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This section includes 375 Mcqs, each offering curated multiple-choice questions to sharpen your Computer Science Engineering (CSE) knowledge and support exam preparation. Choose a topic below to get started.
| 201. |
From digital filter we will get the output pulse as the                of the current and the previous pulse. |
| A. | summation |
| B. | difference |
| C. | product |
| D. | ratio |
| Answer» B. difference | |
| 202. |
The method in which small amount of controlled ISI is introduced into the data stream rather than trying to eliminate it completely is called as |
| A. | correlative coding |
| B. | duobinary signalling |
| C. | partial response signalling |
| D. | all of the mentioned |
| Answer» E. | |
| 203. |
Gaussian pulses are used when cost and power efficiency are major factors. |
| A. | true |
| B. | false |
| Answer» B. false | |
| 204. |
Gaussian pulse shaping filter reduces the spectral occupancy and ISI. |
| A. | true |
| B. | false |
| Answer» C. | |
| 205. |
Gaussian pulse shaping filter follows Nyquist criterion. |
| A. | true |
| B. | false |
| Answer» C. | |
| 206. |
As the roll off factor in raised cosine rolloff filter                      the occupied bandwidth |
| A. | manchester |
| B. | faraday |
| C. | graham bell |
| D. | nyquist |
| Answer» E. | |
| 207. |
Raised cosine filter does not satisfy Nyquist criteria. |
| A. | true |
| B. | false |
| Answer» C. | |
| 208. |
Gaussian filter has zero crossings at adjacent symbol peaks. |
| A. | true |
| B. | false |
| Answer» C. | |
| 209. |
Why is pulse shaping technique used? |
| A. | to increase isi |
| B. | to increase spectral width of modulated signal |
| C. | to reduce isi |
| D. | to reduce power spectral density |
| Answer» D. to reduce power spectral density | |
| 210. |
ISI is                  by increasing channel bandwidth. |
| A. | maximized |
| B. | minimized |
| C. | zero |
| D. | infinite |
| Answer» C. zero | |
| 211. |
Examples of double side band signals are |
| A. | ask |
| B. | psk |
| C. | ask & psk |
| D. | none of the mentioned |
| Answer» D. none of the mentioned | |
| 212. |
A pulse shaping filter should satisfy two requirements. They are |
| A. | should be realizable |
| B. | should have proper roll off factor |
| C. | should be realizable & have proper roll off factor |
| D. | none of the mentioned |
| Answer» D. none of the mentioned | |
| 213. |
Roll off factor is the fraction of |
| A. | excess bandwidth and absolute bandwidth |
| B. | excess bandwidth and minimum nyquist bandwidth |
| C. | absolute bandwidth and minimum nyquist bandwidth |
| D. | none of the mentioned |
| Answer» C. absolute bandwidth and minimum nyquist bandwidth | |
| 214. |
The minimum nyquist bandwidth for the rectangular spectrum in raised cosine filter is |
| A. | 2t |
| B. | 1/2t |
| C. | t2 |
| D. | 2/t |
| Answer» C. t2 | |
| 215. |
Examples of nyquist filters are |
| A. | root raised cosine filter |
| B. | raised cosine filter |
| C. | root raised & raised cosine filter |
| D. | none of the mentioned |
| Answer» D. none of the mentioned | |
| 216. |
A nyquist pulse is the one which can be represented by            shaped pulse multiplied by another time function. |
| A. | sine |
| B. | cosine |
| C. | sinc |
| D. | none of the mentioned |
| Answer» D. none of the mentioned | |
| 217. |
If each pulse of the sequence to be detected is in            shape, the pulse can be detected without ISI. |
| A. | sine |
| B. | cosine |
| C. | sinc |
| D. | none of the mentioned |
| Answer» D. none of the mentioned | |
| 218. |
The method in which the tail of one pulse smears into adjacent symbol interval is called as |
| A. | intersymbol interference |
| B. | interbit interference |
| C. | interchannel interference |
| D. | none of the mentioned |
| Answer» B. interbit interference | |
| 219. |
Power efficiency of M-ary FSK increases, since |
| A. | constellation is densely packed |
| B. | m signals are non-orthogonal |
| C. | fixed null bandwidth |
| D. | m-signals are orthogonal |
| Answer» E. | |
| 220. |
What is symbol rate packing? |
| A. | maximum possible symbol transmission rate |
| B. | maximum possible symbol receiving rate |
| C. | maximum bandwidth |
| D. | maximum isi value allowed |
| Answer» B. maximum possible symbol receiving rate | |
| 221. |
The bandwidth efficiency of an M-ary FSK signal                  with                  in M. |
| A. | constant, increase |
| B. | increases, increase |
| C. | decreases, increase |
| D. | decreases, decrease |
| Answer» D. decreases, decrease | |
| 222. |
In comparison to M-ary PSK, M-ary QAM bandwidth efficiency is            and power efficiency is |
| A. | identical, superior |
| B. | less, superior |
| C. | identical, identical |
| D. | superior, superior |
| Answer» B. less, superior | |
| 223. |
M-ary QAM signal have constant energy per symbol. |
| A. | true |
| B. | false |
| Answer» C. | |
| 224. |
In QAM, the amplitude is                and phase is |
| A. | varied, constant |
| B. | varied, varied |
| C. | constant, varied |
| D. | constant, constant |
| Answer» C. constant, varied | |
| 225. |
The power efficiency of the M ary PSK decreases because of the |
| A. | freely packed constellation |
| B. | increment of bandwidth efficiency |
| C. | fixed null bandwidth |
| D. | densely packed constellation |
| Answer» E. | |
| 226. |
As the value of M Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â the bandwidth efficiency |
| A. | increases, same. |
| B. | increases, decreases |
| C. | increases, increases |
| D. | decreases, same |
| Answer» D. decreases, same | |
| 227. |
What is the radius of the circle in M-ary PSK on which message points are equaly spaced? |
| A. | √es |
| B. | √eb |
| C. | eb |
| D. | es |
| Answer» B. √eb | |
| 228. |
M-ary modulation schemes have very good power efficiency. |
| A. | true |
| B. | false |
| Answer» C. | |
| 229. |
M-ary signalling techniques are not sensitive to timing jitters. |
| A. | true |
| B. | false |
| Answer» C. | |
| 230. |
In an M-ary signalling scheme two or more bits are grouped together to form a |
| A. | chip |
| B. | symbol |
| C. | byte |
| D. | pattern |
| Answer» C. byte | |
| 231. |
Which of the following is a combined linear and constant envelope technique? |
| A. | mpsk |
| B. | psk |
| C. | bpsk |
| D. | qpsk |
| Answer» B. psk | |
| 232. |
Which of the following is not a detection technique used for detection of π/4 QPSK signals? |
| A. | baseband differential detection |
| B. | if differential detection |
| C. | fm discriminator detection |
| D. | envelope detection |
| Answer» E. | |
| 233. |
QPSK signals perform better than OQPSK in the presence of phase jitter. |
| A. | true |
| B. | false |
| Answer» C. | |
| 234. |
The bandwidth of OQPSK is                to QPSK. |
| A. | identical |
| B. | twice |
| C. | half |
| D. | four times |
| Answer» B. twice | |
| 235. |
What is the full form of OQPSK? |
| A. | optical quadrature phase shift keying |
| B. | orthogonal quadrature pulse shift keying |
| C. | orthogonal quadrature phase shift keying |
| D. | offset quadrature phase shift keying |
| Answer» E. | |
| 236. |
QPSK provides twice the bandwidth efficiency and                energy efficiency as compared to BPSK. |
| A. | twice |
| B. | half |
| C. | same |
| D. | four times |
| Answer» D. four times | |
| 237. |
QPSK has                  the bandwidth efficiency of BPSK. |
| A. | twice |
| B. | same |
| C. | half |
| D. | four times |
| Answer» B. same | |
| 238. |
In DPSK system, input signal is differentially encoded and then modulated using a                  modulator. |
| A. | amplitude |
| B. | frequency |
| C. | bpsk |
| D. | qpsk |
| Answer» D. qpsk | |
| 239. |
BPSK uses non-coherent demodulator. |
| A. | true |
| B. | false |
| Answer» C. | |
| 240. |
DPSK uses coherent form of PSK. |
| A. | true |
| B. | false |
| Answer» C. | |
| 241. |
Which of the following is not a linear modulation technique? |
| A. | oqpsk |
| B. | π/4 qpsk |
| C. | fsk |
| D. | bpsk |
| Answer» D. bpsk | |
| 242. |
Linear modulation techniques are not bandwidth efficient. |
| A. | true |
| B. | false |
| Answer» C. | |
| 243. |
In BPSK, the                  of constant amplitude carrier signal is switched between two values according to the two possible values. |
| A. | amplitude |
| B. | phase |
| C. | frequency |
| D. | angle |
| Answer» C. frequency | |
| 244. |
Luminance refers to |
| A. | contrast |
| B. | diffusion |
| C. | brightness |
| D. | aperture |
| Answer» D. aperture | |
| 245. |
How many lines are there in an NTSC signal? |
| A. | 1024 |
| B. | 1856 |
| C. | 625 |
| D. | 525 |
| Answer» E. | |
| 246. |
RGB stands for |
| A. | red green brown |
| B. | red green black |
| C. | red gold blue |
| D. | red green blue |
| Answer» E. | |
| 247. |
How we can define the satisfactory performance of an analog microwave system? |
| A. | carrier to noise ratio that exceeds a given value |
| B. | carrier to noise ratio that is below a given value |
| C. | an erp value that exceeds a given value |
| D. | an erp value that is below a given value |
| Answer» B. carrier to noise ratio that is below a given value | |
| 248. |
Which term is used for moving PCM samples from one time slot to another? |
| A. | time switching |
| B. | space switching |
| C. | phase switching |
| D. | frequency switching |
| Answer» B. space switching | |
| 249. |
What is the full form of LOS? |
| A. | level of signal |
| B. | line of sight |
| C. | loss of signal |
| D. | level of sight |
| Answer» C. loss of signal | |
| 250. |
Power can be coupled into or out of a waveguide with a magnetic field probe. |
| A. | true |
| B. | false |
| Answer» C. | |