MCQOPTIONS
Saved Bookmarks
MCQOPTIONS
This section includes 14 Mcqs, each offering curated multiple-choice questions to sharpen your Electronic Devices Circuits knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
What are the units of slew rate? |
| A. | Second/Volt |
| B. | Volt/second |
| C. | It is a ratio, no units |
| D. | Ohm/second |
| Answer» C. It is a ratio, no units | |
| 2. |
For an ideal operational amplifier (except for the fact that it has finite gain) one set of the value for the input voltages (v2 is the positive terminal v1 is the negative terminal) and output voltage (v0) as determined experimentally is v1= 2.01V, v2=2.00V and v0= -0.99V. Experiment was carried with different values of input and output voltages. Which of the following is not possible considering experimental error? |
| A. | v1= 1.99V, v2= 2.00V, v0 = 1.00V |
| B. | v1= 1.00V, v2= 1.00V, v0 = 0V |
| C. | v1= 1.00V, v2= 1.10V, v0 = 10.1V |
| D. | v1= 0.99V, v2= 2.00V, v0 = 1.00V |
| Answer» E. | |
| 3. |
Express the input voltages v1 and v2 in terms of differential input (vd) and common-mode input(vc). Given v2 > v2. |
| A. | Vd = V1 – V2, Vc = 0.5(V1 + V2) |
| B. | Vd = V2 – V1, Vc = V1 + V2 |
| C. | . Given v2 > v2.a) Vd = V1 – V2, Vc = 0.5(V1 + V2)b) Vd = V2 – V1, Vc = V1 + V2c) Vd = V1 – V2, Vc = V1 + V2 |
| D. | and common-mode input(vc). Given v2 > v2.a) Vd = V1 – V2, Vc = 0.5(V1 + V2)b) Vd = V2 – V1, Vc = V1 + V2c) Vd = V1 – V2, Vc = V1 + V2d) Vd = V2 – V1, Vc = 0.5(V1 + V2) |
| Answer» E. | |
| 4. |
Consider the figure given below. Known that vo = 4V and vi = 2V, determine the gain for the op amp assuming that it is ideal except for the fact that it has finite gain |
| A. | 1001 |
| B. | 2002 |
| C. | 3003 |
| D. | 4004 |
| Answer» C. 3003 | |
| 5. |
In an ideal op amp the open-loop gain is 103. The op amp is used in a feedback circuit, and the voltages appearing at two of its three signal terminals are measured as v2 = 0V and v3 = 2V where it is assumed that v1 and v2 are input terminals and v3 is the output terminal. The value of the differential (vd) and common-mode (vcm)signal is |
| A. | Vd = 2 mV and vcm = 1 mv |
| B. | Vd = 2 mV and vcm = -1 mV |
| C. | Vd = 2 mV and vcm = 2mV |
| D. | and common-mode (vcm)signal isa) Vd = 2 mV and vcm = 1 mvb) Vd = 2 mV and vcm = -1 mVc) Vd = 2 mV and vcm = 2mVd) Vd = 2 mV and vcm = -2mV |
| Answer» C. Vd = 2 mV and vcm = 2mV | |
| 6. |
FOR_AN_IDEAL_OPERATIONAL_AMPLIFIER_(EXCEPT_FOR_THE_FACT_THAT_IT_HAS_FINITE_GAIN)_ONE_SET_OF_THE_VALUE_FOR_THE_INPUT_VOLTAGES_(V2_IS_THE_POSITIVE_TERMINAL_V1_IS_THE_NEGATIVE_TERMINAL)_AND_OUTPUT_VOLTAGE_(V0)_AS_DETERMINED_EXPERIMENTALLY_IS_V1=_2.01V,_V2=2.00V_AND_V0=_-0.99V._EXPERIMENT_WAS_CARRIED_WITH_DIFFERENT_VALUES_OF_INPUT_AND_OUTPUT_VOLTAGES._WHICH_OF_THE_FOLLOWING_IS_NOT_POSSIBLE_CONSIDERING_EXPERIMENTAL_ERROR??$ |
| A. | v<sub>1</sub>= 1.99V, v<sub>2</sub>= 2.00V, v<sub>0</sub> = 1.00V |
| B. | v<sub>1</sub>= 1.00V, v<sub>2</sub>= 1.00V, v<sub>0</sub> = 0V |
| C. | v<sub>1</sub>= 1.00V, v<sub>2</sub>= 1.10V, v<sub>0</sub> = 10.1V |
| D. | v<sub>1</sub>= 0.99V, v<sub>2</sub>= 2.00V, v<sub>0</sub> = 1.00V |
| Answer» E. | |
| 7. |
What_are_the_units_of_slew_rate?$ |
| A. | Second/Volt |
| B. | Volt/second |
| C. | It is a ratio, no units |
| D. | Ohm/second |
| Answer» C. It is a ratio, no units | |
| 8. |
What is the minimum number of pins for a dual operational amplifier IC package? |
| A. | 4 |
| B. | 6 |
| C. | 8 |
| D. | 10 |
| Answer» D. 10 | |
| 9. |
Express the input voltages v1 and v2 in terms of differential input (vd) and common-mode input(vc). Given v2 > v2. |
| A. | V<sub>d</sub> = V<sub>1</sub> – V<sub>2</sub>, V<sub>c</sub> = 0.5(V<sub>1</sub> + V<sub>2</sub>) |
| B. | V<sub>d</sub> = V<sub>2</sub> – V<sub>1</sub>, V<sub>c</sub> = V<sub>1</sub> + V<sub>2</sub> |
| C. | V<sub>d</sub> = V<sub>1</sub> – V<sub>2</sub>, V<sub>c</sub> = V<sub>1</sub> + V<sub>2</sub> |
| D. | V<sub>d</sub> = V<sub>2</sub> – V<sub>1</sub>, V<sub>c</sub> = 0.5(V<sub>1</sub> + V<sub>2</sub>) |
| Answer» E. | |
| 10. |
Operational amplifiers are |
| A. | Differential input and single-ended output type amplifier |
| B. | Single-ended input and single-ended output type amplifier |
| C. | Single-ended input and differential output type amplifier |
| D. | Differential input and differential output type amplifier |
| Answer» B. Single-ended input and single-ended output type amplifier | |
| 11. |
Which of the following is not a terminal for the operational amplifier? |
| A. | Inverting terminal |
| B. | Non-inverting terminal |
| C. | Output terminal |
| D. | None of the mentioned |
| Answer» E. | |
| 12. |
In an ideal op amp the open-loop gain is 103. The op amp is used in a feedback circuit, and the voltages appearing at two of its three signal terminals are measured as v2 = 0V and v3 = 2V where it is assumed that v1 and v2 are input terminals and v3 is the output terminal. The value of the differential (vd) and common-mode (vcm)signal is |
| A. | V<sub>d</sub> = 2 mV and v<sub>cm</sub> = 1 mv |
| B. | V<sub>d</sub> = 2 mV and v<sub>cm</sub> = -1 mV |
| C. | V<sub>d</sub> = 2 mV and v<sub>cm</sub> = 2mV |
| D. | V<sub>d</sub> = 2 mV and v<sub>cm</sub> = -2mV |
| Answer» C. V<sub>d</sub> = 2 mV and v<sub>cm</sub> = 2mV | |
| 13. |
Which of the following is not a property of an ideal operational amplifier? |
| A. | Zero input impedance |
| B. | Infinite bandwidth |
| C. | Infinite open loop gain |
| D. | Zero common-mode gain or conversely infinite common mode-rejection. |
| Answer» B. Infinite bandwidth | |
| 14. |
What is the minimum number of terminals required in an IC package containing four operational amplifiers (quad op amps)? |
| A. | 12 |
| B. | 13 |
| C. | 14 |
| D. | 15 |
| Answer» D. 15 | |