Which of the following is the correct performance equation for mixed power-plants?

Question

TuteeHUB · Accepted Answer

Emaxsinγ2=$\Big[\frac{\lambda}{u}-\tau \Big]-\frac{1}{2}[u^2-u^{-2}]$

TuteeHUB · Answer

Emaxsinγ2=$\Big[\frac{\lambda}{u}+\tau \Big]-\frac{1}{2}[u^2+u^{-2}]$

TuteeHUB · Answer

Emaxsinγ2=$\Big[\frac{\lambda}{u}-\tau \Big]-\frac{1}{2}[u^2-u^{-2}]$

TuteeHUB · Answer

Emaxsinγ2=$\Big[\frac{\lambda}{u}+\tau \Big]-\frac{1}{2}[u^2-u^{-2}]$

TuteeHUB · Answer

Emaxsinγ2=$\Big[\frac{\lambda}{u}-\tau \Big]-\frac{1}{2}[u^2+u^{-2}]$

1.	Which of the following is the correct performance equation for mixed power-plants?
A.	Emaxsinγ2=\(\Big[\frac{\lambda}{u}+\tau \Big]-\frac{1}{2}[u^2+u^{-2}]\)
B.	Emaxsinγ2=\(\Big[\frac{\lambda}{u}-\tau \Big]-\frac{1}{2}[u^2-u^{-2}]\)
C.	Emaxsinγ2=\(\Big[\frac{\lambda}{u}+\tau \Big]-\frac{1}{2}[u^2-u^{-2}]\)
D.	Emaxsinγ2=\(\Big[\frac{\lambda}{u}-\tau \Big]-\frac{1}{2}[u^2+u^{-2}]\)
Answer» B. Emaxsinγ2=\(\Big[\frac{\lambda}{u}-\tau \Big]-\frac{1}{2}[u^2-u^{-2}]\)

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