MCQOPTIONS
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MCQOPTIONS
This section includes 5314 Mcqs, each offering curated multiple-choice questions to sharpen your Chemical Engineering knowledge and support exam preparation. Choose a topic below to get started.
| 551. |
The permanent hardness in water is due to the presence of __________ |
| A. | Sulfates, Chlorides |
| B. | Sulfates, chlorides, nitrates |
| C. | Carbonates and bicarbonates |
| D. | Sulfates and carbonates |
| Answer» C. Carbonates and bicarbonates | |
| 552. |
The total hardness of water is 100ppm as CaCO3 equivalent. What is the type of water? |
| A. | Soft |
| B. | Moderately hard |
| C. | Hard |
| D. | Very hard |
| Answer» C. Hard | |
| 553. |
The Total hardness of soft water as CaCO3 equivalent is __________ |
| A. | 50ppm |
| B. | 100ppm |
| C. | 150ppm |
| D. | 200ppm |
| Answer» B. 100ppm | |
| 554. |
What will be the Total Organic Carbon (TOC) of coloured water? |
| A. | 100-200ppm |
| B. | 100ppm |
| C. | 200ppm |
| D. | 200-300 ppm |
| Answer» B. 100ppm | |
| 555. |
Colour is contributed to which of the following? |
| A. | Natural organic matter |
| B. | Inorganic compounds |
| C. | Total dissolved solids |
| D. | Suspended solids |
| Answer» B. Inorganic compounds | |
| 556. |
How is TDS and conductivity related? |
| A. | TDS = 0.5 conductivity |
| B. | Conductivity= 0.5 TDS |
| C. | TDS=3 Conductivity |
| D. | TDS=Conductivity |
| Answer» B. Conductivity= 0.5 TDS | |
| 557. |
Turbidity in water is caused by which of these following? |
| A. | Total dissolved solids |
| B. | Suspended solids |
| C. | Ions |
| D. | Heavy metals |
| Answer» C. Ions | |
| 558. |
Sea foods are the major source of bio-accumulation in humans. |
| A. | True |
| B. | False |
| Answer» B. False | |
| 559. |
The type of environmental pollutants that remain in the environment for a long time period is called as short-lived pollutant. |
| A. | True |
| B. | False |
| Answer» C. | |
| 560. |
The type of environmental pollutants that remain in the environment for a long time period is called as Persistent pollutant. |
| A. | True |
| B. | False |
| Answer» B. False | |
| 561. |
Bio accumulation is the concentration of pollutant across the food chain. |
| A. | True |
| B. | False |
| Answer» C. | |
| 562. |
The harmful toxic compounds get accumulated within the first organism in the ___________ |
| A. | Gypsum |
| B. | Food chain |
| C. | Xenoestrogen |
| D. | Oxalic acid |
| Answer» C. Xenoestrogen | |
| 563. |
The harmful toxic compounds from the environment gets deposited in an organism within _____________ |
| A. | Trophic level |
| B. | Parabens |
| C. | Oxygen |
| D. | Nitrogen |
| Answer» B. Parabens | |
| 564. |
Which of the following is the source through which toxic chemicals enter the organism’s body? |
| A. | Contaminated air |
| B. | Contaminated water |
| C. | Contaminated food |
| D. | Sterile water |
| Answer» E. | |
| 565. |
What is the following step is not included in the bio accumulation process? |
| A. | Storage |
| B. | Elimination |
| C. | Uptake |
| D. | Filtration |
| Answer» E. | |
| 566. |
What happens when toxins gets accumulated inside the body of an organism? |
| A. | Bilirubin poisoning |
| B. | Steroids poisoning |
| C. | Bile salts poisoning |
| D. | Chronic poisoning |
| Answer» E. | |
| 567. |
What type of chemicals get accumulated in an organism during bio-accumulation process? |
| A. | Pesticides or organic chemicals |
| B. | Sodium |
| C. | Fe |
| D. | Potassium |
| Answer» B. Sodium | |
| 568. |
The organism is at a risk if the amount of toxin being absorbed is more than that being excreted out of the body. |
| A. | True |
| B. | False |
| Answer» B. False | |
| 569. |
The process of building up of harmful chemicals inside a living organism is called as _______ |
| A. | Bio-accumulation |
| B. | Bio-leaching |
| C. | Bio-remediation |
| D. | Bio-fortification |
| Answer» B. Bio-leaching | |
| 570. |
An 8microF capacitor is connected in series with a 0.5 megaohm resistor. The DC voltage supply is 200V. Calculate the current in the capacitor 4s after the power is supplied. |
| A. | 79 microA |
| B. | 68 microA |
| C. | 48 microA |
| D. | 74 microA |
| Answer» E. | |
| 571. |
A 8 microF capacitor is connected in series with a 0.5 megaohm resistor. The DC voltage supply is 200V. Calculate the time taken for the potential difference across the capacitor to grow to 160V. |
| A. | 6.93s |
| B. | 7.77s |
| C. | 2.33s |
| D. | 3.22s |
| Answer» B. 7.77s | |
| 572. |
An 8microF capacitor is connected in series with a 0.5 megaohm resistor. The DC voltage supply is 200V. Calculate the time constant. |
| A. | 1s |
| B. | 2s |
| C. | 3s |
| D. | 4s |
| Answer» E. | |
| 573. |
The aircraft is symmetrical flight during the derivation of equations of motion. |
| A. | True |
| B. | False |
| Answer» B. False | |
| 574. |
What is the function of excess thrust in longitudinal equations of motion? |
| A. | Decrease the potential energy and kinetic energy |
| B. | Increase the potential energy and kinetic energy |
| C. | Decrease the potential energy and increase kinetic energy |
| D. | Increase the potential energy and decrease kinetic energy |
| Answer» C. Decrease the potential energy and increase kinetic energy | |
| 575. |
If the aircraft has a power-producing engine which have driven propellers then the power is to be converted to thrust to formulate the equations of motion. |
| A. | True |
| B. | False |
| Answer» B. False | |
| 576. |
Excess thrust in the longitudinal equations of motion is given by ____________ |
| A. | FN+D |
| B. | FN-D |
| C. | D-FN |
| D. | FN*D |
| Answer» C. D-FN | |
| 577. |
In static performance the acceleration of the flight is zero. |
| A. | True |
| B. | False |
| Answer» B. False | |
| 578. |
The total thrust force assumed in the derivation of equations of motion is ___________ |
| A. | FN=T cosα+DM |
| B. | FN=T cosα-DM |
| C. | T cosα=DM-FN |
| D. | DM=T cosα+FN |
| Answer» C. T cosα=DM-FN | |
| 579. |
Which of the following is not the additional assumption taken in the derivation of the equations of motion? |
| A. | Gross thrust acts in aircraft body axis |
| B. | Thrust component is small compared to lift component |
| C. | Aircraft is in symmetric flight |
| D. | Rate of change of mass is neglected |
| Answer» D. Rate of change of mass is neglected | |
| 580. |
What is the basic assumption taken in formulating equations of motion? |
| A. | All the engines will operate at equal gross thrust |
| B. | All the engines do not operate at equal gross thrust |
| C. | All the engines will operate at equal gross drag |
| D. | All the engines do not operate at equal gross drag |
| Answer» B. All the engines do not operate at equal gross thrust | |
| 581. |
The system of forces acting on the aircraft are propulsive forces, aerodynamic forces, gravitational forces and these result in inertial forces. |
| A. | True |
| B. | False |
| Answer» B. False | |
| 582. |
Which of the following is a correct equation? |
| A. | Fa+Fp+Fg=Fl |
| B. | Fa+Fp+Fg=Fl |
| C. | Fa+Fp+Fg=Fl |
| D. | Fa+Fp+Fg=Fl |
| Answer» B. Fa+Fp+Fg=Fl | |
| 583. |
___________ is used for writing blocks with single replica in memory. |
| A. | Hot |
| B. | Lazy_Persist |
| C. | One_SSD |
| D. | All_SSD |
| Answer» C. One_SSD | |
| 584. |
____________ is used for storing one of the replicas in SSD. |
| A. | Hot |
| B. | Lazy_Persist |
| C. | One_SSD |
| D. | All_SSD |
| Answer» D. All_SSD | |
| 585. |
When a block is warm, some of its replicas are stored in DISK and the remaining replicas are stored in _________ |
| A. | ROM_DISK |
| B. | ARCHIVE |
| C. | RAM_DISK |
| D. | All of the mentioned |
| Answer» C. RAM_DISK | |
| 586. |
Which of the following is only for storage with limited compute? |
| A. | Hot |
| B. | Cold |
| C. | Warm |
| D. | All_SSD |
| Answer» C. Warm | |
| 587. |
Which of the following storage policy is used for both storage and compute? |
| A. | Hot |
| B. | Cold |
| C. | Warm |
| D. | All_SSD |
| Answer» B. Cold | |
| 588. |
Which of the following has high storage density? |
| A. | ROM_DISK |
| B. | ARCHIVE |
| C. | RAM_DISK |
| D. | All of the mentioned |
| Answer» C. RAM_DISK | |
| 589. |
__________ storage is a solution to decouple growing storage capacity from compute capacity. |
| A. | DataNode |
| B. | Archival |
| C. | Policy |
| D. | None of the mentioned |
| Answer» C. Policy | |
| 590. |
Non-zero-dispersion-shifted fiber was introduced in the year 2000. |
| A. | True |
| B. | False |
| Answer» C. | |
| 591. |
The variant of non-zero-dispersion-shifted fiber is called as __________ |
| A. | Dispersion flattened fiber |
| B. | Zero-dispersion fiber |
| C. | Positive-dispersion fiber |
| D. | Negative-dispersion fiber |
| Answer» E. | |
| 592. |
Any amount of stress occurring at the core-cladding interface would be reduced by grading the material composition. |
| A. | True |
| B. | False |
| Answer» B. False | |
| 593. |
For suitable power confinement of fundamental mode, the normalized frequency v should be maintained in the range 1.5 to 2.4μm and the fractional index difference must be linearly increased as a square function while the core diameter is linearly reduced to keep v constant. This confinement is achieved by? |
| A. | Increasing level of silica doping in fiber core |
| B. | Increasing level of germanium doping in fiber core |
| C. | Decreasing level of silica germanium in fiber core |
| D. | Decreasing level of silica doping in fiber core |
| Answer» C. Decreasing level of silica germanium in fiber core | |
| 594. |
The fibers which relax the spectral requirements for optical sources and allow flexible wavelength division multiplying are known as __________ |
| A. | Dispersion-flattened single mode fiber |
| B. | Dispersion-enhanced single mode fiber |
| C. | Dispersion-compressed single mode fiber |
| D. | Dispersion-standardized single mode fiber |
| Answer» B. Dispersion-enhanced single mode fiber | |
| 595. |
An alternative modification of the dispersion characteristics of single mode fibers involves achievement of low dispersion gap over the low-loss wavelength region between __________ |
| A. | 0.2 and 0.9μm |
| B. | 0.1 and 0.2μm |
| C. | 1.3 and 1.6μm |
| D. | 2 and 3μm |
| Answer» D. 2 and 3μm | |
| 596. |
Dispersion-shifted single mode fibers are created by __________ |
| A. | Increasing fiber core diameter and decreasing fractional index difference |
| B. | Decreasing fiber core diameter and decreasing fractional index difference |
| C. | Decreasing fiber core diameter and increasing fractional index difference |
| D. | Increasing fiber core diameter and increasing fractional index difference |
| Answer» D. Increasing fiber core diameter and increasing fractional index difference | |
| 597. |
The dispersion due to material, waveguide and profile are -2.8nm-1km-1, 20.1nm-1km-1 and 23.2nm-1km-1respectively. Find the total first order dispersion? |
| A. | 36.2psnm-1 km-1 |
| B. | 38.12psnm-1 km-1 |
| C. | 40.5psnm-1 km-1 |
| D. | 20.9psnm-1 km-1 |
| Answer» D. 20.9psnm-1 km-1 | |
| 598. |
A single mode fiber has a zero dispersion wavelength of 1.21μm and a dispersion slope of 0.08 psnm-2km-1. What is the total first order dispersion at wavelength 1.26μm. |
| A. | -2.8psnm-1 km-1 |
| B. | -3.76psnm-1 km-1 |
| C. | -1.2psnm-1 km-1 |
| D. | 2.4psnm-1 km-1 |
| Answer» C. -1.2psnm-1 km-1 | |
| 599. |
Most of the power in an optical fiber is transmitted in fiber cladding. |
| A. | True |
| B. | False |
| Answer» C. | |
| 600. |
Γg = dβ / C*dk. What is β in the given equation? |
| A. | Attenuation constant |
| B. | Propagation constant |
| C. | Boltzmann’s constant |
| D. | Free-space |
| Answer» C. Boltzmann’s constant | |