Explore topic-wise MCQs in Boolean Algebra and Logic Simplification .

This section includes 11 Mcqs, each offering curated multiple-choice questions to sharpen your Boolean Algebra and Logic Simplification knowledge and support exam preparation. Choose a topic below to get started.

1.

How many address bits are needed to select all memory locations in the 2118 16K × 1 RAM?

A. 16
B. 10
C. 8
D. 14
Answer» E.
Discussion
2.

What is the bit storage capacity of a ROM with a 1024 × 8 organization?

A. 1024
B. 2048
C. 4096
D. 8192
Answer» E.
Discussion
3.

How many 8 k × 1 RAMs are required to achieve a memory with a word capacity of 8 k and a word length of eight bits?

A. Eight
B. Four
C. Two
D. One
Answer» B. Four
Discussion
4.

The time from the beginning of a read cycle to the end of t ACS or t AA is referred to as:

A. access time
B. data hold
C. read cycle time
D. write enable time
Answer» B. data hold
Discussion
5.

How many 1K × 4 RAM chips would be required to build a 1K × 8 memory system?

A. 2
B. 4
C. 8
D. 16
Answer» B. 4
Discussion
6.

How many address bits are required for a 4096-bit memory organized as a 512 × 8 memory?

A. 2
B. 4
C. 8
D. 9
Answer» E.
Discussion
7.

What are the typical values of t OE ?

A. 10 to 20 ns for bipolar
B. 25 to 100 ns for NMOS
C. 12 to 50 ns for CMOS
D. All of the above
Answer» E.
Discussion
8.

How many address lines would be required for a 2K × 4 memory chip?

A. 8
B. 10
C. 11
D. 12
Answer» D. 12
Discussion
9.

Suppose that a certain semiconductor memory chip has a capacity of 8K × 8. How many bytes could be stored in this device?

A. 8,000
B. 64,000
C. 65,536
D. 8,192
Answer» E.
Discussion
10.

How many 2K × 8 ROM chips would be required to build a 16K × 8 memory system?

A. 2
B. 4
C. 8
D. 16
Answer» D. 16
Discussion
11.

How many address bits are needed to select all memory locations in the 2118 16K × 1 RAM?

A. 8
B. 10
C. 14
D. 16
Answer» D. 16
Discussion