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This section includes 9 Mcqs, each offering curated multiple-choice questions to sharpen your Networking knowledge and support exam preparation. Choose a topic below to get started.
1. |
Find the number of addresses in a range if the first address is 146.102.29.0 and last address is 146.102.32.255. |
A. | 1028 |
B. | 1024 |
C. | 578 |
D. | 512 |
Answer» C. 578 | |
2. |
The following IPv4 addresses in hexadecimal notation is 10000001 00001011 00001011 11101111- |
A. | 0x810B0BEF |
B. | 0x810D0AFF |
C. | 0x810B0BFE |
D. | 0x810C0CEF |
Answer» B. 0x810D0AFF | |
3. |
What is the error (if any) in the following representation 11100010.23.14.67? |
A. | There should be no leading zeros |
B. | We cannot have more than 4 bytes in an IPv4 address |
C. | Each byte should be less than or equal to 255 |
D. | None of the mentioned |
Answer» E. | |
4. |
What is the error (if any) in the following representation 75.45.301.14? |
A. | There should be no leading zeros |
B. | We cannot have more than 4 bytes in an IPv4 address |
C. | Each byte should be less than or equal to 255 |
D. | No error |
Answer» D. No error | |
5. |
What is the error (if any) in the following representation 221.34.7.8.20? |
A. | There should be no leading zeros |
B. | Each byte should be less than or equal to 255 |
C. | We cannot have more than 4 bytes in an IPv4 address |
D. | No error |
Answer» D. No error | |
6. |
What is the error (if any) in the following representation 111.56.045.78? |
A. | There should be no leading zeros |
B. | We cannot have more than 4 bytes in an IPv4 address |
C. | Each byte should be less than or equal to 255 |
D. | No error |
Answer» B. We cannot have more than 4 bytes in an IPv4 address | |
7. |
Convert the following dotted-decimal notation to binary notation 111.56.45.78 |
A. | 01101111 00111000 00101101 01001110 |
B. | 11101111 00111000 00101101 10001110 |
C. | 10000000 00001011 00000011 00011111 |
D. | 10000001 00001011 00001011 11101111 |
Answer» B. 11101111 00111000 00101101 10001110 | |
8. |
Convert the following binary notation to dotted-decimal notation
|
A. | 129.11.11.239 |
B. | 128.11.12.231 |
C. | 127.11.13.244 |
D. | 129.12.1.231 |
Answer» B. 128.11.12.231 | |
9. |
Convert the following binary notation to dotted-decimal notation
|
A. | 128.11.5.32 |
B. | 128.11.3.31 |
C. | 127.11.3.32 |
D. | 127.12.5.31 |
Answer» C. 127.11.3.32 | |