 
			 
			MCQOPTIONS
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				This section includes 19 Mcqs, each offering curated multiple-choice questions to sharpen your Digital Communications knowledge and support exam preparation. Choose a topic below to get started.
| 1. | The performance of non binary concatenated code depends on | 
| A. | Bit errors | 
| B. | Symbols errors | 
| C. | Bit & Symbols errors | 
| D. | None of the mentioned | 
| Answer» C. Bit & Symbols errors | |
| 2. | A concatenated code has | 
| A. | Low error rate | 
| B. | High complexity | 
| C. | Low error rate & High complexity | 
| D. | None of the mentioned | 
| Answer» B. High complexity | |
| 3. | A concatenated code uses | 
| A. | One level of coding | 
| B. | Two levels of coding | 
| C. | Three levels of coding | 
| D. | None of the mentioned | 
| Answer» C. Three levels of coding | |
| 4. | The minimum end to end delay in block interleaving is | 
| A. | 2MN+2M+2 | 
| B. | 2MN-2M+2 | 
| C. | 2MN-2M-2 | 
| D. | 2MN+2M-2 | 
| Answer» C. 2MN-2M-2 | |
| 5. | Separating the symbols makes the channel memory-less. | 
| A. | True | 
| B. | False | 
| Answer» B. False | |
| 6. | THE_MINIMUM_END_TO_END_DELAY_IN_BLOCK_INTERLEAVING_IS?$ | 
| A. | 2MN+2M+2 | 
| B. | 2MN-2M+2 | 
| C. | 2MN-2M-2 | 
| D. | 2MN+2M-2 | 
| Answer» C. 2MN-2M-2 | |
| 7. | A concatenated code has$ | 
| A. | Low error rate | 
| B. | High complexity | 
| C. | Low error rate & High complexity | 
| D. | None of the mentioned | 
| Answer» B. High complexity | |
| 8. | A_concatenated_code_uses$ | 
| A. | One level of coding | 
| B. | Two levels of coding | 
| C. | Three levels of coding | 
| D. | None of the mentioned | 
| Answer» C. Three levels of coding | |
| 9. | Turbo code is a | 
| A. | Serial concatenation code | 
| B. | Parallel concatenation code | 
| C. | Block code | 
| D. | None of the mentioned | 
| Answer» C. Block code | |
| 10. | Concatenated code is an example of | 
| A. | Error detecting code | 
| B. | Error correcting code | 
| C. | Error detecting & correcting code | 
| D. | None of the mentioned | 
| Answer» C. Error detecting & correcting code | |
| 11. | The_performance_of_non_binary_concatenated_code_depends_on | 
| A. | Bit errors | 
| B. | Symbols errors | 
| C. | Bit & Symbols errors | 
| D. | None of the mentioned | 
| Answer» C. Bit & Symbols errors | |
| 12. | Separating the symbols makes the channel memory-less? | 
| A. | True | 
| B. | False | 
| Answer» B. False | |
| 13. | The channel that exhibits multi-path fading | 
| A. | Has memory | 
| B. | Exhibits mutually dependent signal transmission impairments | 
| C. | Received signal will be distorted | 
| D. | All of the mentioned | 
| Answer» E. | |
| 14. | In interpolation | 
| A. | New samples are added | 
| B. | Unreliable samples are removed | 
| C. | New samples are added & Unreliable samples are removed | 
| D. | None of the mentioned | 
| Answer» D. None of the mentioned | |
| 15. | The ______ the error correcting capability used, the _____ will be the erasure correcting capability. | 
| A. | Larger, smaller | 
| B. | Smaller, larger | 
| C. | Smaller, smaller | 
| D. | Larger, larger | 
| Answer» B. Smaller, larger | |
| 16. | Decoding step consists of | 
| A. | De-interleaving | 
| B. | Decoding | 
| C. | De-interleaving & Decoding | 
| D. | None of the mentioned | 
| Answer» D. None of the mentioned | |
| 17. | The CIRC error control scheme includes | 
| A. | Correction | 
| B. | Concealment | 
| C. | Correction & Concealment | 
| D. | None of the mentioned | 
| Answer» D. None of the mentioned | |
| 18. | Sources of channel errors are | 
| A. | Finger prints | 
| B. | Air bubbles | 
| C. | Unwanted particles | 
| D. | All of the mentioned | 
| Answer» E. | |
| 19. | Compact disc is used for | 
| A. | Digital storage | 
| B. | Reproduction of audio signals | 
| C. | Digital storage & Reproduction of audio signals | 
| D. | None of the mentioned | 
| Answer» D. None of the mentioned | |