 
			 
			MCQOPTIONS
 Saved Bookmarks
				This section includes 14 Mcqs, each offering curated multiple-choice questions to sharpen your Network Theory knowledge and support exam preparation. Choose a topic below to get started.
| 1. | The angle between resistance and impedance in the circuit shown below. | 
| A. | tan-11/ωRC | 
| B. | tan-1C/ωR | 
| C. | tan-1R/ωC | 
| D. | tan-1ωRC | 
| Answer» B. tan-1C/ωR | |
| 2. | The magnitude of the impedance of the circuit shown below is? | 
| A. | √(R+1/ωC) | 
| B. | √(R-1/ωC) | 
| C. | √(R2+(1/ωC)2) | 
| D. | √(R2-(1/ωC)2) | 
| Answer» D. √(R2-(1/ωC)2) | |
| 3. | The phase angle between current and voltage in the circuit shown below is? | 
| A. | tan-1ωL/R | 
| B. | tan-1ωR/ | 
| C. | tan-1R/ωL | 
| D. | tan-1L/ωR | 
| Answer» B. tan-1ωR/ | |
| 4. | What is the magnitude of the impedance of the following circuit? | 
| A. | √(R+ωL) | 
| B. | √(R-ωL) | 
| C. | √(R2+(ωL)2) | 
| D. | √(R2-(ωL)2) | 
| Answer» D. √(R2-(ωL)2) | |
| 5. | The current i(t) in the circuit shown below is? | 
| A. | i(t)=(Vm/(R-jωL))etjω | 
| B. | i(t)=(Vm(R+jωL)) etjω | 
| C. | i(t)=(Vm(R-jωL)) etjω | 
| D. | i(t)=(Vm/(R+jωL)) etjω | 
| Answer» E. | |
| 6. | The voltage function v(t) in the circuit shown below is? | 
| A. | v(t) = Vm e-tjω | 
| B. | v(t) = Vmetjω | 
| C. | v(t) = etjω | 
| D. | v(t) = e-tjω | 
| Answer» C. v(t) = etjω | |
| 7. | Impedance is a complex quantity having the real part as _______ and the imaginary part as ______ | 
| A. | resistance, resistance | 
| B. | resistance, reactance | 
| C. | reactance, resistance | 
| D. | reactance, reactance | 
| Answer» C. reactance, resistance | |
| 8. | THE_MAGNITUDE_OF_THE_IMPEDANCE_OF_THE_CIRCUIT_SHOWN_ABOVE_IS??$ | 
| A. | √(R+1/ωC) | 
| B. | √(R-1/ωC) | 
| C. | √(R<sup>2</sup>+(1/ωC)<sup>2</sup> ) | 
| D. | √(R<sup>2</sup>-(1/ωC)<sup>2</sup> ) | 
| Answer» D. ‚Äö√Ñ√∂‚àö‚Ć‚àö‚àÇ(R<sup>2</sup>-(1/‚âà√¨‚àö¬¢C)<sup>2</sup> ) | |
| 9. | The angle between resistance and impedance in the circuit shown above.$ | 
| A. | tan<sup>-1</sup>1/ωRC | 
| B. | tan<sup>-1</sup>⁡C/ωR | 
| C. | tan<sup>-1</sup>⁡R/ωC | 
| D. | tan<sup>-1</sup>⁡ωRC | 
| Answer» B. tan<sup>-1</sup>‚Äö√Ñ√∂‚àö√ñ¬¨‚àûC/‚âà√¨‚àö¬¢R | |
| 10. | The phase angle between current and voltage in the circuit shown above is? | 
| A. | tan<sup>-1</sup>⁡ωL/R | 
| B. | tan<sup>-1</sup>⁡ωR/ | 
| C. | tan<sup>-1</sup>⁡R/ωL | 
| D. | tan<sup>-1</sup>⁡L/ωR | 
| Answer» B. tan<sup>-1</sup>‚Äö√Ñ√∂‚àö√ñ¬¨‚àû‚âà√¨‚àö¬¢R/ | |
| 11. | The magnitude of the impedance of the circuit shown above. | 
| A. | √( R+ωL) | 
| B. | √(R-ωL) | 
| C. | √(R<sup>2</sup>+(ωL)<sup>2</sup> ) | 
| D. | √(R<sup>2</sup>-(ωL)<sup>2</sup> ) | 
| Answer» D. ‚Äö√Ñ√∂‚àö‚Ć‚àö‚àÇ(R<sup>2</sup>-(‚âà√¨‚àö¬¢L)<sup>2</sup> ) | |
| 12. | The impedance of the circuit shown below is? | 
| A. | R + jωL | 
| B. | R – jωL | 
| C. | R + 1/jωL | 
| D. | R – 1/jωL | 
| Answer» B. R ‚Äö√Ñ√∂‚àö√ë‚àö¬® j‚âà√¨‚àö¬¢L | |
| 13. | The current i(t) in the circuit shown above is? | 
| A. | i(t)=(V<sub>m</sub>/(R-jωL))e<sup>tjω</sup> | 
| B. | i(t)=(V<sub>m</sub>(R+jωL)) e<sup>tjω</sup> | 
| C. | i(t)=(V<sub>m</sub>(R-jωL)) e<sup>tjω</sup> | 
| D. | i(t)=(V<sub>m</sub>/(R+jωL)) e<sup>tjω</sup> | 
| Answer» E. | |
| 14. | Impedance is a complex quantity having the real part as _______ and the imaginary part as ______ | 
| A. | resistance, resistance | 
| B. | resistance, reactance | 
| C. | reactance, resistance | 
| D. | reactance, reactance | 
| Answer» C. reactance, resistance | |