Explore topic-wise MCQs in Electronic Devices Circuits.

This section includes 20 Mcqs, each offering curated multiple-choice questions to sharpen your Electronic Devices Circuits knowledge and support exam preparation. Choose a topic below to get started.

1.

The range of β is _________

A. 20 to 500
B. 50 to 300
C. 30 to 400
D. 10 to 20
Answer» B. 50 to 300
2.

When the signal is applied, the ratio of change of collector current to the ratio of change of base current is called_________

A. dc current gain
B. base current amplification factor
C. emitter current amplification factor
D. ac current gain
Answer» E.
3.

In ICEO, wt does the subscript ‘CEO’ mean?

A. collector to base emitter open
B. emitter to base collector open
C. collector to emitter base open
D. emitter to collector base open
Answer» D. emitter to collector base open
4.

The relation between α and β is_________

A. β = α/ (1-α)
B. α = β/(1+β)
C. β = α/ (1+α)
D. α = β/(1- β)
Answer» C. β = α/ (1+α)
5.

The collector supply voltage for a CE configured transistor is 10V. The resistance RL=800Ω. The voltage drop across RL is 0.8V. Find the value of collector emitter voltage.

A. 3.7V
B. 9.2V
C. 6.5V
D. 9.8V
Answer» C. 6.5V
6.

A transistor is connected in CE configuration. Collector supply voltage Vcc=10V, RL=800Ω, voltage drop across RL=0.8V, α=0.96. What is base current?

A. 41.97µA
B. 56.78µA
C. 67.67µA
D. 78.54µA
Answer» B. 56.78µA
7.

In CE configuration, if the voltage drop across 5kΩ resistor connected in the collector circuit is 5V. Find the value of IB when β=50.

A. 0.01mA
B. 0.25mA
C. 0.03mA
D. 0.02mA
Answer» E.
8.

A germanium transistor with α=0.98 gives a reverse saturation current ICBO=10µA in a CB configuration. When it is used in CE configuration with a base current of 0.22µA, calculate the collector current.

A. 0.9867mA
B. 0.7654mA
C. 0.51078mA
D. 0.23456mA
Answer» D. 0.23456mA
9.

In an NPN silicon transistor, α=0.995, IE=10mA and leakage current ICBO=0.5µA. Determine ICEO.

A. 10µA
B. 100µA
C. 90µA
D. 500µA
Answer» C. 90µA
10.

The base current amplification factor β is given by_________

A. IC/IB
B. IB/IC
C. IE/IB
D. IB/IE
Answer» B. IB/IC
11.

THE_RANGE_OF_‚ÂÀ√≠‚ÄÖ√¢¬ß_IS__________?$#

A. 20 to 500
B. 50 to 300
C. 30 to 400
D. 10 to 20
Answer» B. 50 to 300
12.

WHEN_THE_SIGNAL_IS_APPLIED,_THE_RATIO_OF_CHANGE_OF_COLLECTOR_CURRENT_TO_THE_RATIO_OF_CHANGE_OF_BASE_CURRENT_IS_CALLED_________?$

A. dc current gain
B. base current amplification factor
C. emitter current amplification factor
D. ac current gain
Answer» E.
13.

In ICEO, wt does the subscript ‘CEO’ mean?#

A. collector to base emitter open
B. emitter to base collector open
C. collector to emitter base open
D. emitter to collector base open
Answer» D. emitter to collector base open
14.

The relation between α and β is_________$

A. β = α/ (1-α)
B. α = β/(1+β)
C. β = α/ (1+α)
D. α = β/(1- β)
Answer» C. ‚âà√≠‚Äö√¢¬ß = ‚âà√≠¬¨¬±/ (1+‚âà√≠¬¨¬±)
15.

The collector supply voltage for a CE configured transistor is 10V. The resistance RL=800Ω. The voltage drop across RL is 0.8V. Find the value of collector emitter voltage.$

A. 3.7V
B. 9.2V
C. 6.5V
D. 9.8V
Answer» C. 6.5V
16.

A transistor is connected in CE configuration. Collector supply voltage Vcc=10V, RL=800Ω, voltage drop across RL=0.8V, α=0.96. What is base current?$

A. 41.97µA
B. 56.78µA
C. 67.67µA
D. 78.54µA
Answer» B. 56.78¬¨¬®¬¨¬µA
17.

In CE configuration, if the voltage drop across 5kΩ resistor connected in the collector circuit is 5V. Find the value of IB when β=50.$

A. 0.01mA
B. 0.25mA
C. 0.03mA
D. 0.02mA
Answer» E.
18.

A germanium transistor with α=0.98 gives a reverse saturation current ICBO=10µA in a CB configuration. When it is used in CE configuration with a base current of 0.22µA, calculate the collector current.$

A. 0.9867mA
B. 0.7654mA
C. 0.51078mA
D. 0.23456mA
Answer» D. 0.23456mA
19.

In an NPN silicon transistor, α=0.995, IE=10mA and leakage current ICBO=0.5µA. Determine ICEO.$

A. 10µA
B. 100µA
C. 90µA
D. 500µA
Answer» C. 90¬¨¬®¬¨¬µA
20.

The base current amplification factor β is given by_________

A. I<sub>C</sub>/I<sub>B</sub>
B. I<sub>B</sub>/I<sub>C</sub>
C. I<sub>E</sub>/I<sub>B</sub>
D. I<sub>B</sub>/I<sub>E</sub>
Answer» B. I<sub>B</sub>/I<sub>C</sub>