MCQOPTIONS
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MCQOPTIONS
This section includes 8 Mcqs, each offering curated multiple-choice questions to sharpen your Chemical Engineering knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
For equal sized CSTRs in series carrying out 1st order reaction, the concentration at the outlet of nth reactor is ____ |
| A. | CN = \(\frac{1}{(1 + τk)^N} \) |
| B. | CN = \(\frac{C_0}{(1 + τ)^N} \) |
| C. | CN = \(\frac{C_0}{(1 + k)^N} \) |
| D. | CN = \(\frac{C_0}{(1 + τk)^N} \) |
| Answer» E. | |
| 2. |
State true or false.For different sized CSTRs in series, the best system is the one having a minimum volume for a specific conversion. |
| A. | True |
| B. | False |
| Answer» B. False | |
| 3. |
For very low conversion, the value of Damkohler number is ____ |
| A. | ≤0.1 |
| B. | >10 |
| C. | ≥0.1 |
| D. | = 10 |
| Answer» B. >10 | |
| 4. |
For equal sized CSTRs in series carrying out 1st order reactions of constant density, which of the following is true? (ki is the rate constant in a reactor ‘i’ in series) |
| A. | k1 ≠ k2 ≠ … ≠ kn, τ1 = τ2 = … = τn |
| B. | k1 = k2 = … = kn, τ1 = τ2 = … = τn |
| C. | k1 = k2 = … = kn, τ1 ≠ τ2 ≠ … ≠ τn |
| D. | k1< k2< …<kn, τ1 = τ2 = … = τn |
| Answer» C. k1 = k2 = … = kn, τ1 ≠ τ2 ≠ … ≠ τn | |
| 5. |
What is the concentration C4 at the end of 4th reactor, for n unequal sized CSTRs in series, where X4 is the conversion in 4th reactor? |
| A. | C4 = (1 – X4) |
| B. | C4 = C0X4 |
| C. | C0 = C4 (1 – X4) |
| D. | C4 = C0(1 – X4) |
| Answer» E. | |
| 6. |
For ‘i’ CSTRs of variable volume in series, the residence time in the ith reactor is ____ |
| A. | τi = \(\frac{- C_i}{-r_i} \) |
| B. | τi = \(\frac{C_{i-1}- C_i}{-r_i} \) |
| C. | τi = \(\frac{C_i}{-r_i} \) |
| D. | τi = \(\frac{C_{i-1}}{-r_i} \) |
| Answer» C. τi = \(\frac{C_i}{-r_i} \) | |
| 7. |
What is the mole balance of a component in a CSTR? (Where F0 is the molar flowrate of reactant entering and F is the exit molar flowrate) |
| A. | F0 = FX + F |
| B. | F0 = FX + F0 |
| C. | F0 = F0X + F |
| D. | F0 = X + F |
| E. | F0 = FX + Fb) F0 = FX + F0c) F0 = F0X + Fd) F0 = X + F |
| Answer» D. F0 = X + F | |
| 8. |
State true or false.It is preferable to use a number of CSTRs in series to achieve a specific conversion than a single CSTR. |
| A. | True |
| B. | False |
| Answer» B. False | |