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This section includes 17 Mcqs, each offering curated multiple-choice questions to sharpen your Network Theory knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Determine the value of R2 in terms of R0 and N in the circuit shown below is? |
| A. | R2 = NR0/(N2-1) |
| B. | R2 = 2 NR0/(N2-1) |
| C. | R2 = 3 NR0/(N2-1) |
| D. | R2 = 4 NR0/(N2-1) |
| Answer» C. R2 = 3 NR0/(N2-1) | |
| 2. |
Determine the value of R1 in terms of R0 and N in the circuit shown below is? |
| A. | R1 = R0(N-1)/(N+1) |
| B. | R1 = R0(N+1)/(N+1) |
| C. | R1 = R0(N-1)/(N-1) |
| D. | R1 = R0(N+1)/(N-1) |
| Answer» B. R1 = R0(N+1)/(N+1) | |
| 3. |
The value of the characteristic impedance R0 in terms of R1 and R2 and R0 in the circuit shown below is? |
| A. | R1+R2(R1+R0)/(R1+R0+R2) |
| B. | R1+ R2(R1+R0)/(R1+R0+R2) |
| C. | R2+ R2(R1+R0)/(R1+R0+R2) |
| D. | R0+R2(R1+R2)/(R1+R0+R2) |
| Answer» C. R2+ R2(R1+R0)/(R1+R0+R2) | |
| 4. |
Determine the value of N in the circuit shown below. |
| A. | (R1+R2-R0)/R2 |
| B. | (R1-R2-R0)/R2 |
| C. | (R1+R2+R0)/R2 |
| D. | (R1-R2+R0)/R2 |
| Answer» D. (R1-R2+R0)/R2 | |
| 5. |
In the circuit shown below, find the value of I1/I2. |
| A. | (R1-R2+R0)/R2 |
| B. | (R1+R2+R0)/R2 |
| C. | (R1-R2-R0)/R2 |
| D. | (R1+R2-R0)/R2 |
| Answer» C. (R1-R2-R0)/R2 | |
| 6. |
The value of one decibel is equal to? |
| A. | log10 (N) |
| B. | 10 log10 (N) |
| C. | 20 log10 (N) |
| D. | 40 log10 (N) |
| Answer» D. 40 log10 (N) | |
| 7. |
What is the attenuation in dB assuming I1 is the input current and I2 is the output current leaving the port? |
| A. | 10 log10 (I1/I2) |
| B. | 10 log10 (I2/I1) |
| C. | 20 log10 (I2/I1) |
| D. | 20 log10 (I1/I2) |
| Answer» E. | |
| 8. |
If V1 is the voltage at port 1 and V2 is the voltage at port 2, then the attenuation in dB is? |
| A. | 20 log10 (V1/V2) |
| B. | 10 log10 (V1/V2) |
| C. | 20 log10 (V2/V1) |
| D. | 10 log10 (V2/V1) |
| Answer» B. 10 log10 (V1/V2) | |
| 9. |
The attenuation in dB in terms of input power (P1) and output power (P2) is? |
| A. | log10 (P1/P2) |
| B. | 10 log10 (P1/P2) |
| C. | log10 (P2/P1) |
| D. | 10 log10 (P2/P1) |
| Answer» C. log10 (P2/P1) | |
| 10. |
DETERMINE_THE_VALUE_OF_R2_IN_TERMS_OF_R0_AND_N_IN_THE_CIRCUIT_SHOWN_IN_QUESTION_6_IS??$ |
| A. | R<sub>2</sub>= NR<sub>0</sub>/(N<sup>2</sup>-1) |
| B. | R<sub>2</sub>= 2 NR<sub>0</sub>/(N<sup>2</sup>-1) |
| C. | R<sub>2</sub>= 3 NR<sub>0</sub>/(N<sup>2</sup>-1) |
| D. | R<sub>2</sub>= 4 NR<sub>0</sub>/(N<sup>2</sup>-1) |
| Answer» C. R<sub>2</sub>= 3 NR<sub>0</sub>/(N<sup>2</sup>-1) | |
| 11. |
DETERMINE_THE_VALUE_OF_R1_IN_TERMS_OF_R0_AND_N_IN_THE_CIRCUIT_SHOWN_IN_QUESTION_6_IS??$ |
| A. | R<sub>1</sub>= R<sub>0</sub>(N-1)/(N+1) |
| B. | R<sub>1</sub>= R<sub>0</sub>(N+1)/(N+1) |
| C. | R<sub>1</sub>= R<sub>0</sub>(N-1)/(N-1) |
| D. | R<sub>1</sub>= R<sub>0</sub>(N+1)/(N-1) |
| Answer» B. R<sub>1</sub>= R<sub>0</sub>(N+1)/(N+1) | |
| 12. |
The value of the characteristic impedance R0 in terms of R1 and R2 and R0 in the circuit shown in question 6 is? |
| A. | R<sub>1</sub>+R<sub>2</sub>(R<sub>1</sub>+R<sub>0</sub>)/(R<sub>1</sub>+R<sub>0</sub>+R<sub>2</sub>) |
| B. | R<sub>1</sub>+ R<sub>2</sub>(R<sub>1</sub>+R<sub>0</sub>)/(R<sub>1</sub>+R<sub>0</sub>+R<sub>2</sub>) |
| C. | R<sub>2</sub>+ R<sub>2</sub>(R<sub>1</sub>+R<sub>0</sub>)/(R<sub>1</sub>+R<sub>0</sub>+R<sub>2</sub>) |
| D. | R<sub>0</sub>+R<sub>2</sub>(R<sub>1</sub>+R<sub>2</sub>)/(R<sub>1</sub>+R<sub>0</sub>+R<sub>2</sub>) |
| Answer» C. R<sub>2</sub>+ R<sub>2</sub>(R<sub>1</sub>+R<sub>0</sub>)/(R<sub>1</sub>+R<sub>0</sub>+R<sub>2</sub>) | |
| 13. |
Determine the value of N in the circuit shown in question 6. |
| A. | (R<sub>1</sub>+R<sub>2</sub>-R<sub>0</sub>)/R<sub>2</sub> |
| B. | (R<sub>1</sub>-R<sub>2</sub>-R<sub>0</sub>)/R<sub>2</sub> |
| C. | (R<sub>1</sub>+R<sub>2</sub>+R<sub>0</sub>)/R<sub>2</sub> |
| D. | (R<sub>1</sub>-R<sub>2</sub>+R<sub>0</sub>)/R<sub>2</sub> |
| Answer» D. (R<sub>1</sub>-R<sub>2</sub>+R<sub>0</sub>)/R<sub>2</sub> | |
| 14. |
The value of N in dB is? |
| A. | N= anti log (dB) |
| B. | N= anti log(dB/10) |
| C. | N=anti log(dB/20) |
| D. | N=anti log(dB/40) |
| Answer» D. N=anti log(dB/40) | |
| 15. |
What is the attenuation in dB assuming I1 is the input current and I2 is the output current leaving the port? |
| A. | 10 log<sub>10</sub> (I<sub>1</sub>/I<sub>2</sub>) |
| B. | 10 log<sub>10</sub> (I<sub>2</sub>/I<sub>1</sub>) |
| C. | 20 log<sub>10</sub> (I<sub>2</sub>/I<sub>1</sub>) |
| D. | 20 log<sub>10</sub> (I<sub>1</sub>/I<sub>2</sub>) |
| Answer» E. | |
| 16. |
If V1 is the voltage at port 1 and V2 is the voltage at port 2, then the attenuation in dB is? |
| A. | 20 log<sub>10</sub> (V<sub>1</sub>/V<sub>2</sub>) |
| B. | 10 log<sub>10</sub> (V<sub>1</sub>/V<sub>2</sub>) |
| C. | 20 log<sub>10</sub> (V<sub>2</sub>/V<sub>1</sub>) |
| D. | 10 log<sub>10</sub> (V<sub>2</sub>/V<sub>1</sub>) |
| Answer» B. 10 log<sub>10</sub> (V<sub>1</sub>/V<sub>2</sub>) | |
| 17. |
The attenuation in dB in terms of input power (P1) and output power (P2) is? |
| A. | log<sub>10</sub> (P<sub>1</sub>/P<sub>2</sub>) |
| B. | 10 log<sub>10</sub> (P<sub>1</sub>/P<sub>2</sub>) |
| C. | log<sub>10</sub> (P<sub>2</sub>/P<sub>1</sub>) |
| D. | 10 log<sub>10</sub> (P<sub>2</sub>/P<sub>1</sub>) |
| Answer» C. log<sub>10</sub> (P<sub>2</sub>/P<sub>1</sub>) | |