MCQOPTIONS
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MCQOPTIONS
This section includes 15 Mcqs, each offering curated multiple-choice questions to sharpen your Surveying knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
If the radii of the curves in a reverse curve are equal, calculate the distance between the tangent points T1 and T2. Assume R = 98.54m with deflection angle 54˚31ꞌ. |
| A. | 108.52m |
| B. | 180.52m |
| C. | 180.25m |
| D. | 108.25m |
| Answer» C. 180.25m | |
| 2. |
Calculate the chainage of P.R.C, if the chainage of Tangent is 567.54m and the curve length is about 65m. |
| A. | 623.54m |
| B. | 632.45m |
| C. | 362.54m |
| D. | 632.54m |
| Answer» E. | |
| 3. |
Find the value of tangent distance, possessing radius of curvature as 24.89m, common tangent 65m length and having deflection angles as 24˚56ꞌ and 76˚32ꞌ. |
| A. | 64.5m |
| B. | 46.5m |
| C. | 64.98m |
| D. | 62.5m |
| Answer» B. 46.5m | |
| 4. |
Determine the common tangent of a reverse curve if the radius of curvature and deflection angles is given as, 43.57m, 32˚43ꞌ and 65˚76ꞌ. |
| A. | 217.087m |
| B. | 127.087m |
| C. | 127.807m |
| D. | 127.708m |
| Answer» C. 127.807m | |
| 5. |
Calculate the short tangent length, if the radius of curvature is given as 56.21m and the deflection angle as 32˚54ꞌ. |
| A. | 61.6m |
| B. | 116.6m |
| C. | 16.6m |
| D. | 6.6m |
| Answer» D. 6.6m | |
| 6. |
The formula of length of tangent is given as___________ |
| A. | t = L tan(δ/2) |
| B. | t = r – tan(δ/2) |
| C. | t = r + tan(δ/2) |
| D. | t = r * tan(δ/2) |
| Answer» E. | |
| 7. |
In case of parallel straights, the length of the curve is given as__________ |
| A. | L = (2(R1+R2)V)1/2 |
| B. | L = 2L(R1+R2) / V |
| C. | L = 2V(R1-R2) / R |
| D. | L = 2V(R1*R2) / R |
| Answer» B. L = 2L(R1+R2) / V | |
| 8. |
Which of the following indicates the correct set of the cases employed in reverse curves? |
| A. | Perpendicular, non-parallel |
| B. | Parallel, perpendicular |
| C. | Non-parallel, parallel |
| D. | Perpendicular, curved |
| Answer» D. Perpendicular, curved | |
| 9. |
A Reverse curve can be set by which of the following methods? |
| A. | Method of bisection of arcs |
| B. | Method of deflection angles |
| C. | Method of deflection distances |
| D. | Method of tangential angles |
| Answer» E. | |
| 10. |
Chainage at the point of reverse curve can be given as__________ |
| A. | Chainage at P.R.C = Chainage at P.C + length of first arc |
| B. | Chainage at P.R.C = Chainage at P.I + length of first arc |
| C. | Chainage at P.R.C = Chainage at P.C + length of second arc |
| D. | Chainage at P.R.C = Chainage at P.C – length of first arc |
| Answer» B. Chainage at P.R.C = Chainage at P.I + length of first arc | |
| 11. |
Which of the following case is assumed in a reverse curve? |
| A. | Δ = Δ1 * Δ2 |
| B. | Δ = Δ2 – Δ1 |
| C. | Δ = Δ1 – Δ2 |
| D. | Δ = Δ1 + Δ2 |
| Answer» D. Δ = Δ1 + Δ2 | |
| 12. |
Which of the following cases is generally adopted in the reverse curve? |
| A. | T1 = T2 |
| B. | R1 = R2 |
| C. | t1 = t2 |
| D. | Chainages are equal |
| Answer» C. t1 = t2 | |
| 13. |
Which of the following curves is not used in case highways? |
| A. | Simple curve |
| B. | Compound curve |
| C. | Transition curve |
| D. | Reverse curve |
| Answer» E. | |
| 14. |
Which of the following provides the best case for setting the reverse curve? |
| A. | When straights are perpendicular |
| B. | When straights form arc |
| C. | When straights are parallel |
| D. | When straights form curves |
| Answer» D. When straights form curves | |
| 15. |
Reverse curve is a combination of two simple curves. |
| A. | True |
| B. | False |
| Answer» B. False | |