Explore topic-wise MCQs in Testing Subject.

This section includes 657 Mcqs, each offering curated multiple-choice questions to sharpen your Testing Subject knowledge and support exam preparation. Choose a topic below to get started.

1.

In SDRAM’s buffers are used to store data that is read or written.

A. true
B. false
Answer» B. false
2.

To improve the data retrieval rate

A. access time
B. cycle time
C. memory latency
D. none of the mentioned
Answer» D. none of the mentioned
3.

DDR SDRAM’s perform faster data transfer by

A. integrating the hardware
B. transferring on both edges
C. improving the clock speeds
D. increasing the bandwidth
Answer» C. improving the clock speeds
4.

In a SDRAM each row is refreshed every 64ms.

A. true
B. false
Answer» B. false
5.

A                 is used to restore the contents of the cells.

A. sense amplifier
B. refresh counter
C. restorer
D. none of the mentioned
Answer» C. restorer
6.

The mode register is used to

A. select the row or column data transfer mode
B. select the mode of operation
C. select mode of storing the data
D. all of the mentioned
Answer» C. select mode of storing the data
7.

The difference between DRAM’s and SDRAM’s is/are

A. the dram’s will not use the master slave relationship in data transfer
B. the sdram’s make use of clock
C. the sdram’s are more power efficient
D. none of the mentioned
Answer» E.
8.

The block transfer capability of the DRAM is called

A. burst mode
B. block mode
C. fast page mode
D. fast frame mode
Answer» D. fast frame mode
9.

The difference in the address and data connection between DRAM’s and SDRAM’s is

A. the usage of more number of pins in sdram’s
B. the requirement of more address lines in sdram’s
C. the usage of a buffer in sdram’s
D. none of the mentioned
Answer» D. none of the mentioned
10.

In order to read multiple bytes of a row at the same time, we make use of

A. latch
B. shift register
C. cache
D. memory extension
Answer» B. shift register
11.

To get the row address of the required data               is enabled.

A. cas
B. ras
C. cs
D. sense/write
Answer» C. cs
12.

The processor must take into account the delay in accessing the memory location, such memories are called

A. delay integrated
B. asynchronous memories
C. synchronous memories
D. isochronous memories
Answer» C. synchronous memories
13.

                    circuit is used to restore the capacitor value.

A. sense amplify
B. signal amplifier
C. delta modulator
D. none of the mentioned
Answer» B. signal amplifier
14.

The capacitors lose the charge over time due to

A. the leakage resistance of the capacitor
B. the small current in the transistor after being turned on
C. the defect of the capacitor
D. none of the mentioned
Answer» B. the small current in the transistor after being turned on
15.

To reduce the number of external connections required, we make use of

A. de-multiplexer
B. multiplexer
C. encoder
D. decoder
Answer» C. encoder
16.

The Reason for the disregarding of the SRAM’s is

A. low efficiency
B. high power consumption
C. high cost
D. all of the mentioned
Answer» D. all of the mentioned
17.

In a 4M-bit chip organisation has a total of 19 external connections.then it has                 address if 8 data lines are there.

A. 10
B. 8
C. 9
D. 12
Answer» D. 12
18.

The reason for the cells to lose their state over time is

A. the lower voltage levels
B. usage of capacitors to store the charge
C. use of shift registers
D. none of the mentioned
Answer» C. use of shift registers
19.

The disadvantage of DRAM over SRAM is/are

A. lower data storage capacities
B. higher heat dissipation
C. the cells are not static
D. all of the mentioned
Answer» D. all of the mentioned
20.

The advantage of CMOS SRAM over the transistor one’s is

A. low cost
B. high efficiency
C. high durability
D. low power consumption
Answer» E.
21.

Circuits that can hold their state as long as power is applied is

A. dynamic memory
B. static memory
C. register
D. cache
Answer» C. register
22.

A memory organisation that can hold upto 1024 bits and has a minimum of 10 address lines can be organized into

A. 128 x 8
B. 256 x 4
C. 512 x 2
D. 1024 x 1
Answer» E.
23.

The number of external connections required in 16 X 8 memory organisation is

A. 14
B. 19
C. 15
D. 12
Answer» B. 19
24.

A 16 X 8 Organisation of memory cells, can store upto

A. 256 bits
B. 1024 bits
C. 512 bits
D. 128 bits
Answer» E.
25.

The word line is driven by the

A. chip select
B. address decoder
C. data line
D. control line
Answer» C. data line
26.

The cells in a row are connected to a common line called

A. work line
B. word line
C. length line
D. principle diagonal
Answer» C. length line
27.

VLSI stands for

A. very large scale integration
B. very large stand-alone integration
C. volatile layer system interface
D. none of the mentioned
Answer» B. very large stand-alone integration
28.

The logical addresses generated by the cpu are mapped onto physical memory by

A. relocation register
B. tlb
C. mmu
D. none of the mentioned
Answer» D. none of the mentioned
29.

The cells in each column are connected to

A. word line
B. data line
C. read line
D. sense/ write line
Answer» E.
30.

The minimum time delay between two successive memory read operations is

A. cycle time
B. latency
C. delay
D. none of the mentioned
Answer» B. latency
31.

                      is the bottleneck, when it comes computer performance.

A. memory access time
B. memory cycle time
C. delay
D. latency
Answer» C. delay
32.

The duration between the read and the mfc signal is

A. access time
B. latency
C. delay
D. cycle time
Answer» B. latency
33.

EPIC stands for?

A. explicitly parallel instruction computing
B. external peripheral integrating component
C. external parallel instruction computing
D. none of the mentioned
Answer» B. external peripheral integrating component
34.

In VLIW the decision for the order of execution of the instructions depends on the program itself.

A. true
B. false
Answer» B. false
35.

To compute the direction of the branch the VLIW uses

A. seekers
B. heuristics
C. direction counter
D. compass
Answer» C. direction counter
36.

The main difference between the VLIW and the other approaches to improve performance is

A. cost effectiveness
B. increase in performance
C. lack of complex hardware design
D. all of the mentioned
Answer» D. all of the mentioned
37.

The VLIW processors are much simpler as they do not require of

A. computational register
B. complex logic circuits
C. ssd slots
D. scheduling hardware
Answer» E.
38.

VLIW stands for?

A. very long instruction word
B. very long instruction width
C. very large instruction word
D. very long instruction width
Answer» B. very long instruction width
39.

The parallel execution of operations in VLIW is done according to the schedule determined by

A. task scheduler
B. interpreter
C. compiler
D. encoder
Answer» D. encoder
40.

The most common modes of communication in clusters are

A. message queues
B. message passing interface
C. pvm
D. both message passing interface and pvm
Answer» E.
41.

In the client server model of the cluster                     approach is used.

A. load configuration
B. fifo
C. bankers algorithm
D. round robin
Answer» E.
42.

The method followed in case of node failure, wherein the node gets disabled is

A. stonith
B. fibre channel
C. fencing
D. none of the mentioned
Answer» B. fibre channel
43.

The cluster formation in which the work is divided equally among the systems is

A. load-configuration
B. load-division
C. light head
D. both load-configuration and load- division
Answer» B. load-division
44.

The software which governs the group of computers is

A. driver rd45
B. interface ui
C. clustering middleware
D. distributor
Answer» D. distributor
45.

The computer cluster architecture emerged as a result of

A. isa
B. workstation
C. super computers
D. distributed systems
Answer» E.
46.

Each computer in a cluster is connected using

A. utp
B. rj-45
C. stp
D. coaxial cable
Answer» C. stp
47.

The set of loosely connected computers are called as

A. lan
B. wan
C. workstation
D. cluster
Answer» E.
48.

The algorithm followed in most of the systems to perform out of order execution is

A. tomasulo algorithm
B. score carding
C. reader-writer algorithm
D. none of the mentioned
Answer» B. score carding
49.

The problem where process concurrency becomes an issue is called as

A. philosophers problem
B. bakery problem
C. bankers problem
D. reader-writer problem
Answer» E.
50.

                          method is used in centralized systems to perform out of order execution.

A. scorecard
B. score boarding
C. optimizing
D. redundancy
Answer» C. optimizing