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MCQOPTIONS
This section includes 2374 Mcqs, each offering curated multiple-choice questions to sharpen your Embedded Systems knowledge and support exam preparation. Choose a topic below to get started.
| 251. |
Which of the following articles is not manufactured using riveting? |
| A. | Rail wagons |
| B. | Coaches |
| C. | Pressure vessels |
| D. | Helmets |
| Answer» E. | |
| 252. |
Which of the following method combines all the 2D transform methods into one using transform? |
| A. | combine() |
| B. | 2D-tranform() |
| C. | matrix() |
| D. | matrix-2D() |
| Answer» D. matrix-2D() | |
| 253. |
Which of the following transition-timing-function property lets you define your own values in a cubic-bezier function |
| A. | cubic(n,n,n,n) |
| B. | matrix(n,n,n,n) |
| C. | cubic-bezier(n,n,n,n) |
| D. | none of the mentioned |
| Answer» D. none of the mentioned | |
| 254. |
Which of the following transition-timing-function property specifies a transition effect with a slow start, then fast, then end slowly |
| A. | ease |
| B. | ease-in |
| C. | ease-in-out |
| D. | none of the mentioned |
| Answer» B. ease-in | |
| 255. |
Which of the following method skews an element along the X and Y-axis by the given angles using tranform? |
| A. | skewX() |
| B. | skewy() |
| C. | skew-X-Y() |
| D. | skew() |
| Answer» E. | |
| 256. |
Which of the following selector is used to select and style when you place mouse over it? |
| A. | focus |
| B. | hover |
| C. | mouse |
| D. | all of the mentioned |
| Answer» C. mouse | |
| 257. |
To convert its current output into a voltage, the DAC 0808 is connected with |
| A. | Transistor(BJT) externally |
| B. | FET externally |
| C. | OPAMP externally |
| D. | OPAMP internally |
| Answer» D. OPAMP internally | |
| 258. |
The number of scans of the complete 8-digit display that can be carried out in one second is |
| A. | 15 |
| B. | 25 |
| C. | 35 |
| D. | 55 |
| Answer» C. 35 | |
| 259. |
After the display is selected by second port, then the digit (LED) glows for a duration of |
| A. | 5 msec |
| B. | 10 msec |
| C. | 2 msec |
| D. | 6 msec |
| Answer» B. 10 msec | |
| 260. |
Which is true in interfacing 7 segment code display? |
| A. | transmitted by second port |
| B. | display is selected by third port |
| C. | display is selected by second port |
| D. | none of the mentioned |
| Answer» D. none of the mentioned | |
| 261. |
The number of LEDs that can be connected to a port of 8051, if all are expected to glow simultaneously is |
| A. | 6 |
| B. | 8 |
| C. | 10 |
| D. | 12 |
| Answer» C. 10 | |
| 262. |
If EA(active low) signal =1, then the execution starts from |
| A. | internal EPROM |
| B. | flash RAM |
| C. | internal EPROM or flash RAM |
| D. | none |
| Answer» D. none | |
| 263. |
Calculate the amount of heat absorbed by the cooling water, if it is supplied at the rate of 100000 kg/h and the rise in its temperature is observed to be 5°C. (Take cpw = 4.186 kJ/kg-K) |
| A. | 2093000 kJ/h |
| B. | 4653247 kJ/h |
| C. | 5478210 kJ/h |
| D. | 5462400 kJ/h |
| Answer» B. 4653247 kJ/h | |
| 264. |
Calculate the minimum amount of cooling water required if 3516240 kJ of heat is to be absorbed per hour and the rise in temperature should not be more than 7°C. Take cpw = 4.186 kJ/kg-K) |
| A. | 110000 kJ/h |
| B. | 120000 kJ/h |
| C. | 130000 kJ/h |
| D. | 140000 kJ/h |
| Answer» C. 130000 kJ/h | |
| 265. |
Dry and saturated steam (latent heat 2300 kJ/kg) at certain temperature is condensed to 32°C in a surface condenser. The ratio amount cooling water required to the amount of steam condensed is 112. Determine the temperature of the steam entering the condenser, the a temperature of cooling water rises by 5°C. (Take cpw = 4.186 kJ/kg-K) |
| A. | 52.55°C |
| B. | 42.55°C |
| C. | 32.55°C |
| D. | 22.55°C |
| Answer» C. 32.55°C | |
| 266. |
Following observations were made after carefully analyzing a jet condenser.Quantity of cooling water required = 700000 Kg/hLatent heat = 2500 kJ/KgSteam entering the condenser = 15000 kg/hTemperature of steam = 36°CTemperature of condensate = 30°CDetermine the rise in temperature of cooling water if the steam entering is dry and saturated.(cpw = 4.186 kJ/kg-K) |
| A. | 8.93°C |
| B. | 9.93°C |
| C. | 10.93°C |
| D. | 12.93°C |
| Answer» E. | |
| 267. |
Steam (latent heat 2400 kJ/kg) having temperature 40°C and dryness fraction 0.96 enters a jet condenser. Temperature of condensate is observed to be 35°C. If the temperature rise in the cooling water is 5°C, determine the ratio of amount of cooling water required to mass of steam condensed. (Take cpw = 4.186 kJ/kg-K) |
| A. | 88 |
| B. | 99 |
| C. | 111 |
| D. | 222 |
| Answer» D. 222 | |
| 268. |
In a jet condenser, the difference between the temperature of steam (dry and saturated) entering the condenser and the condensate leaving the condenser is 4°C. The amount of cooling water required and the mass of steam being supplied to the condenser are 900000 kg/hr and 12000 kg/hr. Take the latent heat of water to be 2300 kJ/kg and the specific heat at constant pressure to be 4.186 kJ/kg-K. If the temperature of cooling water entering the condenser is 26°C, determine the temperature of cooling water leaving the condenser. |
| A. | 35.65°C |
| B. | 33.38°C |
| C. | 45.54°C |
| D. | entering the condenser and the condensate leaving the condenser is 4°C. The amount of cooling water required and the mass of steam being supplied to the condenser are 900000 kg/hr and 12000 kg/hr. Take the latent heat of water to be 2300 kJ/kg and the specific heat at constant pressure to be 4.186 kJ/kg-K. If the temperature of cooling water entering the condenser is 26°C, determine the temperature of cooling water leaving the condenser.a) 35.65°Cb) 33.38°Cc) 45.54°Cd) 28.32°C |
| Answer» C. 45.54°C | |
| 269. |
A surface condenser is supplied with 10000 kg of wet steam per hour. the dryness fraction of the steam is 0.98. The latent heat of steam is 2000 kJ/kg. The quantity of cooling water required by the condenser is 950000 kg per hour. determine the rise in cooling water temperature, if the difference between the temperature of steam entering and condensate leaving the condenser is 10°C. Take cpw = 4.186 kJ/kg-K. |
| A. | 5°C |
| B. | 10°C |
| C. | 15°C |
| D. | 20°C |
| Answer» B. 10°C | |
| 270. |
A jet condenser is designed to handle 12000 kg of dry and saturated steam per hour. The steam enters the condenser at 38°C (dry and saturated), and the condensate leaves the condenser at 32°C. If the inlet temperature of cooling water is 10°C, find out the mass of cooling water required in kg per hour. Take latent heat of steam as 2300 kJ/kg and specific heat at constant pressure as 4.186 kJ/kg-°C. |
| A. | 302973 kg/hr |
| B. | 246185 kg/hr |
| C. | 876215 kg/hr |
| D. | , and the condensate leaves the condenser at 32°C. If the inlet temperature of cooling water is 10°C, find out the mass of cooling water required in kg per hour. Take latent heat of steam as 2300 kJ/kg and specific heat at constant pressure as 4.186 kJ/kg-°C.a) 302973 kg/hrb) 246185 kg/hrc) 876215 kg/hrd) 741963 kg/hr |
| Answer» B. 246185 kg/hr | |
| 271. |
Which of the following statements about the given expression is TRUE?mw=\(\frac{m_s\{xh_{fg}+c_{pw}(t_s-t_c)\}}{c_{pw}(t_{w2}-t_{w1})}\) |
| A. | It is used to calculate mass of cooling water required in jet condensers |
| B. | While deriving this expression, it is assumed that all the heat lost by steam is gained by cooling water |
| C. | \}}{c_{pw}(t_{w2}-t_{w1})}\) a) It is used to calculate mass of cooling water required in jet condensersb) While deriving this expression, it is assumed that all the heat lost by steam is gained by cooling waterc) ts is he saturation temperature of steam corresponding to the condenser vacuum. |
| D. | cpw represents specific heat of water at constant volume |
| Answer» C. \}}{c_{pw}(t_{w2}-t_{w1})}\) a) It is used to calculate mass of cooling water required in jet condensersb) While deriving this expression, it is assumed that all the heat lost by steam is gained by cooling waterc) ts is he saturation temperature of steam corresponding to the condenser vacuum. | |
| 272. |
Which of the following is the correct expression for finding out the quantity of cooling water required in surface condensers? |
| A. | mw=\(\frac{m_s\{xh_{fg}+c_{pw}(t_s-t_c)\}}{(t_{w2}-t_{w1})}\) |
| B. | mw=\(\frac{m_s\{xh_{fg}+c_{pw}(t_s-t_c)\}}{c_{pw}(t_{w1}-t_{w2})}\) c) mw=\(\frac{m_s\{xh_{fg}+c_{pw}(t_s-t_c)\}}{c_{pw}(t_{w2}-t_{w1})}\) d) mw=\(\frac{m_s\{h_{fg}+c_{pw}(t_s-t_ |
| C. | \}}{(t_{w2}-t_{w1})}\) b) mw=\(\frac{m_s\{xh_{fg}+c_{pw}(t_s-t_c)\}}{c_{pw}(t_{w1}-t_{w2})}\) c) mw=\(\frac{m_s\{xh_{fg}+c_{pw}(t_s-t_c)\}}{c_{pw}(t_{w2}-t_{w1})}\) |
| D. | mw=\(\frac{m_s\{h_{fg}+c_{pw}(t_s-t_c)\}}{c_{pw}(t_{w2}-t_{w1})}\) |
| Answer» D. mw=\(\frac{m_s\{h_{fg}+c_{pw}(t_s-t_c)\}}{c_{pw}(t_{w2}-t_{w1})}\) | |
| 273. |
Which of the following is the correct expression for finding out the quantity of cooling water required in jet condensers? |
| A. | mw=\(\frac{m_s\{xh_{fg}+c_{pw}(t_{w1}-t_{w2})\}}{c_{pw}(t_{w2}-t_{w1})}\) |
| B. | mw=\(\frac{m_s\{h_{fg}+c_{pw}(t_s-t_{w2})\}}{c_{pw} (t_{w2}-t_{w1})}\) |
| C. | mw=\(\frac{m_s\{xh_{fg}+c_{pw}(t_s-t_{w2})\}}{t_{w2}-t_{w1})}\) |
| D. | mw=\(\frac{m_s\{xh_{fg}+c_{pw}(t_s-t_{w2})\}}{c_{pw} (t_{w2}-t_{w1})}\) |
| Answer» E. | |
| 274. |
Consider the general discretized equation aPΦP=aWΦW+aEΦE+S. Which of these will become zero for the left boundary node? |
| A. | ΦE |
| B. | aE |
| C. | ΦW |
| D. | aW |
| Answer» E. | |
| 275. |
Which of these equations govern the problem of source-free one-dimensional steady-state heat conduction? |
| A. | \(\frac{d}{dx}(k\frac{dT}{dx})\) |
| B. | \(\frac{d}{dx}(k\frac{d\phi}{dx})\) |
| C. | \(\frac{d}{dx}(\Gamma\frac{dT}{dx})\) |
| D. | \(\frac{d}{dx}(\Gamma\frac{d\phi}{dx})\) |
| Answer» B. \(\frac{d}{dx}(k\frac{d\phi}{dx})\) | |
| 276. |
The general discretized equation is modified for ____________ |
| A. | the central control volume |
| B. | the boundary control volumes |
| C. | the non-boundary control volumes |
| D. | the interior control volumes |
| Answer» C. the non-boundary control volumes | |
| 277. |
Consider the following stencil. Get the discretized form of \((\frac{d\phi}{dx})_w\) using the central differencing scheme. |
| A. | \(\frac{\phi_P+\phi_W}{\delta x_{WP}}\) |
| B. | \(\frac{\phi_P-\phi_W}{2}\) |
| C. | \(\frac{\phi_P-\phi_W}{\delta x_WP}\) |
| D. | \(\frac{\phi_P+\phi_W}{2}\) |
| Answer» D. \(\frac{\phi_P+\phi_W}{2}\) | |
| 278. |
Consider the following stencil.Apply linear interpolation to the term Γe. |
| A. | \(\frac{\Gamma_e+\Gamma_E}{2}\) |
| B. | \(\frac{\Gamma_W+\Gamma_E}{2}\) |
| C. | \(\frac{\Gamma_P+\Gamma_W}{2}\) |
| D. | \(\frac{\Gamma_P+\Gamma_E}{2}\) |
| Answer» E. | |
| 279. |
Consider the following stencil.Discretize the diffusive term of the one-dimensional steady-state diffusion problem based on this stencil. (Note: Flow direction is from left to right). |
| A. | \((\Gamma\frac{d\phi}{dx})_e-(\Gamma\frac{d\phi}{dx})_w \) |
| B. | \((\Gamma \frac{d\phi}{dx})_E-(\Gamma\frac{d\phi}{dx})_W\) |
| C. | \((\Gamma A\frac{d\phi}{dx})_E-(\Gamma\frac{d\phi}{dx})_W\) |
| D. | \((\Gamma A\frac{d\phi}{dx})_e-(\Gamma\frac{d\phi}{dx})_w\) |
| Answer» E. | |
| 280. |
Which of these gives the statement of one-dimensional steady-state diffusion problem? |
| A. | The diffusive flux of Φ leaving the exit face is the same as the diffusive flux of Φ entering the inlet face |
| B. | The diffusive flux of Φ leaving the exit face plus the diffusive flux of Φ entering the inlet face is equal to the generation of Φ |
| C. | The diffusive flux of Φ leaving the exit face minus the diffusive flux of Φ entering the inlet face is equal to the generation of Φ |
| D. | The diffusive flux of Φ leaving the exit face is the same in magnitude and opposite in direction as the diffusive flux of Φ entering the inlet face |
| Answer» D. The diffusive flux of Φ leaving the exit face is the same in magnitude and opposite in direction as the diffusive flux of Φ entering the inlet face | |
| 281. |
Which of these theorems is used to transform the general diffusion term into boundary based integral in the FVM? |
| A. | Gauss divergence theorem |
| B. | Stokes’ theorem |
| C. | Kelvin-Stokes theorem |
| D. | Curl theorem |
| Answer» B. Stokes’ theorem | |
| 282. |
Which of these equations represent 1-D steady state diffusion? |
| A. | div(Γ grad Φ)+S=0 |
| B. | \(\frac{d}{dx}(\Gamma\frac{d\phi}{dx})+S=0\) |
| C. | \(\frac{d\phi}{dt}+\frac{d}{dx}(\Gamma\frac{d\phi}{dx})+S=0\) |
| D. | \(\frac{d\phi}{dt}+div(\Gamma grad\phi)+S=0\) |
| Answer» C. \(\frac{d\phi}{dt}+\frac{d}{dx}(\Gamma\frac{d\phi}{dx})+S=0\) | |
| 283. |
Which of these statements is true? |
| A. | 1-D steady-state diffusion is the simplest of all transport equations |
| B. | 1-D steady-state diffusion is the toughest of all transport equations |
| C. | 1-D steady-state convection is the simplest of all transport equations |
| D. | 1-D transient diffusion is the simplest of all transport equations |
| Answer» B. 1-D steady-state diffusion is the toughest of all transport equations | |
| 284. |
What is the value of pressure ratio if the pressure at point 1 and 2 is 1.809 and 3.467 bar, respectively? |
| A. | 1.916 |
| B. | 1.916 bar |
| C. | 0.521 |
| D. | 0.521 bar |
| Answer» B. 1.916 bar | |
| 285. |
What is the value of C.O.P. of high-temperature cascade system in terms of intermediate temperature in the following diagram?If TEL and TCL = Evaporator and condenser temperatures for low-temperature cascade systemTEH and TCH = Evaporator and condenser temperatures for high-temperature cascade system |
| A. | TEH / TCH – TCH |
| B. | TI / TCH – TI |
| C. | TCH / TI – TCH |
| D. | TEH / TI – TCH |
| Answer» C. TCH / TI – TCH | |
| 286. |
What is the value of C.O.P. of low-temperature cascade system in terms of intermediate temperature in the following diagram?If TEL and TCL = Evaporator and condenser temperatures for low-temperature cascade systemTEH and TCH = Evaporator and condenser temperatures for high-temperature cascade system |
| A. | TEL / TCL – TCL |
| B. | TCL / TCL – TEL |
| C. | TCL / TI – TCL |
| D. | TEL / TI – TCL |
| Answer» E. | |
| 287. |
What is the value of power required to drive the systems in the following diagram? |
| A. | m1 (h2 – h4) + m2 (h5 – h6) kW |
| B. | m1 (h2 – h1) + m2 (h8 – h1) kJ/s |
| C. | m1 (h2 – h1) + m2 (h6 – h5) kW |
| D. | m1 (h2 – h1) + m2 (h6 – h5) kJ/min |
| Answer» D. m1 (h2 – h1) + m2 (h6 – h5) kJ/min | |
| 288. |
What is the value of C.O.P. in the following diagram? |
| A. | 210 Q / m1 (h2 – h4) + m2 (h5 – h6) |
| B. | 210 Q / m1 (h2 – h7) + m2 (h6 – h8) |
| C. | 210 Q / m1 (h2 – h8) + m2 (h5 – h8) |
| D. | 210 Q / m1 (h2 – h1) + m2 (h6 – h5) |
| Answer» E. | |
| 289. |
What is the value of work done in the following diagram? |
| A. | m1 (h2 – h4) + m2 (h5 – h6) |
| B. | m1 (h2 – h1) + m2 (h6 – h5) |
| C. | m1 (h2 – h8) + m2 (h5 – h8) |
| D. | m1 (h2 – h5) + m2 (h4 – h8) |
| Answer» C. m1 (h2 – h8) + m2 (h5 – h8) | |
| 290. |
What is the value of m2 / m1 in the following diagram? |
| A. | (h2 – h4) / (h5 – h8) |
| B. | (h6 – h4) / (h7 – h8) |
| C. | (h1 – h4) / (h6 – h8) |
| D. | (h2 – h1) / (h1 – h8) |
| Answer» B. (h6 – h4) / (h7 – h8) | |
| 291. |
What is the value of m1 in the following diagram? |
| A. | 210 Q / (h1 – h7) kg/min |
| B. | 210 Q / (h1 – h4) kg/s |
| C. | 210 Q / (h1 – h4) kg/min |
| D. | 210 Q / (h1 – h7) kg/s |
| Answer» D. 210 Q / (h1 – h7) kg/s | |
| 292. |
Cascade refrigeration system reduces the C.O.P. |
| A. | True |
| B. | False |
| Answer» C. | |
| 293. |
How is the cascade system achieved? |
| A. | VCR system in a parallel combination |
| B. | VAR system in a series combination |
| C. | VAR system in a parallel combination |
| D. | VCR system in a series combination |
| Answer» E. | |
| 294. |
Multiple refrigerants can be used in the cascade refrigeration system. |
| A. | True |
| B. | False |
| Answer» B. False | |
| 295. |
A safety valve for a dam to discharge major floods is called? |
| A. | Spillway |
| B. | Penstock |
| C. | Fore bay |
| D. | Canal |
| Answer» B. Penstock | |
| 296. |
Which type of penstocks is less expensive? |
| A. | Buried penstock |
| B. | Covered penstock |
| C. | Open penstock |
| D. | Exposed penstock |
| Answer» E. | |
| 297. |
Which type of penstock is used in cold climates? |
| A. | Buried penstock |
| B. | Covered penstock |
| C. | Open penstock |
| D. | Exposed penstock |
| Answer» B. Covered penstock | |
| 298. |
Presence of Corrosive gases like H2S and SO2 affect the voltage drop. |
| A. | True |
| B. | False |
| Answer» B. False | |
| 299. |
Water containing H2S, CO2 and CH2 are less corrosive to dam structure. |
| A. | True |
| B. | False |
| Answer» C. | |
| 300. |
Water gets polluted by submerged vegetation mineral. |
| A. | True |
| B. | False |
| Answer» B. False | |