MCQOPTIONS
Saved Bookmarks
MCQOPTIONS
This section includes 108 Mcqs, each offering curated multiple-choice questions to sharpen your Mathematics knowledge and support exam preparation. Choose a topic below to get started.
| 51. |
A lady has only 25 paise and 50-paise coins in her purse. She has a total of 120 coins and the total amount is Rs. 50. The number of coins of each type in her purse, respectively, is |
| A. | 90, 30 |
| B. | 60, 60 |
| C. | 40, 80 |
| D. | 70, 50 |
| Answer» D. 70, 50 | |
| 52. |
\[\left( 3A+B \right)-3\left( A-B \right)\]equals |
| A. | \[4A\] |
| B. | \[4B\] |
| C. | \[2A+2B\] |
| D. | \[4A-2B\] |
| Answer» C. \[2A+2B\] | |
| 53. |
The expression obtained when x is multipled by 2 and then subtracted from 3 is |
| A. | \[2x-3\] |
| B. | \[2x+3\] |
| C. | \[3-2x\] |
| D. | \[3x-2\] |
| Answer» B. \[2x+3\] | |
| 54. |
The solution of\[0.2(2x-1)-0.5(3x-1)=0.4\]is |
| A. | \[\frac{1}{11}\] |
| B. | \[-\frac{1}{11}\] |
| C. | \[\frac{3}{11}\] |
| D. | \[\frac{-3}{11}\] |
| Answer» C. \[\frac{3}{11}\] | |
| 55. |
If \[{{x}^{3}}-5x+7\] is divisible by \[(x+2)\], then the remainder is |
| A. | -21 |
| B. | -20 |
| C. | -17 |
| D. | -25 |
| Answer» B. -20 | |
| 56. |
What is the method of finding a solution by trying out various values for the variable called? |
| A. | Error method |
| B. | Trial and error method |
| C. | Testing method |
| D. | Checking method |
| Answer» C. Testing method | |
| 57. |
If \[p=-2,\] the value of\[-2{{p}^{3}}-3{{p}^{2}}+4p+7\] |
| A. | \[0\] |
| B. | \[1\] |
| C. | \[3\] |
| D. | \[-3\] |
| Answer» D. \[-3\] | |
| 58. |
DIRECTIONS: The questions in this segment consists of two statements, one labelled as "Assertion A" and the other labelled as "Reason R?. You are to examine these two statements carefully and decide if the Assertion A and Reason R are individually true and if so, whether the reason is a correct explanation of the assertion. Select your answers to these items using codes given below. Assertion: In the expression \[3{{x}^{2}}+7{{y}^{2}}-2xy\,+4{{x}^{2}}+8xy+9{{y}^{2}},\]\[3{{x}^{2}},\,4{{x}^{2}}\] are like terms, -2xy, 5xy are like terms and \[7{{y}^{2}},\,9{{y}^{2}}\] are like terms. Reason: When the terms have same literal factors they are called unlike terms. |
| A. | If both Assertion and Reason are correct and Reason is the correct explanation of Assertion. |
| B. | If both Assertion and Reason are correct, but Reason is not the correct explanation of Assertion. |
| C. | If Assertion is correct but Reason is incorrect. |
| D. | If Assertion is incorrect but Reason is correct. |
| Answer» D. If Assertion is incorrect but Reason is correct. | |
| 59. |
Consider the following statement. (i) To solve an equation means to find the value of the unknown variable in the equation. (ii) Value of the unknown variable is called the root of the equation. (iii) All monomials, binomials, trinomials, and polynomials are called by the name polynomial. Which of the statement (s) is/are true? |
| A. | (i), (ii) and (iii) |
| B. | (i) and (ii) |
| C. | (i) and (iii) |
| D. | (ii) and (iii) |
| Answer» E. | |
| 60. |
DIRECTIONS: Match Column-I with Column-II and select the correct answer using the codes given below the columns. A B C D |
| A. | 3412 |
| B. | 3142 |
| C. | 2314 |
| D. | 4312 |
| Answer» B. 3142 | |
| 61. |
Raju's father's age is 5 years more than three times Raju's age. Raju's father is 44 years old, equation to find Raju's age is:- |
| A. | 3 (Raju's age) + 5 = 44 |
| B. | 3 (Raju's age + 5) = 44 |
| C. | 5 (Raju's age) + 3 = 44 |
| D. | Either a or b |
| Answer» B. 3 (Raju's age + 5) = 44 | |
| 62. |
Standard form of 7000000 is |
| A. | \[7.0\times {{10}^{6}}\] |
| B. | \[0.7\times {{10}^{7}}\] |
| C. | \[70\times {{10}^{5}}\] |
| D. | \[70\times {{10}^{6}}\] |
| Answer» B. \[0.7\times {{10}^{7}}\] | |
| 63. |
DIRECTIONS: Read the passage(s) given below and answer the questions that follow. Passage ? 2 Rahul's mother's age is 5 years less than four times his age. Five years from now, what will be the age of Kabul's mother? |
| A. | \[4x+5\] years |
| B. | 4x + 10 years |
| C. | \[10x-5\] years |
| D. | 4x years |
| Answer» E. | |
| 64. |
If \[2{{x}^{3}}+4{{x}^{2}}+2ax+b\] is exactly divisible by \[{{x}^{2}}-1\],then the value of a and b respectively will be |
| A. | 1, 2 |
| B. | - 1, 4 |
| C. | 1, - 2 |
| D. | -1, - 4 |
| Answer» E. | |
| 65. |
Identify the equation with one variable from the following. |
| A. | \[\text{z+1224}\] |
| B. | \[\text{20-}\left( \text{10-5} \right)\text{=}\left( \text{3}\times \text{5} \right)\] |
| C. | \[\text{2n+1 =11}\] |
| D. | \[\frac{\text{3q}}{\text{2}}\text{0}\] |
| Answer» D. \[\frac{\text{3q}}{\text{2}}\text{0}\] | |
| 66. |
For her mobile phone service, Sachi pays Rs. 145 per month and 75 paise for each extra minute. She talks over the allowed number of minutes in the monthly plan. She received a bill of Rs.178 last month. How many extra minutes did she use her phone beyond the allowed time. |
| A. | 46 min |
| B. | 44 min |
| C. | 55 min |
| D. | 48 min |
| Answer» C. 55 min | |
| 67. |
Three prizes are to be distributed in a Mental Ability quiz contest. The value of the second prize is five-sixths the value of the first prize and the value of the third prize is four-fifths that of the second prize. If the total value of three prizes is Rs. 150, find the value of third prize. |
| A. | Rs. 40 |
| B. | Rs. 50 |
| C. | Rs. 60 |
| D. | Rs. 120 |
| Answer» B. Rs. 50 | |
| 68. |
Directions: Match Column-I with Column-II and select the correct answer using the codes given below the columns. |
| A. | \[A\to p;B\to s;C\to q;D\to r\] |
| B. | \[A\to s;B\to q;C\to r;D\to p\] |
| C. | \[A\to r;B\to p;C\to s;D\to q\] |
| D. | \[A\to q;B\to r;C\to p;D\to s\] |
| Answer» D. \[A\to q;B\to r;C\to p;D\to s\] | |
| 69. |
If \[f(x)=|x|\,\,\,\forall x\in R\], then the function is |
| A. | not one to one function |
| B. | one to one function |
| C. | into function |
| D. | not into function |
| Answer» D. not into function | |
| 70. |
Which is the correct expression for '-p multiplied by 5' ? |
| A. | \[-(-5p)\] |
| B. | \[-p+5\] |
| C. | \[-5p\] |
| D. | \[5-p\] |
| Answer» D. \[5-p\] | |
| 71. |
After 12 years I shall be 3 times as old as I was 4 years ago. Find my present age. |
| A. | 12 years |
| B. | 13 years |
| C. | 14 years |
| D. | 18 years |
| Answer» B. 13 years | |
| 72. |
A number is 56 greater then the average of its third, quarter and one twelfth. Find it. |
| A. | 53 |
| B. | 72 |
| C. | 85 |
| D. | 86 |
| Answer» C. 85 | |
| 73. |
The multiplicative inverse of\[{{(16)}^{2}}\]is |
| A. | \[{{(16)}^{1}}\] |
| B. | \[{{(16)}^{-2}}\] |
| C. | \[{{(16)}^{-3}}\] |
| D. | \[1\] |
| Answer» C. \[{{(16)}^{-3}}\] | |
| 74. |
The value of \[|-5-6|\times |-4+3|\]on simplification is |
| A. | 13 |
| B. | 12 |
| C. | 11 |
| D. | 10 |
| Answer» D. 10 | |
| 75. |
The smallest number, which must be added to 803642 in order to obtain a multiple ot 9, is |
| A. | 1 |
| B. | 2 |
| C. | 3 |
| D. | 4 |
| Answer» E. | |
| 76. |
If \[9{{x}^{2}}+48+p\] to be a perfect square , then the value of \[p\] is |
| A. | 81 |
| B. | 64 |
| C. | 36 |
| D. | 16 |
| Answer» C. 36 | |
| 77. |
L.C.M. of 125, 175 and 225 is |
| A. | 7875 |
| B. | 7575 |
| C. | 7075 |
| D. | 1235 |
| Answer» B. 7575 | |
| 78. |
Three bells, toll at intervals of 36 sec, 40 sec and sec respectively. They start ringing toll at particular time. They next toll together after |
| A. | 18 minutes |
| B. | 12 minutes |
| C. | 6 minutes |
| D. | 24 minutes |
| Answer» C. 6 minutes | |
| 79. |
The smaller value of n for which\[{{x}^{2}}-2x-3\]and\[{{x}^{3}}-2{{x}^{2}}-nx-3\]have an H.C.F. involving \[x\] is |
| A. | 0 |
| B. | 1 |
| C. | 2 |
| D. | 3 |
| Answer» D. 3 | |
| 80. |
The method of finding solution by trying out various values for the variable is called |
| A. | Error method |
| B. | Trial and error method |
| C. | Testing method |
| D. | Checking method |
| Answer» C. Testing method | |
| 81. |
The numerical coefficient of \[{{x}^{2}}\] in the expression\[{{x}^{3}}-5{{x}^{2}}-8x+4\] |
| A. | \[-\]8 |
| B. | 4 |
| C. | \[-\]5 |
| D. | 1 |
| Answer» D. 1 | |
| 82. |
If \[{{a}^{x}}=b,\,{{b}^{y}}=c,\,{{c}^{z}}=a\], then the value of \[xyz\] is |
| A. | 0 |
| B. | 1 |
| C. | \[\frac{1}{abc}\] |
| D. | abc |
| Answer» C. \[\frac{1}{abc}\] | |
| 83. |
In a piggy bank the number of 25 paise coins is five times the number of 50 paise coins. If there are 120 coins, find the amount in the bank. |
| A. | Rs. 25 |
| B. | Rs. 10 |
| C. | Rs. 35 |
| D. | Rs. 40 |
| Answer» D. Rs. 40 | |
| 84. |
If \[x=2,\] \[y=3\] and \[z=-5\] then \[{{x}^{3}}+\]\[{{y}^{3}}+\]\[{{z}^{3}}=?\] |
| A. | 90 |
| B. | \[-90\] |
| C. | 0 |
| D. | \[-90xyz\] |
| Answer» C. 0 | |
| 85. |
If \[{{56}^{2}}-{{51}^{2}}=5p\], then p is equal is |
| A. | 106 |
| B. | 107 |
| C. | 105 |
| D. | 104 |
| Answer» C. 105 | |
| 86. |
Additive inverse\[{{x}^{2}}-x+2\] |
| A. | \[-{{x}^{2}}+x-2\] |
| B. | \[{{x}^{2}}+x+2\] |
| C. | \[-{{x}^{2}}-x+2\] |
| D. | \[-{{x}^{2}}+x+2\] |
| Answer» B. \[{{x}^{2}}+x+2\] | |
| 87. |
The value of\[\left( {{a}^{3}}-2{{a}^{2}}+4a-5 \right)-\left( {{a}^{2}}+2{{a}^{2}}-8a+5 \right)\] |
| A. | \[2{{a}^{3}}-4{{a}^{2}}+12a-10\] |
| B. | \[2{{a}^{3}}-4{{a}^{2}}-12a+10\] |
| C. | \[2{{a}^{3}}+4{{a}^{2}}+12a+10\] |
| D. | \[2{{a}^{3}}-4{{a}^{2}}+12a+10\] |
| Answer» B. \[2{{a}^{3}}-4{{a}^{2}}-12a+10\] | |
| 88. |
If \[{{x}^{2}}+7ax+40=0\] and \[{{x}^{2}}+2ax-60=0\] have a common root, then the value of a is |
| A. | ± 1 |
| B. | ± 2 |
| C. | ± 3 |
| D. | ± 4 |
| Answer» C. ± 3 | |
| 89. |
The value of \[{{(625)}^{0.16}}\times {{(625)}^{0.09}}\]is |
| A. | 4 |
| B. | 5 |
| C. | 25 |
| D. | 625 |
| Answer» C. 25 | |
| 90. |
Which of the following equations has x = 2 as a solution? |
| A. | \[x+2=5\] |
| B. | \[x-2=0\] |
| C. | \[2x+1=0\] |
| D. | \[x+3=6\] |
| Answer» C. \[2x+1=0\] | |
| 91. |
The number of terms in the product of\[\left( 3x-2 \right)\] and\[\left( 2x+3 \right)\]is |
| A. | one |
| B. | two |
| C. | three |
| D. | four |
| Answer» D. four | |
| 92. |
a + b is a factor of |
| A. | \[{{a}^{4}}({{b}^{2}}-{{c}^{2}})+{{b}^{4}}({{c}^{2}}-{{b}^{2}})+{{c}^{4}}({{a}^{2}}-{{b}^{2}})\] |
| B. | \[a{{(b-c)}^{3}}+b{{(c-a)}^{3}}+c{{(a-b)}^{3}}\] |
| C. | \[{{(a+b+c)}^{3}}-{{(b+c-a)}^{3}}-{{(c+a-b)}^{3}}-{{(a+b-c)}^{3}}\] |
| D. | \[a({{b}^{4}}-{{c}^{4}})+b({{c}^{4}}-{{a}^{4}})+c({{a}^{4}}+{{b}^{4}})\] |
| Answer» B. \[a{{(b-c)}^{3}}+b{{(c-a)}^{3}}+c{{(a-b)}^{3}}\] | |
| 93. |
The sum of two numbers is 19 and one of the numbers is one more than twice the other. Represent this statement in the form of an equation using variable x. |
| A. | \[x(2x+1)=19\] |
| B. | \[x+(2x+1)\,=19\] |
| C. | \[x+(2x-1)\,=19\] |
| D. | \[x\div (2x-1)=19\] |
| Answer» C. \[x+(2x-1)\,=19\] | |
| 94. |
The condition that the roots of the equation \[l{{x}^{2}}+mx+n=0\] may be in the ratio 3: 4 is |
| A. | \[14{{n}^{2}}=49ml\] |
| B. | \[{{m}^{2}}=9nl\] |
| C. | \[12{{m}^{2}}=49nl\] |
| D. | \[4{{l}^{2}}=49nl\] |
| Answer» D. \[4{{l}^{2}}=49nl\] | |
| 95. |
The ratio of the ages of A and B ten years before was 3 : 5. The ratio of their present ages is 2 : 3. Their ages are respectively |
| A. | 30, 50 |
| B. | 20,30 |
| C. | 40, 60 |
| D. | 16, 24 |
| Answer» D. 16, 24 | |
| 96. |
If \[{{\log }_{10}}[{{\log }_{10}}(\log _{10}^{x})]=0\], then |
| A. | \[x={{10}^{3}}\] |
| B. | \[x={{10}^{10}}\] |
| C. | \[x={{10}^{5}}\] |
| D. | None of these |
| Answer» C. \[x={{10}^{5}}\] | |
| 97. |
If the roots of \[{{x}^{2}}-2mx+{{m}^{2}}-1=0\]lie between - 2 and 4, then |
| A. | \[-3\le m\le 4\] |
| B. | \[-3\le m\le 5\] |
| C. | \[-1\le m\le 5\] |
| D. | \[-1\le m\le 3\] |
| Answer» D. \[-1\le m\le 3\] | |
| 98. |
Given log 6 and log 8, then the only logarithm that cannot be obtained without using the table is |
| A. | log 64 |
| B. | log 21 |
| C. | \[\log \frac{8}{3}\] |
| D. | log 9 |
| Answer» C. \[\log \frac{8}{3}\] | |
| 99. |
The value of \[18-|-7|-|11-22|\]is equal to |
| A. | 58 |
| B. | 0 |
| C. | 41 |
| D. | 28 |
| Answer» C. 41 | |
| 100. |
A number consists of two digits. The sum of the digits is 11, reversing the digits, the number decreases by 45. The number is |
| A. | 38 |
| B. | 65 |
| C. | 74 |
| D. | 83 |
| Answer» E. | |