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This section includes 97 Mcqs, each offering curated multiple-choice questions to sharpen your Computer Fundamentals knowledge and support exam preparation. Choose a topic below to get started.
51. |
Determine the octal equivalent of (432267)10? |
A. | (432267)8 |
B. | (346731)8 |
C. | (2164432)8 |
D. | (1514213)8 |
E. | (2168432)8 |
Answer» E. (2168432)8 | |
52. |
If 52/4 = 12, the base of the number system is |
A. | 4 |
B. | 5 |
C. | 6 |
D. | 8 |
Answer» D. 8 | |
53. |
In a binary number system, how much does nibble mean? |
A. | 8 bits |
B. | 4 bits |
C. | 16 bits |
D. | 1 bit |
Answer» C. 16 bits | |
54. |
Find the decimal equivalent of the 6-bit binary number (111.001)2 |
A. | 5.251 |
B. | 7.1251 |
C. | 5.6251 |
D. | 7.6251 |
Answer» C. 5.6251 | |
55. |
In Binary-coded Decimal (BCD) systems, the decimal number 81 is represented as |
A. | 10000001 |
B. | 10100010 |
C. | 01010001 |
D. | 00011000 |
Answer» B. 10100010 | |
56. |
Conversion of +1000 decimal number into signed binary word results |
A. | 0000 0011 1110 1000 |
B. | 1000 0011 1110 1000 |
C. | 1111 1100 0001 1000 |
D. | 0111 1100 0001 1000 |
Answer» B. 1000 0011 1110 1000 | |
57. |
Binary data is being represented in size of byte and in 2’s complement form. The number of 0’s present in representation of (-127)decimal is |
A. | 8 |
B. | 7 |
C. | 6 |
D. | 5 |
Answer» D. 5 | |
58. |
Binary code of decimal number 27 would be |
A. | 010110 |
B. | 011011 |
C. | 110110 |
D. | 101010 |
Answer» C. 110110 | |
59. |
Choose invalid statement: |
A. | (32.2)4 = (14.5)10 |
B. | (356)8 = (EE)16 |
C. | (58.6)10 = (3B.C)16 |
D. | (101011)2 = (53)8 |
Answer» D. (101011)2 = (53)8 | |
60. |
FG in Hexadecimal Systems can be written in Binary System as |
A. | 11111100 |
B. | 11110011 |
C. | 11111111 |
D. | Not a valid Hexadecimal Number |
Answer» E. | |
61. |
On dividing (101011)2 by (11)2 the quotient and remainder respectively are: |
A. | (1110)2 and (1)2 |
B. | (1101)2 and (0)2 |
C. | (1110)2 and (0)2 |
D. | (1011)2 and (1)2 |
Answer» B. (1101)2 and (0)2 | |
62. |
Match List-I with List-II:List-IList-IIa)Baudot codei)Permits the correction of errors by receiver without retransmissionb)Hamming codeii)Provides no error detection at allc)Error detecting codeiii)Permits the detection of two errors or correction of only one errord)Forward error-correcting codeiv)Uses an extra parity bit at the end of each word to detect errors in received dataChoose the correct option from those given below: |
A. | a-ii; b-iii; c-iv; d-i |
B. | a-iii; b-ii; c-i; d-iv |
C. | a-iv; b-ii; c-i; d-iii |
D. | a-ii; b-iii; c-i; d-iv |
Answer» B. a-iii; b-ii; c-i; d-iv | |
63. |
A Frequency Hopping Spread Spectrum system has its frequency synthesizers controlled by five stage shift-registers with feedback connections taken from the second and fifth stages. The number of slots available for frequency hopping is: |
A. | 32 |
B. | 31 |
C. | 24 |
D. | 28 |
Answer» B. 31 | |
64. |
Decimal number 73 may be written in a binary system as |
A. | 1001010 |
B. | 1001001 |
C. | 1001011 |
D. | 100011 |
Answer» C. 1001011 | |
65. |
0110 in binary form can be written as _________ in decimal form. |
A. | 4 |
B. | 5 |
C. | 6 |
D. | 7 |
Answer» D. 7 | |
66. |
An 8085 microprocessor executes the following instructions:Two numbers are represented in signed 2’s complement form asP = 11101101 and Q = 11100110If Q is subtracted from P, the value obtained in signed 2’s complement form is |
A. | 100000111 |
B. | 00000111 |
C. | 11111001 |
D. | 011111001 |
Answer» C. 11111001 | |
67. |
In context of error detection and correction in computer networks, CRC stands for: |
A. | Cyclic Reduction Code |
B. | Cyclic Redundancy Check |
C. | Cyber Request Check |
D. | Cyber Repetition Code |
Answer» C. Cyber Request Check | |
68. |
A device which converts BCD to seven segment is called ______ |
A. | Encoder |
B. | Decoder |
C. | Multiplexer |
D. | Demultiplexer |
Answer» C. Multiplexer | |
69. |
Binary number (1101)2 when added to another binary number (101)2 yields |
A. | 10011 |
B. | 10010 |
C. | 11010 |
D. | 11001 |
Answer» C. 11010 | |
70. |
Let 312 as a number in the base-B number system, where B is unknown. If (312)B = (54)10, then what is the value of the base B? |
A. | 6 |
B. | 5 |
C. | 4 |
D. | 12 |
Answer» D. 12 | |
71. |
Find the sum of binary number 1010 and 0011 |
A. | 1021 |
B. | 1101 |
C. | 1011 |
D. | 1111 |
Answer» C. 1011 | |
72. |
If (211)x = (152)8, then the value of base x is |
A. | 6 |
B. | 5 |
C. | 7 |
D. | 9 |
Answer» D. 9 | |
73. |
Addition of the hexadecimal numbers (DEF. 12)16 and (12 EF.C)16 gives: |
A. | (20DE.B2)16 |
B. | (20DE.E2)16 |
C. | (20DE.D2)16 |
D. | (20DE.C2)16 |
Answer» C. (20DE.D2)16 | |
74. |
Of the following, which is the binary equivalent of the decimal number 368? |
A. | 101110000 |
B. | 110110000 |
C. | 111010000 |
D. | 111100000 |
Answer» B. 110110000 | |
75. |
Conversion of decimal number 6110 to its binary number equivalent is |
A. | 1100112 |
B. | 110011102 |
C. | 1111012 |
D. | 111112 |
Answer» D. 111112 | |
76. |
Find the decimal equivalent of the 6-bit binary number (101.101)2 |
A. | 5.2510 |
B. | 5.12510 |
C. | 5.62510 |
D. | 6.62510 |
Answer» D. 6.62510 | |
77. |
(B2F8)16 = (?)10What should come in the place of question mark? |
A. | 51246 |
B. | 45816 |
C. | 32678 |
D. | 10240 |
Answer» C. 32678 | |
78. |
In an 8 bit two’s complement number system, inversion of all 8 bits occur during code transition |
A. | from -127 to -128 |
B. | from 0 to +127 |
C. | from +126 to +127 |
D. | from -1 to 0 |
Answer» E. | |
79. |
In context of computer networks, which of the following is not an error correcting code? |
A. | Binary convolution codes |
B. | Low density parity check codes |
C. | Reed-Soloman codes |
D. | None of these |
Answer» E. | |
80. |
In CRC if the data unit is 100111001 and the divisor is 1011 then what is dividend at the receiver? |
A. | 100111001101 |
B. | 100111001011 |
C. | 100111001 |
D. | 100111001110 |
Answer» C. 100111001 | |
81. |
Multiplication of 2 binary numbers A and B yields 11001; if A is 101, then B is |
A. | 101 |
B. | 111 |
C. | 110 |
D. | None of these |
Answer» B. 111 | |
82. |
Excess-3 code for decimal number 7 is: |
A. | 1110 |
B. | 1010 |
C. | 1011 |
D. | 1100 |
Answer» C. 1011 | |
83. |
Match the following list:List – I (Octal)List – II (Decimal)a) 35i) 53b) 65ii) 62c) 54iii) 29d) 76iv) 44 Correct code are: |
A. | (a) – (iii), (b) – (ii), (c) – (iv), (d) – (i) |
B. | (a) – (iv), (b) – (iii), (c) – (ii), (d) – (i) |
C. | (a) – (ii), (b) – (iii), (c) – (i), (d) – (iv) |
D. | (a) – (iii), (b) – (i), (c) – (iv), (d) – (ii) |
Answer» E. | |
84. |
If N is a 16-bit signed integer, The 2’s complement representation of N is (F87B)16.The 2’s complement representation of 8*N is ________ |
A. | (𝐶3𝐷8)16 |
B. | (187B)16 |
C. | (F878)16 |
D. | (987B)16 |
Answer» B. (187B)16 | |
85. |
A hexadecimal number system is |
A. | an obsolete system no longer in use |
B. | widely used in analysing and programming microprocessors |
C. | used in calculators only |
D. | none of these |
Answer» C. used in calculators only | |
86. |
If (146)x + (313)x-2 = (246)8, then the value of base x is: |
A. | 5 |
B. | 6 |
C. | 7 |
D. | 9 |
Answer» D. 9 | |
87. |
Match the following list: List – I(Codes) List – II(No. of Bits used)(a)Baudot code(i)7 bits(b)ASCII code(ii)5 bits(c)EBCDIC code(iii)10 digits(d)Code 39(iv)8 bits |
A. | (a) – (ii), (b) – (i), (c) – (iv), (d) – (iii) |
B. | (a) – (i), (b) – (ii), (c) – (iii), (d) – (iv) |
C. | (a) – (ii), (b) – (i), (c) – (iii), (d) – (iv) |
D. | (a) – (iv), (b) – (iii), (c) – (ii), (d) – (i) |
Answer» B. (a) – (i), (b) – (ii), (c) – (iii), (d) – (iv) | |
88. |
WHICH_OF_THE_FOLLOWING_IS_NOT_A_BINARY_NUMBER??$ |
A. | 1111 |
B. | 101 |
C. | 11E |
D. | 000 |
Answer» D. 000 | |
89. |
Which_of_the_following_is_the_correct_representation_of_a_binary_number?$ |
A. | (124)<sub>2</sub> |
B. | 1110 |
C. | (110)<sup>2</sup> |
D. | (000)<sub>2</sub> |
Answer» E. | |
90. |
Convert the binary equivalent 10101 to its decimal equivalent? |
A. | 21 |
B. | 12 |
C. | 22 |
D. | 31 |
Answer» B. 12 | |
91. |
A bit in a computer terminology means either 0 or 1. |
A. | True |
B. | False |
Answer» B. False | |
92. |
The input hexadecimal representation of 1110 is _______________ |
A. | 0111 |
B. | E |
C. | 15 |
D. | 14 |
Answer» C. 15 | |
93. |
The octal equivalent of 1100101.001010 is ______ |
A. | 624.12 |
B. | 145.12 |
C. | 154.12 |
D. | 145.21 |
Answer» C. 154.12 | |
94. |
A computer language that is written in binary codes only is _____ |
A. | machine language |
B. | C |
C. | C |
D. | pascal |
Answer» B. C | |
95. |
The binary equivalent of the decimal number 10 is __________ |
A. | 0010 |
B. | 10 |
C. | 1010 |
D. | 010 |
Answer» D. 010 | |
96. |
The value of radix in binary number system is _____________ |
A. | 2 |
B. | 8 |
C. | 10 |
D. | 1 |
Answer» B. 8 | |
97. |
Which of the following is not a positional number system? |
A. | Roman Number System |
B. | Octal Number System |
C. | Binary Number System |
D. | Hexadecimal Number System |
Answer» B. Octal Number System | |