MCQOPTIONS
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This section includes 15 Mcqs, each offering curated multiple-choice questions to sharpen your Network Theory knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Determine the voltage across the inductor in the circuit shown below is? |
| A. | VL = 60(-e-2t)V |
| B. | VL = 60(e2t)V |
| C. | VL = 60(e-2t)V |
| D. | VL = 60(-e2t)V |
| Answer» D. VL = 60(-e2t)V | |
| 2. |
The expression of voltage across resistor in the circuit shown below is? |
| A. | VR = 60(1+e2t)V |
| B. | VR = 60(1-e-2t)V |
| C. | VR = 60(1-e2t)V |
| D. | VR = 60(1+e-2t)V |
| Answer» C. VR = 60(1-e2t)V | |
| 3. |
The expression of current from the circuit shown below is? |
| A. | i=2(1-e-2t)A |
| B. | i=2(1+e-2t)A |
| C. | i=2(1+e2t)A |
| D. | i=2(1+e2t)A |
| Answer» B. i=2(1+e-2t)A | |
| 4. |
The expression of current obtained from the circuit in terms of differentiation from the circuit shown below? |
| A. | di/dt+i=4 |
| B. | di/dt+2i=0 |
| C. | di/dt+2i=4 |
| D. | di/dt-2i=4 |
| Answer» D. di/dt-2i=4 | |
| 5. |
A series R-L circuit with R = 30Ω and L = 15H has a constant voltage V = 60V applied at t = 0 as shown in the figure. Determine the current (A) in the circuit at t = 0+. |
| A. | in the circuit at t = 0+.a) 1 |
| B. | 2 |
| C. | 3 |
| D. | 0 |
| Answer» E. | |
| 6. |
The expression of current in R-L circuit is? |
| A. | i=(V/R)(1+exp((R/L)t)) |
| B. | i=-(V/R)(1-exp((R/L)t)) |
| C. | i=-(V/R)(1+exp((R/L)t)) |
| D. | i=(V/R)(1-exp((R/L)t)) |
| Answer» E. | |
| 7. |
THE_EXPRESSION_OF_VOLTAGE_ACROSS_RESISTOR_IN_THE_CIRCUIT_SHOWN_IN_THE_QUESTION_6_IS??$ |
| A. | V<sub>R</sub> =60(1+e<sup>2t</sup>)V |
| B. | V<sub>R</sub> =60(1-e<sup>-2t</sup>)V |
| C. | V<sub>R</sub> =60(1-e<sup>2t</sup>)V |
| D. | V<sub>R</sub> =60(1+e<sup>-2t</sup>)V |
| Answer» C. V<sub>R</sub> =60(1-e<sup>2t</sup>)V | |
| 8. |
Determine the voltage across the inductor in the circuit shown in the question 6 is?$ |
| A. | V<sub>L</sub> =60(-e<sup>-2t</sup>)V |
| B. | V<sub>L</sub> =60(e<sup>2t</sup>)V |
| C. | V<sub>L</sub> =60(e<sup>-2t</sup>)V |
| D. | V<sub>L</sub> =60(-e<sup>2t</sup>)V |
| Answer» D. V<sub>L</sub> =60(-e<sup>2t</sup>)V | |
| 9. |
The expression of current from the circuit shown in the question 6 is? |
| A. | i=2(1-e<sup>-2t</sup>)A |
| B. | i=2(1+e<sup>-2t</sup>)A |
| C. | i=2(1+e<sup>2t</sup>)A |
| D. | i=2(1+e<sup>2t</sup>)A |
| Answer» B. i=2(1+e<sup>-2t</sup>)A | |
| 10. |
The expression of current obtained from the circuit in terms of differentiation from the circuit shown in the question 6? |
| A. | di/dt+i=4 |
| B. | di/dt+2i=0 |
| C. | di/dt+2i=4 |
| D. | di/dt-2i=4 |
| Answer» D. di/dt-2i=4 | |
| 11. |
After how many time constants, the transient part reaches more than 99 percent of its final value? |
| A. | 2 |
| B. | 3 |
| C. | 4 |
| D. | 5 |
| Answer» E. | |
| 12. |
The value of the time constant in the R-L circuit is? |
| A. | L/R |
| B. | R/L |
| C. | R |
| D. | L |
| Answer» B. R/L | |
| 13. |
In the expression of current in the R-L circuit the transient part is? |
| A. | R/V |
| B. | (V/R)(-exp⁡((R/L)t)) |
| C. | (V/R)(exp⁡((R/L)t)) |
| D. | V/R |
| Answer» C. (V/R)(exp‚Äö√Ñ√∂‚àö√ñ¬¨‚àû((R/L)t)) | |
| 14. |
The steady state part in the expression of current in the R-L circuit is? |
| A. | (V/R)(exp⁡((R/L)t)) |
| B. | (V/R)(-exp⁡((R/L)t)) |
| C. | V/R |
| D. | R/V |
| Answer» D. R/V | |
| 15. |
The expression of current in R- L circuit is? |
| A. | i=(V/R)(1+exp⁡((R/L)t)) |
| B. | i=-(V/R)(1-exp⁡((R/L)t)) |
| C. | i=-(V/R)(1+exp⁡((R/L)t)) |
| D. | i=(V/R)(1-exp⁡((R/L)t)) |
| Answer» E. | |