MCQOPTIONS
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MCQOPTIONS
This section includes 11 Mcqs, each offering curated multiple-choice questions to sharpen your Structural Analysis knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
What will be the ILD equation for ILD of shear at point D? |
| A. | -.43 + 0.16625X |
| B. | -.33 + 0.16625X |
| C. | -.53 + 0.16625X |
| D. | -.33 + 0.216625X |
| Answer» C. -.53 + 0.16625X | |
| 2. |
What will be the ILD equation for ILD of shear at point C for AB part of beam? |
| A. | -0.33 + 0.165X |
| B. | -0.33 + 0.265X |
| C. | -0.43 + 0.165X |
| D. | -0.33 + 0.365X |
| Answer» B. -0.33 + 0.265X | |
| 3. |
What will be the ILD equation for ILD of shear at point B? |
| A. | 1.33 – 0.116625X |
| B. | 2.33 – 0.16625X |
| C. | 3.33 – 0.16625X |
| D. | 1.33 – 0.16625X |
| Answer» E. | |
| 4. |
If both, a load of 50KN at point C and a uniform load of 10KN/m between CB acts, then what will be the shear generated at point C? |
| A. | 48.75 |
| B. | 50.75 |
| C. | 46.75 |
| D. | 52.75 |
| Answer» B. 50.75 | |
| 5. |
What will be the equation of ILD of shear force at point C for AC part? |
| A. | .25X – 1.25 |
| B. | .25X – 2.25 |
| C. | .25X – .25 |
| D. | .25X + .25 |
| Answer» D. .25X + .25 | |
| 6. |
IF_BOTH,_A_LOAD_OF_50KN_AT_POINT_C_AND_A_UNIFORM_LOAD_OF_10KN/M_BETWEEN_CB_ACTS,_THEN_WHAT_WILL_BE_THE_SHEAR_GENERATED_AT_POINT_C??$ |
| A. | 48.75 |
| B. | 50.75 |
| C. | 46.75 |
| D. | 52.75 |
| Answer» B. 50.75 | |
| 7. |
What will be the shear developed at point C if a uniform load of 10KN/m is applied between point B and C? |
| A. | 10.25 KN |
| B. | 11.25 KN |
| C. | 12.25 KN |
| D. | 13.25 KN |
| Answer» E. | |
| 8. |
If a concentrated load of 50KN is applied at point C, then what will be the shear developed at point C? |
| A. | 17.5 KN |
| B. | 27.5 KN |
| C. | 37.5 KN |
| D. | 47.5 KN |
| Answer» B. 27.5 KN | |
| 9. |
If we have to apply a concentrated load in the above shown beam, such that shear at C becomes max. , where should we apply that load? |
| A. | At A |
| B. | At B |
| C. | At C |
| D. | Midway between A and C |
| Answer» C. At C | |
| 10. |
What will be the equation of ILD of shear force at point C for CB part? |
| A. | 0.75 – 0.375X |
| B. | 0.75 – 0.475X |
| C. | 0.85 – 0.375X |
| D. | 0.75 – 0.1375X |
| Answer» D. 0.75 ‚Äö√Ñ√∂‚àö√ë‚àö¬® 0.1375X | |
| 11. |
If on ILD analysis peak force comes out to be 2 KN, then what will be the peak force if loading is 2KN? |
| A. | 1 KN |
| B. | 2 KN |
| C. | 3 KN |
| D. | 4 KN |
| Answer» B. 2 KN | |