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This section includes 8 Mcqs, each offering curated multiple-choice questions to sharpen your Linear Integrated Circuit knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
TO_CHANGE_THE_HIGH_CUTOFF_FREQUENCY_OF_A_FILTER._IT_IS_MULTIPLIED_BY_R_OR_C_BY_A_RATIO_OF_ORIGINAL_CUT-OFF_FREQUENCY_KNOWN_AS?$ |
| A. | Gain scaling |
| B. | Frequency scaling |
| C. | Magnitude scaling |
| D. | Phase scaling |
| Answer» C. Magnitude scaling | |
| 2. |
Find the difference in gain magnitude for a filter ,if it is the response obtained for frequencies f1=200Hz and f2=3kHz. Specification: AF=2 and fH=1kHz.$ |
| A. | 4.28 dB |
| B. | 5.85 dB |
| C. | 1.56 dB |
| D. | None of the mentioned |
| Answer» B. 5.85 dB | |
| 3. |
Using_the_frequency_scaling_technique,_convert_10kHz_cut-off_frequency_of_the_low_pass_filter_to_a_cutoff_frequency_of_16kHz.(Take_C=0.01µF_and_R=15.9kΩ)$# |
| A. | 6.25kΩ |
| B. | 9.94kΩ |
| C. | 16kΩ |
| D. | 1.59kΩ |
| Answer» D. 1.59k‚âà√≠¬¨¬© | |
| 4. |
Find the High cut-off frequency if the pass band gain of a filter is 10? |
| A. | 70.7Hz |
| B. | 7.07kHz |
| C. | 7.07Hz |
| D. | 707Hz |
| Answer» C. 7.07Hz | |
| 5. |
In a low pass butterworth filter, the condition at which f=fH is called |
| A. | Cut-off frequency |
| B. | Break frequency |
| C. | Corner frequency |
| D. | All of the mentioned |
| Answer» D. All of the mentioned | |
| 6. |
Determine the gain of the first order low pass filter if the phase angle is 59.77o and the pass band gain is 7. |
| A. | 3.5 |
| B. | 7 |
| C. | 12 |
| D. | 1.71 |
| Answer» E. | |
| 7. |
1-i,2-ii,3-iii |
| A. | 1-ii,2-iii,3-i |
| B. | 1-iii,2-ii,3-i |
| C. | 1-iii,2-i,3-ii |
| Answer» B. 1-iii,2-ii,3-i | |
| 8. |
Find the complex equation for the gain of the first order low pass butterworth filter as a function of frequency. |
| A. | A<sub>F</sub>/[1+j(f/f<sub>H</sub>)]. |
| B. | A<sub>F</sub>/‚àö [1+j(f/f<sub>H</sub>)<sup>2</sup>]. |
| C. | A<sub>F</sub>√ó[1+j(f/f<sub>H</sub>)]. |
| D. | None of the mentioned |
| Answer» B. A<sub>F</sub>/‚Äö√Ñ√∂‚àö‚Ć‚àö‚àÇ [1+j(f/f<sub>H</sub>)<sup>2</sup>]. | |