2</sub>+⋯G<sub>n</sub>)
Answer» D. V<sup>‚Äö√Ñ√∂‚àö√ë‚àö‚â§</sup>=((V<sub>1</sub>/G<sub>1</sub>+V<sub>2</sub>/G<sub>2</sub>+‚Äö√Ñ√∂‚àö¬£‚àö√≤.+V<sub>n</sub>/G<sub>n</sub>))/( G<sub>1</sub>+G<sub>2</sub>+‚Äö√Ñ√∂‚àö¬£‚àö√≤G<sub>n</sub>)
Discussion
15.

According to Millman’s Theorem, if there are n voltage sources with n internal resistances respectively, are in parallel, then these sources are replaced by?

A. single current source I’ in series with R’
B. single voltage source V’ in series with R’
C. single current source I’ in parallel to R’
D. single voltage source V’ in parallel to R’
Answer» C. single current source I‚Äö√Ñ√∂‚àö√ë‚àö¬• in parallel to R‚Äö√Ñ√∂‚àö√ë‚àö¬•
Discussion