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This section includes 14 Mcqs, each offering curated multiple-choice questions to sharpen your Casting knowledge and support exam preparation. Choose a topic below to get started.
1. |
Gating design for a mould of 50cm*25cm*15cm is shown in below figure. The cross-sectional area of the gate is 5 cm2. Neglecting friction and velocity distribution effects, what is the filling time (t) for the design (in second)? |
A. | 19.25 |
B. | 21.86 |
C. | 34.21 |
D. | ?a) 19.25b) 21.86c) 34.21d) 10.39 |
Answer» C. 34.21 | |
2. |
Which of the following gating designs is used to avoid the splashing of the molten metal in the mould? |
A. | Vertical gating |
B. | Horizontal gating |
C. | Inclined gating |
D. | Bottom gating |
Answer» E. | |
3. |
In the given figure of Entry with rounded corner type of changes in flow geometry, the value of friction loss factor (eғ) is_____ |
A. | 0.33eғs |
B. | 0.5eғs |
C. | 2eғs |
D. | eғs |
Answer» B. 0.5eғs | |
4. |
Given figure below, shows a ladle having an internal diameter of 1 m with a capacity height of 1.2 m. It has a nozzle of 75 mm exit diameter. What is the mass flow rate in kg/sec?Take CD (Coefficient of discharge) = 0.96, ρ (Density of molten metal) = 2700 kg/m3 |
A. | 34.22 |
B. | 46.38 |
C. | 55.34 |
D. | 60.10 |
E. | = 0.96, ρ (Density of molten metal) = 2700 kg/m3 a) 34.22b) 46.38c) 55.34d) 60.10 |
Answer» D. 60.10 | |
5. |
Friction loss factor (eғ) in the conduit of liquid metal depends on _____ |
A. | temperature of the molten metal |
B. | presence of dross in the molten metal |
C. | ratio of the flow area and Reynolds no. of the flow |
D. | whirling of the molten metal |
Answer» D. whirling of the molten metal | |
6. |
Which_of_the_following_gating_designs_is_used_to_avoid_the_splashing_of_the_molten_metal_in_the_mould?$ |
A. | Vertical gating |
B. | Horizontal gating |
C. | Inclined gating |
D. | Bottom gating |
Answer» E. | |
7. |
Which of the following ways can use for stopping the rapid solidification of the molten metal in the mould? |
A. | By having the mould of high permeability |
B. | By making a uniform flow of molten metal |
C. | By creating high pressure on the molten metal |
D. | By using too much superheat |
Answer» E. | |
8. |
Friction loss factor (e“ì) in the conduit of liquid metal depends on _____$ |
A. | temperature of the molten metal |
B. | presence of dross in the molten metal |
C. | ratio of the flow area and Reynolds no. of the flow |
D. | whirling of the molten metal |
Answer» D. whirling of the molten metal | |
9. |
For a smooth conduit, which of the following is the value of friction factor (f) for laminar and turbulent flow respectively? |
A. | 10/Re, 0.0791(Re)<sup>-0.25</sup> |
B. | 16/Re, 0.0791(Re)<sup>-0.25</sup> |
C. | 10/Re, 0.0771(Re)<sup>-0.25</sup> |
D. | 16/Re, 0.0171(Re)<sup>-0.25</sup> |
Answer» C. 10/Re, 0.0771(Re)<sup>-0.25</sup> | |
10. |
The velocity distribution within the conduit depends on _____ |
A. | shape of the conduit and nature of flow |
B. | temperature of the molten metal |
C. | impurities present in the molten metal |
D. | type of the molten metal |
Answer» B. temperature of the molten metal | |
11. |
Which of the following terms is modified in the integrated energy balance equation for non-uniform velocity distribution? |
A. | Potential energy |
B. | Kinetic energy |
C. | Pressure energy |
D. | Thermal energy |
Answer» C. Pressure energy | |
12. |
Why is Velocity of a fluid in contact with any solid surface is zero? |
A. | Due to cohesive forces in the fluid particles |
B. | Due to low velocity of fluid |
C. | Due to no slip condition |
D. | Due to high intermolecular forces between the fluid particles |
Answer» D. Due to high intermolecular forces between the fluid particles | |
13. |
Which of the following reasons is the incorrect reason for frictional losses in the conduit? |
A. | Gradual change in flow direction |
B. | Sudden contraction of the flow cross-sections |
C. | Sudden enlargement of the flow cross-sections |
D. | Due to irrotational flow of molten metal |
Answer» E. | |
14. |
The energy loss due to friction (Ef) in a circular conduit (on the basis of per unit mass) is given by_____ |
A. | Ef = 4fLv̅²/2D |
B. | Ef = 8fLv̅²/2D |
C. | Ef = 4fLv̅³/2D |
D. | Ef = 4fLv̅²/D |
Answer» B. Ef = 8fLv‚àö√â‚àö√±¬¨¬®‚Äö√¢¬ß/2D | |