Explore topic-wise MCQs in Heat Transfer.

This section includes 16 Mcqs, each offering curated multiple-choice questions to sharpen your Heat Transfer knowledge and support exam preparation. Choose a topic below to get started.

1.

“If β is less than zero, then with respect to the relation k = k0 (1 + β t), conductivity depends on surface area”.

A. True
B. False
Answer» C.
2.

The temperatures on the two sides of a plane wall are t1 and t2 and thermal conductivity of the wall material is prescribed by the relationK = k0 e (-x/δ)Where, k0 is constant and δ is the wall thickness. Find the relation for temperature distribution in the wall?

A. t 1 – t x / t 1 – t 2 = x
B. t 1 – t x / t 1 – t 2 = δ
C. t 1 – t x / t 1 – t 2 = δ/x
D. t 1 – t x / t 1 – t 2 = x/δ
Answer» E.
3.

The unit of thermal conductivity doesn’t contain which parameter?

A. Watt
B. Pascal
C. Meter
D. Kelvin
Answer» C. Meter
4.

If β is greater than zero, then choose the correct statement with respect to given relationk = k0 (1 +β t)

A. k doesn’t depend on temperature
B. k depends on temperature
C. k is directly proportional to t
D. Data is insufficient
Answer» D. Data is insufficient
5.

The accompanying sketch shows the schematic arrangement for measuring the thermal conductivity by the guarded hot plate method. Two similar 1 cm thick specimens receive heat from a 6.5 cm by 6.5 cm guard heater. When the power dissipation by the wattmeter was 15 W, the thermocouples inserted at the hot and cold surfaces indicated temperatures as 325 K and 300 K. What is the thermal conductivity of the test specimen material?

A. 0.81 W/m K
B. 0.71 W/m k
C. 0.61 W/m K
D. 0.51 W/m K
Answer» C. 0.61 W/m K
6.

With respect to the equation k = k0 (1 +β t) which is true if we put β = 0?

A. Slope of temperature curve is constant
B. Slope of temperature curve does not change
C. Slope of temperature curve increases
D. Slope of temperature curve is decreases
Answer» B. Slope of temperature curve does not change
7.

A plane wall of thickness δ has its surfaces maintained at temperatures T1 and T2. The wall is made of a material whose thermal conductivity varies with temperature according to the relation k = k0 T2. Find the expression to work out the steady state heat conduction through the wall?

A. Q = 2A k0 (T 1 3 – T 2 3)/3 δ
B. Q = A k0 (T 1 3 – T 2 3)/3 δ
C. Q = A k0 (T 1 2 – T 2 2)/3 δ
D. Q = A k0 (T 1 – T 2)/3 δ
Answer» C. Q = A k0 (T 1 2 – T 2 2)/3 δ
8.

The inner and outer surfaces of a furnace wall, 25 cm thick, are at 300 degree Celsius and 30 degree Celsius. Here thermal conductivity is given by the relationK = (1.45 + 0.5 * 10-5 t2) KJ/m hr degWhere, t is the temperature in degree centigrade. Calculate the heat loss per square meter of the wall surface area?

A. 1355.3 kJ/m2 hr
B. 2345.8 kJ/m2 hr
C. 1745.8 kJ/m2 hr
D. 7895.9 kJ/m2 hr
Answer» D. 7895.9 kJ/m2 hr
9.

“If β is less than zero, then with respect to the relation k = k0 (1 + β t), conductivity depends on surface area”.$#

A. True
B. False
Answer» C.
10.

The unit of thermal conductivity doesn’t contain which parameter?#

A. Watt
B. Pascal
C. Meter
D. Kelvin
Answer» C. Meter
11.

If β is greater than zero, then choose the correct statement with respect to given relation$

A.
B. k doesn’t depend on temperature
C. k depends on temperature
D. k is directly proportional to t
Answer» D. k is directly proportional to t
12.

With respect to the equation k = k0 (1 +β t) which is true if we put β = 0?$

A. Slope of temperature curve is constant
B. Slope of temperature curve does not change
C. Slope of temperature curve increases
D. Slope of temperature curve is decreases
Answer» B. Slope of temperature curve does not change
13.

The mean thermal conductivity evaluated at the arithmetic mean temperature is represented by

A. k<sub>m</sub> = k<sub>0</sub> [1 + β (t<sub>1</sub> – t<sub>2</sub>)/2].
B. k<sub>m</sub> = k<sub>0</sub> [1 + (t<sub>1</sub> + t<sub>2</sub>)/2].
C. k<sub>m</sub> = k<sub>0</sub> [1 + β (t<sub>1</sub> + t<sub>2</sub>)/3].
D. k<sub>m</sub> = k<sub>0</sub> [1 + β (t<sub>1</sub> + t<sub>2</sub>)/2].
Answer» E.
14.

A plane wall of thickness δ has its surfaces maintained at temperatures T1 and T2. The wall is made of a material whose thermal conductivity varies with temperature according to the relation k = k0 T2. Find the expression to work out the steady state heat conduction through the wall?$

A. Q = 2A k<sub>0</sub> (T <sub>1 </sub><sup>3</sup> – T <sub>2 </sub><sup>3</sup>)/3 δ
B. Q = A k<sub>0</sub> (T <sub>1 </sub><sup>3</sup> – T <sub>2 </sub><sup>3</sup>)/3 δ
C. Q = A k<sub>0</sub> (T <sub>1 </sub><sup>2</sup> – T <sub>2 </sub><sup>2</sup>)/3 δ
D. Q = A k<sub>0</sub> (T <sub>1</sub> – T <sub>2</sub>)/3 δ
Answer» C. Q = A k<sub>0</sub> (T <sub>1 </sub><sup>2</sup> ‚Äö√Ñ√∂‚àö√ë‚àö¬® T <sub>2 </sub><sup>2</sup>)/3 ‚âà√≠¬¨‚Ä¢
15.

The inner and outer surfaces of a furnace wall, 25 cm thick, are at 300 degree Celsius and 30 degree Celsius. Here thermal conductivity is given by the relation

A. KJ/m hr deg
B.
C. 1355.3 kJ/m<sup>2</sup> hr
Answer» D.
16.

With variable thermal conductivity, Fourier law of heat conduction through a plane wall can be expressed as

A. Q = -k<sub>0</sub> (1 + β t) A d t/d x
B. Q = k<sub>0</sub> (1 + β t) A d t/d x
C. Q = – (1 + β t) A d t/d x
D. Q = (1 + β t) A d t/d x
Answer» B. Q = k<sub>0</sub> (1 + ‚âà√≠‚Äö√¢¬ß t) A d t/d x