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This section includes 10 Mcqs, each offering curated multiple-choice questions to sharpen your Mechanical Metallurgy knowledge and support exam preparation. Choose a topic below to get started.
1. |
The Burgers vector for Body-centred cubic lattice will be equal to ________ |
A. | ao[100] |
B. | ao[110] |
C. | ao/2[111] |
D. | ao/2[110] |
Answer» D. ao/2[110] | |
2. |
The extended dislocation formed on the basal plane of Hexagonal closed packed structure are sessile dislocation. |
A. | True |
B. | False |
Answer» C. | |
3. |
Burger vector for Hexagonal closed packed structure is ______ |
A. | (a0/3)[1120] |
B. | (a0)[1120] |
C. | (a0/3)[1000] |
D. | (a0)[1000] |
Answer» B. (a0)[1120] | |
4. |
The basal plane and chief slip direction for Hexagonal closed packed structure is _________ |
A. | (0 0 0 1) & <1 1 2 0> |
B. | (0 2 1 1) & <1 1 -2 0> |
C. | (0 0 0 1) & <1 0 0 0> |
D. | (1 1 2 2) & <1 1 -2 1> |
Answer» B. (0 2 1 1) & <1 1 -2 0> | |
5. |
Shockley dislocation is which type of dislocation? |
A. | Sessile |
B. | Glissile |
C. | Full dislocation |
D. | Mixed dislocation |
Answer» C. Full dislocation | |
6. |
The burgers vector for frank partial dislocation is equal to ___________ (Lattice parameter is ao) |
A. | ao[100] |
B. | ao/2[110] |
C. | ao/3[111] |
D. | ao/3[110] |
Answer» D. ao/3[110] | |
7. |
The higher the width of the stacking fault _________ will be the stacking-fault energy. Higher the stacking fault energy __________ will be the cross slip. |
A. | higher, easier |
B. | lower, easier |
C. | lower, difficult |
D. | higher, difficult |
Answer» C. lower, difficult | |
8. |
The formation of Shockley partial dislocation in the material will generate a region of stacking fault. |
A. | True |
B. | False |
Answer» B. False | |
9. |
The slip in FCC crystal occurs in the (111) plane in {110} direction, but generally it is not energetically favourable, so it slips into two partial dislocations. The correct partial dislocation is represented by which of the following equation? |
A. | ao/2[1 1 0] → ao/3[-1 2 1]+ao/2[112] |
B. | ao/2[1 1 0] → ao/6[-1 2 1]+ao/6[112] |
C. | ao/2[1 1 0] → ao/6[2 -1 -1]+ao/2[11-2] |
D. | ao[1 1 0] → ao/3[-1 2 1]+ao/2[112] |
Answer» D. ao[1 1 0] → ao/3[-1 2 1]+ao/2[112] | |
10. |
The burger vector for Face-centred cubic material is _______; Where ao is the lattice parameter. |
A. | ao/2[110] |
B. | ao/2[111] |
C. | ao[110] |
D. | ao[100] |
Answer» B. ao/2[111] | |