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This section includes 5 Mcqs, each offering curated multiple-choice questions to sharpen your Ordinary Differential Equations knowledge and support exam preparation. Choose a topic below to get started.
1. |
What is the solution of D.E (D2 2D)y = ex sin x when solved using the method of undetermined coefficients? |
A. | ( y = c_1 + c_2 ,e^{2x} frac{e^x (xsin x + cos u2061x)}{2} ) |
B. | (y = c_1 + c_2 ,e^{2x} frac{e^x sin x}{2} ) |
C. | (y = c_1 + c_2 ,e^{2x} frac{e^x cos x}{2} ) |
D. | (y = c_1 + c_2 ,e^{2x} frac{e^x (sin x + x cos u2061x)}{4} ) |
Answer» C. (y = c_1 + c_2 ,e^{2x} frac{e^x cos x}{2} ) | |
2. |
Using the method of undetermined coefficients find the P.I for the D.E x (t) x (t) = 3et + sin t. |
A. | x<sub>p</sub> = 3e<sup>t</sup> + ( frac{t}{2} ) (cos u2061t 2 sin u2061t ) |
B. | x<sub>p</sub> = 3te<sup>t</sup> + ( frac{1}{2} ) (cos u2061t + sin u2061t ) |
C. | x<sub>p</sub> = 3te<sup>t</sup> + ( frac{t}{3} ) (4cos u2061t + 2sin u2061t ) |
D. | x<sub>p</sub> = 3e<sup>t</sup> + ( frac{1}{2} ) (cos u2061t sin u2061t ) |
Answer» C. x<sub>p</sub> = 3te<sup>t</sup> + ( frac{t}{3} ) (4cos u2061t + 2sin u2061t ) | |
3. |
Find the Particular integral solution of the D.E (D2 4D + 3)y = 20 cos x by the method of undetermined coefficients. |
A. | y<sub>p</sub> = 4 cos u2061x 3 sin u2061x |
B. | y<sub>p</sub> = 2 sin u2061x 4 cos u2061x |
C. | y<sub>p</sub> = 3 cos u2061x + 4 sin u2061x |
D. | y<sub>p</sub> = 2 cos u2061x 4 sin u2061x |
Answer» E. | |
4. |
Solution of the D.E y + 3y + 2y = 12x2 when solved using the method of undetermined coefficients is ________ |
A. | y = c<sub>1</sub> e<sup>x</sup> + c<sub>2</sub> e<sup>2x</sup> + 2 11x + x<sup>2</sup> |
B. | y = c<sub>1</sub> e<sup> x</sup> + c<sub>2</sub> e<sup> 2x</sup> + 18 + 21x + 3x<sup>2</sup> |
C. | y = c<sub>1</sub> e<sup>x</sup> + c<sub>2</sub> e<sup> 2x</sup> + 11 + 18x + 2x<sup>2</sup> |
D. | y = c<sub>1</sub> e<sup> x</sup> + c<sub>2</sub> e<sup> 2x</sup> + 21 18x + 6x<sup>2</sup> |
Answer» E. | |
5. |
Solution of the D.E y 4y + 4y = ex when solved using method of undetermined coefficients is _____ |
A. | y = (c<sub>1</sub> + c<sub>2</sub>)e<sup>2x</sup> + 2e<sup>x</sup> 1 |
B. | y = (c<sub>1</sub> + c<sub>2</sub> x)e<sup>2x</sup> + 4e<sup>x</sup> 4 |
C. | y = (c<sub>1</sub> + c<sub>2</sub> x)e<sup>2x</sup> + e<sup>x</sup> |
D. | y = (c<sub>1</sub> + c<sub>2</sub> x)e<sup>x</sup> + 4e<sup>x</sup> |
Answer» D. y = (c<sub>1</sub> + c<sub>2</sub> x)e<sup>x</sup> + 4e<sup>x</sup> | |