Explore topic-wise MCQs in Mechanical Metallurgy.

This section includes 10 Mcqs, each offering curated multiple-choice questions to sharpen your Mechanical Metallurgy knowledge and support exam preparation. Choose a topic below to get started.

1.

A uniform cylinder of length L is compressed to half of its original length. Calculate true strain and engineering strain for the cylinder.

A. Engineering strain = 1, True strain = 0.69
B. Engineering strain = 0.5, True strain = 0.69
C. Engineering strain = -0.5, True strain = -0.69
D. Engineering strain = -1, True strain = -0.69
Answer» D. Engineering strain = -1, True strain = -0.69
Discussion
2.

A tensile specimen of 6 mm diameter and gauge length 25 mm reached a maximum load of 45 kN and fractured at 35 kN. The maximum diameter at fracture is 5mm. Determine the true stress at the fracture point.

A. 445 MPa
B. 371.13 MPa
C. 398 MPa
D. 518.87 MPa
Answer» E.
Discussion
3.

A tensile specimen of 6 mm diameter and gauge length 25 mm reached a maximum load of 45 kN and fractured at 35 kN. The maximum diameter at fracture is 5mm. Determine the engineering stress at maximum load (Ultimate tensile strength).

A. 796 MPa
B. 398 MPa
C. 512 MPa
D. 52 MPa
Answer» C. 512 MPa
Discussion
4.

What is the relationship between engineering stress and true stress?Given that; s = engineering stress, σ = true stress, e = engineering strain, ε = true strain.

A. σ = s(e+1)
B. σ = ln(s)
C. σ = ln[s(e+1)]
D. σ = se+1
Answer» B. σ = ln(s)
Discussion
5.

For perfectly plastic material, Poisson’s ratio is equal to ________

A. 1
B. 0.5
C. 0.33
D. 0
Answer» C. 0.33
Discussion
6.

The advantage of using true strain is that the total true strain is equal to the sum of the incremental strains.

A. True
B. False
Answer» B. False
Discussion
7.

A uniform cylinder of length L is elongated to twice of its original length. Calculate true strain and engineering strain for the cylinder in percentage?

A. Engineering strain=100%, True strain=69.31%
B. Engineering strain=69.31%, True strain=100%
C. Engineering strain=50%, True strain=50%
D. Engineering strain=50%, True strain=100%
Answer» B. Engineering strain=69.31%, True strain=100%
Discussion
8.

The relationship between the true strain and engineering strain is given as _____Where e=conventional strain, ε= Engineering strain

A. ε=e
B. ε=ln(e)
C. ε=ln(e+1)
D. ε=ln(1/(1+
E. ε=ln(e+1)d) ε=ln(1/(1+e))
Answer» D. ε=ln(1/(1+
Discussion
9.

The initial length of sample is Lo and instantaneous length of the sample is L. The true strain of the material will be equal to _________

A. L/Lo
B. Lo/L
C. ln{(L-Lo)/L}
D. ln{L/Lo}
Answer» E.
Discussion
10.

The engineering stress-strain curve does not give an accurate indication of the deformation characteristic of the material because it’s calculation is based on the original dimension of the specimen. These dimensions continuously change during the test.

A. True
B. False
Answer» B. False
Discussion