Explore topic-wise MCQs in Network Theory.

This section includes 14 Mcqs, each offering curated multiple-choice questions to sharpen your Network Theory knowledge and support exam preparation. Choose a topic below to get started.

1.

Given a m-derived low pass filter has cut-off frequency 1 kHz, design impedance of 400Ω and the resonant frequency of 1100 Hz. Find the value of m.

A. 0.216
B. 0.316
C. 0.416
D. 0.516
Answer» D. 0.516
Discussion
2.

Given a m-derived low pass filter has cut-off frequency 1 kHz, design impedance of 400Ω and the resonant frequency of 1100 Hz. Find the value of k.

A. 400
B. 1000
C. 1100
D. 2100
Answer» B. 1000
Discussion
3.

The value of Z1‘ in terms of Z1, Z2 from the circuits shown below is?

A. Z1‘=(m Z2(Z2 4 m)/(1-m2))/m Z1(Z2 4 m/(1-m2))
B. Z1‘=(m Z1(Z2 4 m)/(1-m2))/m Z2(Z2 4 m/(1-m2))
C. Z1‘=(m Z1(Z2 4 m)/(1-m2))/m Z1(Z2 4 m/(1-m2))
D. Z1‘=(m Z1(Z2 4 m)/(1-m2))/m Z1(Z1 4 m/(1-m2))
Answer» D. Z1‘=(m Z1(Z2 4 m)/(1-m2))/m Z1(Z1 4 m/(1-m2))
Discussion
4.

The relation between Zoπ and Zoπ’ in the circuits shown below is?

A. Zoπ = 2 Zoπ’
B. Zoπ = 4 Zoπ’
C. Zoπ = Zoπ’
D. Zoπ = 3 Zoπ’
Answer» D. Zoπ = 3 Zoπ’
Discussion
5.

The value of Z2’ in terms of Z1, Z2 from the circuits shown below is?

A. Z2‘=Z2/4 m (1-m2)+Z2/m
B. Z2‘=Z1/4 m (1-m2)+Z1/m
C. Z2‘=Z2/4 m (1-m2)+Z1/m
D. Z2‘=Z1/4 m (1-m2)+Z2/m
Answer» E.
Discussion
6.

The relation between ZoT and ZoT‘ in the circuits shown below.

A. ZoT = ZoT‘
B. ZoT = 2 ZoT‘
C. ZoT = 3 ZoT‘
D. ZoT = 4 ZoT‘View Answer
Answer» B. ZoT = 2 ZoT‘
Discussion
7.

GIVEN_A_M-DERIVED_LOW_PASS_FILTER_HAS_CUT-OFF_FREQUENCY_1_KHZ,_DESIGN_IMPEDANCE_OF_400‚ÄÖ√Ñ√∂‚ÀÖ√´¬¨‚ÀÇ_AND_THE_RESONANT_FREQUENCY_OF_1100_HZ._FIND_THE_VALUE_OF_K.?$#

A. 400
B. 1000
C. 1100
D. 2100
Answer» B. 1000
Discussion
8.

The_value_of_m_from_the_information_provided_in_question_9.$

A. 0.216
B. 0.316
C. 0.416
D. 0.516
Answer» D. 0.516
Discussion
9.

The expression of m of the m-derived low pass filter is?

A. m=‚àö(1+(f<sub>c</sub>/f<sub>r</sub>)<sup>2</sup> )
B. m=‚àö(1+(f<sub>c</sub>/f)<sup>2</sup>)
C. m=‚àö(1-(f<sub>c</sub>/f<sub>r</sub>)<sup>2</sup> )
D. m=‚àö(1-(f<sub>c</sub>/f)<sup>2</sup> )
Answer» D. m=‚Äö√Ñ√∂‚àö‚Ć‚àö‚àÇ(1-(f<sub>c</sub>/f)<sup>2</sup> )
Discussion
10.

The resonant frequency of m-derived low pass filter in terms of the cut-off frequency of low pass filter is?

A. f<sub>c</sub>/‚àö(1-m<sup>2</sup> )
B. f<sub>c</sub>/‚àö(1+m<sup>2</sup> )
C. f<sub>c</sub>/(π√(1-m<sup>2</sup> ))
D. f<sub>c</sub>/(π√(1+m<sup>2</sup> ))
Answer» B. f<sub>c</sub>/‚Äö√Ñ√∂‚àö‚Ć‚àö‚àÇ(1+m<sup>2</sup> )
Discussion
11.

The cut-off frequency of the low pass filter is?

A. 1/‚àöLC
B. 1/(π√LC)
C. 1/‚àöL
D. 1/(π√L)
Answer» C. 1/‚Äö√Ñ√∂‚àö‚Ć‚àö‚àÇL
Discussion
12.

The value of resonant frequency in the m-derived low pass filter is?

A. f<sub>r</sub>=1/(‚àö(LC(1+m<sup>2</sup> ) ))
B. f<sub>r</sub>=1/(√(πLC(1+m<sup>2</sup> ) ))
C. f<sub>r</sub>=1/(‚àö(LC(1-m<sup>2</sup> ) ))
D. f<sub>r</sub>=1/(√(πLC(1-m<sup>2</sup> ) ))
Answer» E.
Discussion
13.

The value of Z1‘ in terms of Z1, Z2 from the circuits shown in question 3 is?$

A. Z<sub>1</sub><sup>‘</sup>=(m Z<sub>2</sub>(Z<sub>2</sub> 4 m)/(1-m<sup>2</sup> ))/m Z<sub>1</sub>(Z<sub>2</sub> 4 m/(1-m<sup>2</sup> ))
B. Z<sub>1</sub><sup>‘</sup>=(m Z<sub>1</sub>(Z<sub>2</sub> 4 m)/(1-m<sup>2</sup> ))/m Z<sub>2</sub>(Z<sub>2</sub> 4 m/(1-m<sup>2</sup> ))
C. Z<sub>1</sub><sup>‘</sup>=(m Z<sub>1</sub>(Z<sub>2</sub> 4 m)/(1-m<sup>2</sup> ))/m Z<sub>1</sub>(Z<sub>2</sub> 4 m/(1-m<sup>2</sup> ))
D. Z<sub>1</sub><sup>‘</sup>=(m Z<sub>1</sub>(Z<sub>2</sub> 4 m)/(1-m<sup>2</sup> ))/m Z<sub>1</sub>(Z<sub>1</sub> 4 m/(1-m<sup>2</sup> ))
Answer» D. Z<sub>1</sub><sup>‚Äö√Ñ√∂‚àö√ë‚àö‚â§</sup>=(m Z<sub>1</sub>(Z<sub>2</sub> 4 m)/(1-m<sup>2</sup> ))/m Z<sub>1</sub>(Z<sub>1</sub> 4 m/(1-m<sup>2</sup> ))
Discussion
14.

The value of Z2’ in terms of Z1, Z2 from the circuits shown in question 1 is?$

A. Z<sub>2</sub><sup>‘</sup>=Z<sub>2</sub>/4 m (1-m<sup>2</sup> )+Z<sub>2</sub>/m
B. Z<sub>2</sub><sup>‘</sup>=Z<sub>1</sub>/4 m (1-m<sup>2</sup> )+Z<sub>1</sub>/m
C. Z<sub>2</sub><sup>‘</sup>=Z<sub>2</sub>/4 m (1-m<sup>2</sup> )+Z<sub>1</sub>/m
D. Z<sub>2</sub><sup>‘</sup>=Z<sub>1</sub>/4 m (1-m<sup>2</sup> )+Z<sub>2</sub>/m
Answer» E.
Discussion