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				This section includes 13 Mcqs, each offering curated multiple-choice questions to sharpen your Machine Kinematics knowledge and support exam preparation. Choose a topic below to get started.
| 1. | THE_CORIOLIS_COMPONENT_OF_ACCELERATION_DEPENDS_UPON?$ | 
| A. | velocity of slider | 
| B. | angular velocity of the link | 
| C. | all of the mentioned | 
| D. | none of the mentioned | 
| Answer» D. none of the mentioned | |
| 2. | A slider moves at a velocity v on a link revolving at ωrad/s. The coriolis component of acceleration is$# | 
| A. | ωv | 
| B. | 2ωv | 
| C. | ω<sup>2</sup>v | 
| D. | 2ωv<sup>2</sup> | 
| Answer» C. ‚âà√¨‚àö¬¢<sup>2</sup>v | |
| 3. | A_body_in_motion_will_be_subjected_to_coriolis_acceleration_when_that_body_is$ | 
| A. | in plane rotation with variable velocity | 
| B. | in plane translation with variable velocity | 
| C. | in plane motion which is a resultant of plane translation and rotation | 
| D. | restrained to rotate while sliding over another body | 
| Answer» E. | |
| 4. | The sense of coriolis component 2ωv is same as that of the relative velocity vector v rotated at$ | 
| A. | 45<sup>0</sup> in the direction of rotation of the link containing the path | 
| B. | 45<sup>0</sup> in the direction opposite to the rotation of the link containing the path | 
| C. | 90<sup>0</sup> in the direction of rotation of the link containing the path | 
| D. | 180<sup>0</sup> in the direction opposite to the rotation of the link containing the path | 
| Answer» D. 180<sup>0</sup> in the direction opposite to the rotation of the link containing the path | |
| 5. | The coriolis component of acceleration leads the sliding velocity by | 
| A. | 45<sup>0</sup> | 
| B. | 90<sup>0</sup> | 
| C. | 135<sup>0</sup> | 
| D. | 180<sup>0</sup> | 
| Answer» C. 135<sup>0</sup> | |
| 6. | The coriolis component of acceleration is taken into account fo? | 
| A. | slider crank mechanism | 
| B. | four bar chain mechanism | 
| C. | quick return motion mechanism | 
| D. | all of the mentioned | 
| Answer» D. all of the mentioned | |
| 7. | The coriolis component of acceleration acts | 
| A. | along the sliding surface | 
| B. | perpendicular to the sliding surface | 
| C. | at 45<sup>0</sup> to the sliding surface | 
| D. | parallel to the sliding surface | 
| Answer» C. at 45<sup>0</sup> to the sliding surface | |
| 8. | The tangential component of acceleration of the slider with respect to the coincident point on the link is called coriolis component of acceleration. | 
| A. | True | 
| B. | False | 
| Answer» B. False | |
| 9. | In a shaper mechanism, the coriolis component of acceleration does not exists. | 
| A. | True | 
| B. | False | 
| Answer» C. | |
| 10. | When a point at the end of a link moves with constant angular velocity, its acceleration will have | 
| A. | radial component only | 
| B. | tangential component only | 
| C. | coriolis component only | 
| D. | radial and tangential components both | 
| Answer» B. tangential component only | |
| 11. | When a point moves along a straight line, its acceleration will have | 
| A. | radial component only | 
| B. | tangential component only | 
| C. | coriolis component only | 
| D. | radial and tangential components both | 
| Answer» C. coriolis component only | |
| 12. | The centre of gravity of a coupler link in a four bar mechanism will experience | 
| A. | no acceleration | 
| B. | only linear acceleration | 
| C. | only angular acceleration | 
| D. | both linear and angular acceleration | 
| Answer» E. | |
| 13. | The acceleration of a particle at any instant has two components, radial component and tangential component. These two components will be | 
| A. | parallel to each other | 
| B. | perpendicular to each other | 
| C. | inclined at 45<sup>0</sup> | 
| D. | opposite to each other | 
| Answer» C. inclined at 45<sup>0</sup> | |