MCQOPTIONS
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MCQOPTIONS
This section includes 2167 Mcqs, each offering curated multiple-choice questions to sharpen your Php knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
KCU is used more than the other KCT and KCV. |
| A. | True |
| B. | False |
| Answer» B. False | |
| 2. |
Which of the following is not a correct designation of impact strength? |
| A. | KCU |
| B. | KCV |
| C. | KCT |
| D. | KCW |
| Answer» B. KCV | |
| 3. |
Which of the following properties is impact strength indicative of? |
| A. | Elasticity |
| B. | Hardness |
| C. | Stiffness |
| D. | Toughness |
| Answer» E. | |
| 4. |
What is the unit of impact strength? |
| A. | N/m |
| B. | MN/m |
| C. | MN/m2 |
| D. | N/m2 |
| Answer» D. N/m2 | |
| 5. |
Up till which point will a body regain its original shape? |
| A. | Yield point |
| B. | Elastic limit |
| C. | Fracture limit |
| D. | Ultimate tensile strength point |
| Answer» C. Fracture limit | |
| 6. |
Which of the following statements about mass spectrometers are not true? |
| A. | Time of flight mass spectrometer has the ability to record the entire mass spectrum at a time |
| B. | Time of flight mass spectrometers have poor resolution |
| C. | Conventional spectrometer detects only one peak at a time |
| D. | All spectrometers have the ability to record the entire mass spectrum at a time |
| Answer» E. | |
| 7. |
Which of the following is an ion optic device in which ions pass through a mirror and their flight is reversed? |
| A. | Reversal device |
| B. | Reflectron |
| C. | Mirror arrangement |
| D. | Separation chamber |
| Answer» C. Mirror arrangement | |
| 8. |
The current produced by ions arriving at the collector necessitates the use of which of the following? |
| A. | Wide band amplifier |
| B. | Narrow band amplifier |
| C. | Wide band filter |
| D. | Narrow band filter |
| Answer» B. Narrow band amplifier | |
| 9. |
Which of the following is not a component of the time of flight analyser spectrometer? |
| A. | Ion source |
| B. | Field free separation region |
| C. | Electron multiplication region |
| D. | Photo tube |
| Answer» E. | |
| 10. |
For the circuit diagram as depicted in the figure, the current per phase under balanced condition with a consumer end load of 90 kW, 414V operating at a power factor of 0.65 is ___________ |
| A. | 157.66 A |
| B. | 152 A |
| C. | 111.4 A |
| D. | 193.1 A |
| Answer» B. 152 A | |
| 11. |
The maximum rms voltage between one phase and ground neutral for a three phase 4-wire ac system will be ___________________ |
| A. | 171.46 kV |
| B. | 242.5 kV |
| C. | 221 kV |
| D. | 127 kV |
| Answer» B. 242.5 kV | |
| 12. |
The maximum rms voltage between one phase and ground neutral for a three phase 4-wire ac system will be ____________ |
| A. | 221.32 kV |
| B. | 313 kV |
| C. | 442 kV |
| D. | 127 kV |
| Answer» B. 313 kV | |
| 13. |
For a 2-wire ac single phase distribution system operating at ‘30’ MW and ‘315’ kV, operating at the power factor of 0.8 having 15Ω of resistance of each wire, then the power received at the consumer end will be ____________ |
| A. | 29.79 MW |
| B. | 29.895 MW |
| C. | 29.76 MW |
| D. | 29 MW |
| Answer» B. 29.895 MW | |
| 14. |
For a 2-wire ac single phase distribution system operating at ‘30’ MW and ‘315’ kV, operating at the power factor of 0.8 having 15Ω of resistance of each wire, then the copper loss at the substation in kW will be ___________ |
| A. | 210.67 |
| B. | 105.33 |
| C. | 240.87 |
| D. | 108.27 |
| Answer» B. 105.33 | |
| 15. |
If a 2-wire ac single phase distribution system operating at ‘30’ MW and ‘315’ kV, operating at the power factor of 0.8, then the current in the outer wire in kA is _____ |
| A. | 0.0838 |
| B. | 83.8 |
| C. | 8.38 |
| D. | 1.131 |
| Answer» B. 83.8 | |
| 16. |
If a 2-wire ac single phase distribution system operating at ‘P’ MW and ‘V’ kV, operating at the power factor of 0.8, then the current in the outer wire in kA is ______ |
| A. | 0.8P/V |
| B. | 1.131P/V |
| C. | 1.88P/V |
| D. | 0.088P/V |
| Answer» B. 1.131P/V | |
| 17. |
For the given circuit diagram for the substation fed with 315 kV, the voltage between the two outer conductors is ____________ |
| A. | 445.5 kV |
| B. | 890 kV |
| C. | 630 kV |
| D. | 223 kV |
| Answer» B. 890 kV | |
| 18. |
Falling edge of the SS pin denotes ________ |
| A. | end of the transfer |
| B. | starts a new transfer |
| C. | selects a new master |
| D. | none of the mentioned |
| Answer» C. selects a new master | |
| 19. |
When the buffer is ________ the low power mode is__________ |
| A. | empty, reset |
| B. | having one byte, reset |
| C. | full, reset |
| D. | empty, two |
| Answer» D. empty, two | |
| 20. |
Is SPI a full duplex technique? |
| A. | yes |
| B. | no |
| C. | cant be said |
| D. | depends on the conditions |
| Answer» B. no | |
| 21. |
The driving point impedance of an LC network is given by Z(s)=(s4+4s2+3)/(s3+2s). By taking the continued fraction expansion using second Cauer form, find the value of L4. |
| A. | 5 |
| B. | 2/5 |
| C. | 3/5 |
| D. | 4/5 |
| Answer» B. 2/5 | |
| 22. |
The driving point impedance of an LC network is given by Z(s)=(s4+4s2+3)/(s3+2s). By taking the continued fraction expansion using second Cauer form, find the value of C3. |
| A. | 25/s |
| B. | 2/25s |
| C. | 25/3s |
| D. | 25/4s |
| Answer» C. 25/3s | |
| 23. |
The driving point impedance of an LC network is given by Z(s)=(s4+4s2+3)/(s3+2s). By taking the continued fraction expansion using second Cauer form, find the value of L2. |
| A. | 1/5 |
| B. | 2/5 |
| C. | 3/5 |
| D. | 5/4 |
| Answer» E. | |
| 24. |
The driving point impedance of an LC network is given by Z(s)=(s4+4s2+3)/(s3+2s). By taking the continued fraction expansion using second Cauer form, find the value of C1. |
| A. | 2/3 |
| B. | 2/2 |
| C. | 1/2 |
| D. | 4/2 |
| Answer» B. 2/2 | |
| 25. |
The driving point impedance of an LC network is given by Z(s)=(2s5+12s3+16s)/(s4+4s2+3). By taking the continued fraction expansion using first Cauer form, find the value of L5. |
| A. | 2 |
| B. | 2/5 |
| C. | 2/7 |
| D. | 2/3 |
| Answer» E. | |
| 26. |
The driving point impedance of an LC network is given by Z(s)=(2s5+12s3+16s)/(s4+4s2+3). By taking the continued fraction expansion using first Cauer form, find the value of C4. |
| A. | 1/2 |
| B. | 1/4 |
| C. | 3/4 |
| D. | 1 |
| Answer» D. 1 | |
| 27. |
The driving point impedance of an LC network is given by Z(s)=(2s5+12s3+16s)/(s4+4s2+3). By taking the continued fraction expansion using first Cauer form, find the value of L3. |
| A. | 8 |
| B. | 8/3 |
| C. | 8/5 |
| D. | 8/7 |
| Answer» C. 8/5 | |
| 28. |
The driving point impedance of an LC network is given by Z(s)=(2s5+12s3+16s)/(s4+4s2+3). By taking the continued fraction expansion using first Cauer form, find the value of C2. |
| A. | 1 |
| B. | 1/2 |
| C. | 1/3 |
| D. | 1/4 |
| Answer» E. | |
| 29. |
Find the first reminder obtained by taking the continued fraction expansion in the driving point impedance of an LC network is given by Z(s)=(2s5+12s3+16s)/(s4+4s2+3). By taking the continued fraction expansion using first Cauer form. |
| A. | 4s3+10s |
| B. | 12s3+10s |
| C. | 4s3+16s |
| D. | 12s3+16s |
| Answer» B. 12s3+10s | |
| 30. |
The driving point impedance of an LC network is given by Z(s)=(2s5+12s3+16s)/(s4+4s2+3). By taking the continued fraction expansion using first Cauer form, find the value of L1. |
| A. | s |
| B. | 2s |
| C. | 3s |
| D. | 4s |
| Answer» C. 3s | |
| 31. |
Which of the following set is not joined by friction welding process? |
| A. | Aluminium to Steel |
| B. | Copper to Aluminium |
| C. | Copper to Titanium |
| D. | Rubidium to Caesium |
| Answer» E. | |
| 32. |
Which of the following is not the advantage of friction welding? |
| A. | No smoke generation during the process |
| B. | Less sparks are produced during the process |
| C. | Applicable for all metals |
| D. | Time saving process |
| Answer» D. Time saving process | |
| 33. |
Friction welding produces a _____ bond. |
| A. | metallic |
| B. | metallurgical |
| C. | ionic |
| D. | co-ordinate |
| Answer» C. ionic | |
| 34. |
In Direct Drive Friction Welding, energy is supplied by _____ |
| A. | an electromagnet |
| B. | a capacitor |
| C. | an electric motor |
| D. | a heating unit called heater |
| Answer» D. a heating unit called heater | |
| 35. |
Consider the one-dimensional heat conduction equation. Apply forward difference method to approximate time rate and central difference method to approximate x-derivative. The resulting equation is in _____________ |
| A. | Implicit linear form |
| B. | Explicit linear form |
| C. | Explicit non-linear form |
| D. | Implicit non-linear form |
| Answer» C. Explicit non-linear form | |
| 36. |
Which of these schemes will lead to an implicit problem? |
| A. | Higher-order schemes |
| B. | SIMPLE algorithm |
| C. | High-resolution scheme |
| D. | Crank-Nicolson scheme |
| Answer» E. | |
| 37. |
The time-step size in explicit schemes depends upon _____________ |
| A. | Grid size |
| B. | Number of iterations |
| C. | Total time interval |
| D. | Given mathematical equation |
| Answer» B. Number of iterations | |
| 38. |
Which of these may cause a problem to implicit schemes? |
| A. | Coupled equations |
| B. | Partial differential equations |
| C. | Non-linear equations |
| D. | Linear equations |
| Answer» D. Linear equations | |
| 39. |
Which of these is correct regarding implicit schemes? |
| A. | Truncation error is less |
| B. | Computation time is more |
| C. | Time-step size is small |
| D. | Easy to set-up |
| Answer» B. Computation time is more | |
| 40. |
What is advantageous in implicit schemes? |
| A. | Error |
| B. | Consistency |
| C. | Convergence |
| D. | Stability |
| Answer» E. | |
| 41. |
Which of these properties limit the time-step size in the explicit schemes? |
| A. | Convergence |
| B. | Stability |
| C. | Consistency |
| D. | Error |
| Answer» C. Consistency | |
| 42. |
Implicit time-based problems will result in __________ |
| A. | Coupled equations |
| B. | Uncoupled equations |
| C. | Linear equations |
| D. | Non-linear equations |
| Answer» B. Uncoupled equations | |
| 43. |
What is the main disadvantage of explicit schemes in a time-dependent problem? |
| A. | Marching solution |
| B. | Simultaneous equations |
| C. | Small time-step size |
| D. | Small grid size |
| Answer» D. Small grid size | |
| 44. |
Which of these methods of solving a system of equations will be needed after using an explicit scheme? |
| A. | Sequential |
| B. | Simultaneous |
| C. | Iterative |
| D. | Direct |
| Answer» B. Simultaneous | |
| 45. |
Which of the following are the components of a water cooling system? |
| A. | water jacket |
| B. | water pump |
| C. | fan |
| D. | all of the mentioned |
| Answer» B. water pump | |
| 46. |
The main disadvantage of forced cooling is that cooling is ensured under all conditions of operation. |
| A. | True |
| B. | False |
| Answer» C. | |
| 47. |
The circulation of water starts only after the engine has become hot enough to cause thermo-syphon. |
| A. | True |
| B. | False |
| Answer» B. False | |
| 48. |
In thermo-syphon cooling system, the cooling only depends on temperature and is independent of the engine speed. |
| A. | True |
| B. | False |
| Answer» B. False | |
| 49. |
The thermo-syphon cooling system can be used in high output engines due to its inability to meet the requirement of large flow rates of water. |
| A. | True |
| B. | False |
| Answer» C. | |
| 50. |
What are the various methods used for circulating water around the cylinder and cylinder heads? |
| A. | thermo-syphon cooling |
| B. | forced or pump cooling |
| C. | cooling with thermostatic regulator |
| D. | all of the mentioned |
| Answer» E. | |