MCQOPTIONS
Saved Bookmarks
MCQOPTIONS
This section includes 13 Mcqs, each offering curated multiple-choice questions to sharpen your Manufacturing Processes knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
What will be the indexing to cut 30 teeth on a gear using simple indexing method? |
| A. | Rotate indexing crank by 5 holes in 15 holes circle |
| B. | Rotate indexing crank by 10 holes in 15 holes circle |
| C. | Rotate indexing crank by one complete turn and 7 holes in 21 holes circle |
| D. | Rotate indexing crank by one complete turn and 10 holes in 15 holes circle |
| Answer» D. Rotate indexing crank by one complete turn and 10 holes in 15 holes circle | |
| 2. |
How many indexing methods are there for cutting a gear? |
| A. | 2 |
| B. | 4 |
| C. | 6 |
| D. | 8 |
| Answer» C. 6 | |
| 3. |
Face hobbed bevel gear sets tend to have their involute point location_____ |
| A. | on the flank centre |
| B. | on the addendum circle |
| C. | between addendum and dedendum circle |
| D. | between flank centre and the heel |
| Answer» E. | |
| 4. |
HOW_MANY_INDEXING_METHODS_ARE_THERE_FOR_CUTTING_A_GEAR??$ |
| A. | 2 |
| B. | 4 |
| C. | 6 |
| D. | 8 |
| Answer» C. 6 | |
| 5. |
What will be the indexing to cut 30 teeth on a gear using simple indexing method?$ |
| A. | Rotate indexing crank by 5 holes in 15 holes circle |
| B. | Rotate indexing crank by 10 holes in 15 holes circle |
| C. | Rotate indexing crank by one complete turn and 7 holes in 21 holes circle |
| D. | Rotate indexing crank by one complete turn and 10 holes in 15 holes circle |
| Answer» D. Rotate indexing crank by one complete turn and 10 holes in 15 holes circle | |
| 6. |
Face hobbed bevel gear sets tend to have their involute point location____? |
| A. | on the flank centre |
| B. | on the addendum circle |
| C. | between addendum and dedendum circle |
| D. | between flank centre and the heel |
| Answer» E. | |
| 7. |
It is possible to grind face hobbed gears. |
| A. | True |
| B. | False |
| Answer» C. | |
| 8. |
Which of the following is a result of the constant relative indexing motion between cutter and workpiece? |
| A. | Un-equal tooth thickness taper |
| B. | Un-equal slot width taper |
| C. | Equal slot width taper and un-equal tooth thickness taper |
| D. | Natural sloth width taper and equal tooth thickness taper |
| Answer» E. | |
| 9. |
Face hobbed gear sets are manufactured as continues indexing. |
| A. | True |
| B. | False |
| Answer» B. False | |
| 10. |
What causes an un-proportionally thin and high tooth in the toe region, and a short and thick tooth at the heel? |
| A. | Difference in PCDs of the generating gears |
| B. | Error in indexing while manufacturing |
| C. | Difference in outer and inner circumference of the generating gear |
| D. | Difference in feed rates |
| Answer» D. Difference in feed rates | |
| 11. |
A certain tooth depth taper is applied in all face milled completing bevel gears. |
| A. | True |
| B. | False |
| Answer» B. False | |
| 12. |
Face milled gear sets are manufactured in_____ |
| A. | Single-indexing—one slot at a time |
| B. | Single-indexing¬—two slots at a time |
| C. | Double-indexing—two slots at a time |
| D. | All the slots at a time |
| Answer» B. Single-indexing¬¨¬®¬¨¬Æ‚Äö√Ñ√∂‚àö√ë‚àö√Ütwo slots at a time | |
| 13. |
Which of the following methods delivers the better rolling performance and higher strength of the manufactured bevel gear? |
| A. | Face milling completing and hard finishing by grinding |
| B. | Face hobbing and hard finishing by lapping |
| C. | Face milling with five-cut and hard finishing by lapping |
| D. | Face milling completing and hard finishing by lapping |
| Answer» B. Face hobbing and hard finishing by lapping | |