With variable thermal conductivity, Fourier law of heat conduction through a plane wall can be expressed as

Q = k 0 (1 + ‚âà√≠‚Äö√¢¬ß t) A d t/d x

Q = -k0 (1 + ‚âà√≠‚Äö√¢¬ß t) A d t/d x

Q = k0 (1 + ‚âà√≠‚Äö√¢¬ß t) A d t/d x

Q = ‚Äö√Ñ√∂‚àö√ë‚àö¬® (1 + ‚âà√≠‚Äö√¢¬ß t) A d t/d x

Q = (1 + ‚âà√≠‚Äö√¢¬ß t) A d t/d x

With variable thermal conductivity, Fourier law of heat conduction thr

1.	With variable thermal conductivity, Fourier law of heat conduction through a plane wall can be expressed as
A.	Q = -k<sub>0</sub> (1 + ‚âà√≠‚Äö√¢¬ß t) A d t/d x
B.	Q = k<sub>0</sub> (1 + ‚âà√≠‚Äö√¢¬ß t) A d t/d x
C.	Q = ‚Äö√Ñ√∂‚àö√ë‚àö¬® (1 + ‚âà√≠‚Äö√¢¬ß t) A d t/d x
D.	Q = (1 + ‚âà√≠‚Äö√¢¬ß t) A d t/d x
Answer» B. Q = k<sub>0</sub> (1 + ‚âà√≠‚Äö√¢¬ß t) A d t/d x

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With variable thermal conductivity, Fourier law of heat conduction through a plane wall can be expressed as

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