MCQOPTIONS
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MCQOPTIONS
This section includes 97 Mcqs, each offering curated multiple-choice questions to sharpen your Computer Fundamentals knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Which of the following is the correct representation of a binary number? |
| A. | (124)2 |
| B. | 1110 |
| C. | (110)2 |
| D. | (000)2 |
| Answer» E. | |
| 2. |
Which of the following is not a binary number? |
| A. | 1111 |
| B. | 101 |
| C. | 11E |
| D. | 000 |
| Answer» D. 000 | |
| 3. |
Convert the binary equivalent 10101 to its decimal equivalent. |
| A. | 21 |
| B. | 12 |
| C. | 22 |
| D. | 31 |
| Answer» B. 12 | |
| 4. |
Which of the following is not a positional number system? |
| A. | Roman Number System |
| B. | Octal Number System |
| C. | Binary Number System |
| D. | Hexadecimal Number System |
| Answer» B. Octal Number System | |
| 5. |
Decimal equivalent of Hexadecimal number (C3B1)16 is |
| A. | 12197 |
| B. | 32097 |
| C. | 52097 |
| D. | 50097 |
| Answer» E. | |
| 6. |
100.63 in Decimal System can be written in Binary Systems as |
| A. | (1100001.101)2 |
| B. | (1100110.101)2 |
| C. | (1100100.101)2 |
| D. | (1100100.101)2 |
| Answer» D. (1100100.101)2 | |
| 7. |
Convert the Hexadecimal number 4DF to its octal equivalent |
| A. | 2333 |
| B. | 2337 |
| C. | 2773 |
| D. | 2373 |
| Answer» C. 2773 | |
| 8. |
Consider the equation (43)x = (y3)8 where x and y are unknown. The number of possible solution is |
| A. | 4 |
| B. | 6 |
| C. | 5 |
| D. | 7 |
| Answer» D. 7 | |
| 9. |
Binary 11110 equals ____ in hexadecimal |
| A. | 2A |
| B. | 2E |
| C. | 1E |
| D. | 2C |
| Answer» D. 2C | |
| 10. |
If (11X1Y)8 = (12C9)16 then the values X and Y are |
| A. | 3 and 1 |
| B. | 5 and 7 |
| C. | 7 and 5 |
| D. | 1 and 5 |
| Answer» B. 5 and 7 | |
| 11. |
Add 8 and 9 in the BCD code. |
| A. | 00010111 |
| B. | 00010001 |
| C. | 01110111 |
| D. | 10001001 |
| Answer» B. 00010001 | |
| 12. |
(734)8 = (?)16 |
| A. | C 1 D |
| B. | D C 1 |
| C. | 1 C D |
| D. | 1 D C |
| Answer» E. | |
| 13. |
If the constraint length of a (n, k, L) convolutional code is defined as the number of encoder output bits influenced by each message bit, then the constraint length is given by |
| A. | L(n + 1) |
| B. | n(L + 1) |
| C. | n(L + k) |
| D. | L(n + k) |
| Answer» C. n(L + k) | |
| 14. |
Decimal 15 equals ____ in binary. |
| A. | 0111 |
| B. | 1111 |
| C. | 1011 |
| D. | 1101 |
| Answer» C. 1011 | |
| 15. |
Decimal number 1375 in its octal form is |
| A. | 2357 |
| B. | 2537 |
| C. | 3257 |
| D. | 4257 |
| Answer» C. 3257 | |
| 16. |
How many bytes are there in binary number 1001101000111010? |
| A. | 1 |
| B. | 2 |
| C. | 3 |
| D. | 4 |
| Answer» C. 3 | |
| 17. |
________ can detect burst error of length less than or equal to degree of the polynomial and detects burst errors that affect odd number of bits. |
| A. | Hamming Code |
| B. | CRC |
| C. | VRC |
| D. | None of the above |
| Answer» C. VRC | |
| 18. |
220 bytes and 240 bytes are respectively equal to _________ and _________ |
| A. | 1MB, 1TB |
| B. | 1GB, 1TB |
| C. | 1KB, 1GB |
| D. | 1MB, 1GB |
| Answer» B. 1GB, 1TB | |
| 19. |
(1111.11)2 equals |
| A. | -1.011 |
| B. | 0.751 |
| C. | 15.31 |
| D. | 15.751 |
| Answer» E. | |
| 20. |
In the following figure, the output in decimal will be |
| A. | 255 |
| B. | 127 |
| C. | 31 |
| D. | zero |
| Answer» C. 31 | |
| 21. |
One byte equals to ______ bits. |
| A. | 16 |
| B. | 8 |
| C. | 32 |
| D. | 10 |
| Answer» C. 32 | |
| 22. |
A byte is |
| A. | a group of 2 bits |
| B. | a group of 4 bits |
| C. | a group of 8 bits |
| D. | a group of 16 bits |
| Answer» D. a group of 16 bits | |
| 23. |
Convert hex number to decimal.(0101)16 |
| A. | 572 |
| B. | 527 |
| C. | 257 |
| D. | 253 |
| Answer» D. 253 | |
| 24. |
Convert the binary number 11000110 to Gray code. |
| A. | 00100101 |
| B. | 10100100 |
| C. | 11100110 |
| D. | 10100101 |
| Answer» E. | |
| 25. |
Choose the correct option for the following two statements:A: 1’s complement circuit is more complex than that of 2’s complement method.B: The extra carry is considered in 1’s complement whereas it is disregarded in 2’s complement method. |
| A. | Both are true |
| B. | A is true, B is false |
| C. | B is true, A is false |
| D. | Both are false |
| Answer» D. Both are false | |
| 26. |
Extended ASCII code has _____ bits and provision of a maximum of ______ symbols respectively. |
| A. | 8, 256 |
| B. | 8, 128 |
| C. | 7, 128 |
| D. | 16, 256 |
| Answer» B. 8, 128 | |
| 27. |
If (1235)x = (3033)y, where x and y indicate the bases of the corresponding numbers, then |
| A. | x = 9 and y = 7 |
| B. | x = 8 and y = 6 |
| C. | x = 7 and y = 5 |
| D. | x = 6 and y = 4 |
| Answer» C. x = 7 and y = 5 | |
| 28. |
In excess-three code, the 4-bit group that is used is ____. |
| A. | 0011 |
| B. | 0010 |
| C. | 1110 |
| D. | 0001 |
| Answer» B. 0010 | |
| 29. |
BCD code has always how many bits per number |
| A. | 2 |
| B. | 4 |
| C. | 8 |
| D. | 16 |
| Answer» C. 8 | |
| 30. |
How many bits are required to represents 99999 in BCD form? |
| A. | 10 |
| B. | 20 |
| C. | 32 |
| D. | 41 |
| Answer» C. 32 | |
| 31. |
4F2D is a/an ___________ number. |
| A. | decimal |
| B. | octal |
| C. | binary |
| D. | hexadecimal |
| Answer» E. | |
| 32. |
Based on the paragraph given below answer the following question:The traditional methods of combinational circuits involve simplification and realization using gates. Using these methods, complex functions have been integrated and are easily available in IC form. There is an attractive array of devices like a multiplexer, demultiplexer, decoders, comparators, parity generators/checkers, which significantly reduce IC package count thereby reducing the system cost. The system design is greatly simplified because the laborious and time-consuming simplification methods are generally not required with these devices. This also improves the reliability of the system by reducing the number of external wired connections. But they have some limitations as well. Different memories like ROM, PROM can also be used to implement combinational circuits without much simplification.In a BCD Subtractor if the sum of minuend and the nine’s complement of the subtrahend is not a valid BCD Code, then which binary number is added to the sum to get the correct answer? |
| A. | 1000 |
| B. | 0001 |
| C. | 0110 |
| D. | 0111 |
| Answer» D. 0111 | |
| 33. |
P, Q, and R are the decimal integers corresponding to the 4-bit binary number 1100 considered in signed magnitude, 1’s complement, and 2’s complement representations, respectively. The 6-bit 2’s complement representation of (P + Q + R) is |
| A. | 110101 |
| B. | 110010 |
| C. | 111101 |
| D. | 111001 |
| Answer» B. 110010 | |
| 34. |
In which digital code is decimal digit expressed by 4 binary digits. |
| A. | BCD code |
| B. | Binary code |
| C. | ASCII code |
| D. | Gray code |
| Answer» B. Binary code | |
| 35. |
Binary equivalent of Gray code number 0101 is |
| A. | 1101 |
| B. | 1100 |
| C. | 1001 |
| D. | 0110 |
| Answer» E. | |
| 36. |
A binary number system with 2n bits, all of the which are 1's has the value. |
| A. | 22n - 1 |
| B. | 22n |
| C. | 22n + 1 |
| D. | 2 × 2n-1 |
| Answer» B. 22n | |
| 37. |
BCD equivalent of (345)10 is: |
| A. | 0011 1001 1010 |
| B. | 1001 1001 1111 |
| C. | 0011 0100 0101 |
| D. | 0101 1100 1001 |
| Answer» D. 0101 1100 1001 | |
| 38. |
Evaluate 1101112/1012 |
| A. | 11102 |
| B. | 10102 |
| C. | 11112 |
| D. | 10012 |
| Answer» C. 11112 | |
| 39. |
Find the complement of A + A̅ B |
| A. | B |
| B. | \( \overline { A B }\) |
| C. | \( \overline { A +B }\) |
| D. | A |
| Answer» D. A | |
| 40. |
Directions: The question consists of two statements, one labeled as ‘Statement (I)’ and the other labeled as ‘Statement (II)’. You are to examine these two statements carefully and select the answers to these items using the codes given below:Statement (I): The hexadecimal numbers are first converted into binary numbers and operations are performed using the binary representation of hexadecimal numbers using rules of binary numbers.Statement (II): The information can be handled in hexadecimal form in digital circuits but it is easier to enter information using binary numbers. |
| A. | Both Statement (I) and Statement (II) are individually true and Statement (II) is the correct explanation of Statement (I). |
| B. | Both Statement (I) and Statement (II) are individually true, but Statement (II) is not the correct explanation of Statement (I). |
| C. | Statement (I) is true, but Statement (II) is false. |
| D. | Statement (I) is false, but Statement (II) is true. |
| Answer» D. Statement (I) is false, but Statement (II) is true. | |
| 41. |
Binary addition of 16 and -83 using 2’s compliment results in: |
| A. | -10000112 |
| B. | 10000112 |
| C. | 10000102 |
| D. | -10000102 |
| Answer» B. 10000112 | |
| 42. |
Given (135)base x + (144)base x = (323)base xWhat is the value of base x? |
| A. | 5 |
| B. | 3 |
| C. | 12 |
| D. | 6 |
| Answer» E. | |
| 43. |
2's complement of -7 is |
| A. | 0111 |
| B. | 1000 |
| C. | 1111 |
| D. | 1001 |
| Answer» E. | |
| 44. |
If (110)x = (132)4, then x = |
| A. | 8 |
| B. | 5 |
| C. | 4 |
| D. | 9 |
| Answer» C. 4 | |
| 45. |
How many different symbols (digits/characters) are used in a base-N number system? |
| A. | N -2 |
| B. | N |
| C. | N - 1 |
| D. | N + 1 |
| Answer» C. N - 1 | |
| 46. |
How many nibbles are there in 16 bits? |
| A. | 2 |
| B. | 16 |
| C. | 8 |
| D. | 4 |
| Answer» E. | |
| 47. |
Hexadecimal conversion of (430.25)8 gives ______ |
| A. | (108.54)16 |
| B. | (118.54)16 |
| C. | (108.44)16 |
| D. | (118.44)16 |
| Answer» C. (108.44)16 | |
| 48. |
Hexadecimal conversion of decimal number 227 will be |
| A. | A3 |
| B. | E3 |
| C. | CC |
| D. | C3 |
| Answer» C. CC | |
| 49. |
If 73x (in base x number system) is equal to 54y (in base y number system), the possible values of x and y are |
| A. | 8 and 16 |
| B. | 10 and 12 |
| C. | 9 and 13 |
| D. | 8 and 11 |
| Answer» E. | |
| 50. |
BCD equivalent of decimal number 43 is |
| A. | 101 011 |
| B. | 1000 0011 |
| C. | 0100 0011 |
| D. | 0011 0100 |
| Answer» D. 0011 0100 | |