MCQOPTIONS
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MCQOPTIONS
This section includes 10 Mcqs, each offering curated multiple-choice questions to sharpen your Aircraft Performance knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
There is an alternative method to calculate climb rate and gradient. |
| A. | True |
| B. | False |
| Answer» B. False | |
| 2. |
Level accelerated is best suitable for thrust producing engines. |
| A. | True |
| B. | False |
| Answer» B. False | |
| 3. |
The partial climb is best suitable for power-producing engines. |
| A. | True |
| B. | False |
| Answer» B. False | |
| 4. |
What is the use of partial climbs? |
| A. | It is used for calculating climb rate |
| B. | It is used for calculating gradient of climb |
| C. | It is used for calculating speed |
| D. | It is used for calculating velocity |
| Answer» B. It is used for calculating gradient of climb | |
| 5. |
The advanced ratio is given by _______________ |
| A. | J=\(\frac{D}{nV}\) |
| B. | J=\(\frac{nV}{D}\) |
| C. | J=\(\frac{V}{nD}\) |
| D. | J=\(\frac{n}{VD}\) |
| Answer» D. J=\(\frac{n}{VD}\) | |
| 6. |
The rate of climb of an aircraft is measured by _______ |
| A. | variometer |
| B. | altimeter |
| C. | pitot-static prob |
| D. | gyroscope |
| Answer» B. altimeter | |
| 7. |
At which speed the maximum rate of climb occurs? |
| A. | u=0.76 |
| B. | u=0.98 |
| C. | u=1 |
| D. | u=2 |
| Answer» B. u=0.98 | |
| 8. |
The best rate of climb is attained at _____________ |
| A. | airspeed above maximum drag speed |
| B. | airspeed above maximum power speed |
| C. | airspeed above minimum power speed |
| D. | airspeed above minimum drag speed |
| Answer» D. airspeed above minimum drag speed | |
| 9. |
The best gradient of climb is attained at _____________ |
| A. | airspeed below maximum drag speed |
| B. | airspeed below maximum power speed |
| C. | airspeed below minimum power speed |
| D. | airspeed below minimum drag speed |
| Answer» E. | |
| 10. |
Which of the following is the correct performance equation for mixed power-plants? |
| A. | Emaxsinγ2=\(\Big[\frac{\lambda}{u}+\tau \Big]-\frac{1}{2}[u^2+u^{-2}]\) |
| B. | Emaxsinγ2=\(\Big[\frac{\lambda}{u}-\tau \Big]-\frac{1}{2}[u^2-u^{-2}]\) |
| C. | Emaxsinγ2=\(\Big[\frac{\lambda}{u}+\tau \Big]-\frac{1}{2}[u^2-u^{-2}]\) |
| D. | Emaxsinγ2=\(\Big[\frac{\lambda}{u}-\tau \Big]-\frac{1}{2}[u^2+u^{-2}]\) |
| Answer» B. Emaxsinγ2=\(\Big[\frac{\lambda}{u}-\tau \Big]-\frac{1}{2}[u^2-u^{-2}]\) | |