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This section includes 13 Mcqs, each offering curated multiple-choice questions to sharpen your Mathematics knowledge and support exam preparation. Choose a topic below to get started.
1. |
Find the value of (98)2 – (2)2. |
A. | 9600 |
B. | 960 |
C. | 96000 |
D. | 900 |
Answer» B. 960 | |
2. |
Find the value of (10001 + 12)(10001 – 12). |
A. | 1000190857 |
B. | 1000019857 |
C. | 10019857 |
D. | 100019857 |
Answer» E. | |
3. |
Calculate the value of 904 × 902. |
A. | 815408 |
B. | 8105408 |
C. | 810548d) 81548 |
D. | 81548d) 815400 |
Answer» B. 8105408 | |
4. |
Using the standard identity, find the value of 201 × 204. |
A. | 4104 |
B. | 401004 |
C. | 40104 |
D. | 41004 |
Answer» E. | |
5. |
Evaluate the value (x + 12)(x + 1). |
A. | x2 + 13x – 13 |
B. | x2 + 13x + 13 |
C. | x2 + 13x – 12 |
D. | x2 + 13x + 12 |
Answer» E. | |
6. |
Using the standard identity, find the value of (2m + 2)(2m + 3). |
A. | 4m2 + 10m + 5 |
B. | 4m2 + 10m + 6 |
C. | 4m2 + 10m – 6 |
D. | 4m2 + 10m – 5 |
Answer» C. 4m2 + 10m – 6 | |
7. |
Find the value of (12.4)2. |
A. | 152.77 |
B. | 153.66 |
C. | 153.76 |
D. | 152.76 |
Answer» D. 152.76 | |
8. |
Using the standard identity, find the value of (3.9)2. |
A. | 15.11 |
B. | 16.11 |
C. | 15.21 |
D. | 16.21 |
Answer» D. 16.21 | |
9. |
Evaluate the value of (2q – 3p)2. |
A. | 4q2 + 9p2 + 12pq |
B. | 4q2 + 9p2 – 12pq |
C. | 4q2 + 9p2 + 6pq |
D. | 4q2 + 9p2 – 6pq |
Answer» C. 4q2 + 9p2 + 6pq | |
10. |
Calculate the value of (11x – 2y)2. |
A. | 121x2 + 4y2 – 22xy |
B. | 121x2 + 4y2 – 44xy |
C. | 121x2 + 4y2 + 44xy |
D. | 121x2 + 4y2 + 22xy |
Answer» C. 121x2 + 4y2 + 44xy | |
11. |
Find the value of (m + 4n)2 using the standard identity. |
A. | m2 + 4n2 – 8mn |
B. | m2 + 16n2 + 4mn |
C. | m2 + 16n2 + 8mn |
D. | m2 + 4n2 + 8mn |
Answer» D. m2 + 4n2 + 8mn | |
12. |
Find the value of (2a + 1)2 using standard identity. |
A. | 4a2 + 2 + 2a |
B. | 4a2 + 2 – 4a |
C. | 4a2 – 2 + 4a |
D. | 4a2 + 2 + 4a |
Answer» E. | |
13. |
Select the term which is not an identity. |
A. | (a + b)2 = a2 + b2b) (a + b)2 = a2 + b2 + 2abc) (a – |
B. | 2 = a2 + b2b) (a + b)2 = a2 + b2 + 2ab |
C. | (a – b)2 = a2 + b2 – 2ab |
D. | (a + 1)(a + 2) = a2 + 3a + 2 |
Answer» B. 2 = a2 + b2b) (a + b)2 = a2 + b2 + 2ab | |