We know that the general form of quadratic equation is\xa0ax2+bx+c=0.The given equation is\xa0(x+2)3=2x(x2−1)\xa0can be simplified as follows:\xa0(x+2)3\xa0= 2x(x2−1)⇒x3+23+(3×x×2)( x+2)=2×3−2x (∵(a+b)3=a3+b3+3ab(a+b))⇒x3+8+6x(x+2)=2×3−2x⇒x3+8+6×2+12x=2×3−2x⇒x3+8+6×2+12x−2×3+2x=0⇒−x3+6×2+14x+8=0Since the variable\xa0x\xa0in the equation\xa0−x3+6×2+14x+8=0\xa0has degree\xa03, therefore, it is not of the form\xa0ax2+bx+c=0.Hence, the equation\xa0(x+2)3=2x(x2−1)\xa0is not a quadratic equation.
thank u