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This section includes 14 Mcqs, each offering curated multiple-choice questions to sharpen your Organic Chemistry knowledge and support exam preparation. Choose a topic below to get started.
1. |
Which of the following is the slow, low-temperature, flameless form of combustion, sustained by the heat evolved when oxygen directly attacks the surface of a condensed-phase fuel? |
A. | Rapid combustion |
B. | Turbulent combustion |
C. | Spontaneous combustion |
D. | Smouldering |
Answer» E. | |
2. |
The value ∆H transition of C (graphite) → C (diamond) is 1.9 kJ/mol at 25℃ entropy of graphite is higher than entropy of diamond. This implies that? |
A. | C(diamond) is more thermodynamically stable then C (graphite) at 25℃ |
B. | C(graphite) is more thermodynamically stable than C (diamond) at 25℃ |
C. | diamond will provide more heat on complete combustion at 25℃d) ∆Gtransition of C (diamon |
D. | is 1.9 kJ/mol at 25℃ entropy of graphite is higher than entropy of diamond. This implies that?a) C(diamond) is more thermodynamically stable then C (graphite) at 25℃b) C(graphite) is more thermodynamically stable than C (diamond) at 25℃c) diamond will provide more heat on complete combustion at 25℃d) ∆Gtransition of C (diamond) → C (graphit |
E. | → C (diamond) is 1.9 kJ/mol at 25℃ entropy of graphite is higher than entropy of diamond. This implies that?a) C(diamond) is more thermodynamically stable then C (graphite) at 25℃b) C(graphite) is more thermodynamically stable than C (diamond) at 25℃c) diamond will provide more heat on complete combustion at 25℃d) ∆Gtransition of C (diamond) → C (graphite) is -ve |
Answer» E. → C (diamond) is 1.9 kJ/mol at 25℃ entropy of graphite is higher than entropy of diamond. This implies that?a) C(diamond) is more thermodynamically stable then C (graphite) at 25℃b) C(graphite) is more thermodynamically stable than C (diamond) at 25℃c) diamond will provide more heat on complete combustion at 25℃d) ∆Gtransition of C (diamond) → C (graphite) is -ve | |
3. |
The heat of combustion of carbon is 394 KJ/mol. What will be the heat evolved in combustion of 6.023 x 1022 atoms of carbon? |
A. | 64.7 KJ |
B. | 39.4 KJ |
C. | 42.4 KJ |
D. | 91.6 KJ |
Answer» C. 42.4 KJ | |
4. |
Equal volumes of C2H2 & H2 are combusted under identical condition. What will be the ratio of heat evolved for C2H2 and H2?H2 (g) + 1/2 O2(g) → H2O(g), ∆H=-241.8 KJC2H2 (g) + 5/2 O2(g) → CO2(g) + H2O(g), ∆H=-1300 KJ |
A. | 5.37/1 |
B. | 1/5.37 |
C. | 1/1 |
D. | 2.8/6.1 |
Answer» C. 1/1 | |
5. |
Which of the following reaction has a faster rate of reaction for nascent oxygen atom? |
A. | R1 >> R2 |
B. | R1 > R2 |
C. | R1 << R2 |
D. | R1 < R2 |
Answer» D. R1 < R2 | |
6. |
THE_VALUE_‚ÄÖ√Ñ√∂‚ÀւĆ‚ÀÖ√∫H_TRANSITION_OF_C_(GRAPHITE)_‚ÄÖ√Ñ√∂‚ÀÖ√∫‚Àւ†_C_(DIAMOND)_IS_1.9_KJ/MOL_AT_25‚ÄÖ√Ñ√∂‚ÀÖ√´‚ÀÖ√¢_ENTROPY_OF_GRAPHITE_IS_HIGHER_THAN_ENTROPY_OF_DIAMOND._THIS_IMPLIES_THAT:?$# |
A. | C(diamond) is more thermodynamically stable then C (graphite) at 25‚ÑÉ |
B. | C(graphite) is more thermodynamically stable than C (diamond) at 25‚ÑÉ |
C. | diamond will provide more heat on complete combustion at 25‚ÑÉ |
D. | ∆G<sub>transition</sub> of C (diamond) → C (graphite) is -ve |
Answer» E. | |
7. |
Which_of_the_following_is_the_slow,_low-temperature,_flameless_form_of_combustion,_sustained_by_the_heat_evolved_when_oxygen_directly_attacks_the_surface_of_a_condensed-phase_fuel?$ |
A. | Rapid combustion |
B. | Turbulent combustion |
C. | Spontaneous combustion |
D. | Smouldering |
Answer» E. | |
8. |
The heat of combustion of carbon is 394 KJ/mol. What will be the heat evolved in combustion of 6.023 x 1022 atoms of carbon? |
A. | 64.7 KJ |
B. | 39.4 KJ |
C. | 42.4 KJ |
D. | 91.6 KJ |
Answer» C. 42.4 KJ | |
9. |
Equal volumes of C2H2 & H2 are combusted under identical condition. What will be the ratio of heat evolved for C2H2 and H2? |
A. | + 1/2 O<sub>2</sub>(g) → H<sub>2</sub>O(g), ∆H=-241.8 KJ |
B. | + 5/2 O<sub>2</sub>(g) → CO<sub>2</sub>(g) + H<sub>2</sub>O(g), ∆H=-1300 KJ |
C. | 5.37/1 |
D. | 1/5.37 |
Answer» C. 5.37/1 | |
10. |
With respect to enthalpy of combustion which of the following is correct? |
A. | ∆H<sub>rxn</sub> = Σ∆H<sub>f</sub> (product) – Σ∆H<sub>f</sub> (reactant) |
B. | ∆H<sub>rxn</sub> = Σ∆H<sub>f</sub> (reactant) – Σ∆H<sub>f</sub> (product) |
C. | ∆H<sub>rxn</sub> = Σ∆H<sub>f</sub> (product) + Σ∆H<sub>f</sub> (reactant) |
D. | ∆H<sub>rxn</sub> = 2 Σ∆H<sub>f</sub> (product) – Σ∆H<sub>f</sub> (reactant) |
Answer» B. ‚Äö√Ñ√∂‚àö‚Ć‚àö√∫H<sub>rxn</sub> = ‚âà√≠¬¨¬£‚Äö√Ñ√∂‚àö‚Ć‚àö√∫H<sub>f</sub> (reactant) ‚Äö√Ñ√∂‚àö√ë‚àö¬® ‚âà√≠¬¨¬£‚Äö√Ñ√∂‚àö‚Ć‚àö√∫H<sub>f</sub> (product) | |
11. |
Which of the following statement is incorrect about oxidation number? |
A. | Show electron density and about the tendency of an atom or molecule to engage oxidation-reduction reactions |
B. | The oxidation number is always given in Roman numerals while the formal charge is always given in numbers |
C. | To calculate an oxidation number, it is essential to know which element in a chemical bond is the most electronegative |
D. | It cannot be a negative number |
Answer» E. | |
12. |
What is the type of reaction between alkanes and hydroxyl radical? |
A. | endothermic |
B. | exothermic |
C. | isothermal |
D. | isochoric |
Answer» C. isothermal | |
13. |
Which of the following is not true about combustion of hydrocarbons? |
A. | All hydrocarbons react in air to form carbon monoxide and then carbon dioxide |
B. | First step is always the reaction between the hydrocarbon and hydroxyl radical |
C. | Alkanes, the hydroxyl radical abstracts a hydrogen atom and forms a carbanion |
D. | With alkenes and alkynes, the electron-deficient hydroxyl radical adds to the multiple bond |
Answer» D. With alkenes and alkynes, the electron-deficient hydroxyl radical adds to the multiple bond | |
14. |
What is the concentration of carbon dioxide in the atmosphere? |
A. | 3.5 x 10<sup>6</sup> ppm |
B. | 1.0 x 10<sup>2</sup> ppm |
C. | 1.6 x 10<sup>5</sup> ppm |
D. | 1.0 x 10<sup>3</sup> ppm |
Answer» B. 1.0 x 10<sup>2</sup> ppm | |