Which of the following transformations can be carried out by using HI as a reducing agent, under acidic conditions?
[Given : I2(s) → 2I−; E° = 0.54 V]
(i) Cu+ → Cu(s); E° = 0.52 V
(ii) Cr3+ → Cr2+; E° = − 0.41 V
(iii) Fe3+ → Fe2+; E° = 0.77 V
(iv) Fe2+ → Fe(s); E° = − 0.44 V
(a) (i) and (iii)
(b) (ii) and (iv)
(c) Only (iii)
(d) Only (ii)
Answer is : (c) Only (iii)
The more positive E° value of metal, feasible transformation can be carried out by using HI as reducing agent under acidic conditions.
As E° = 0.77 V(Fe3+ → Fe2+) is more positive than, E° = 0.54(I2(s) → 2I−) thus can be used for carrying out transformation as it is the strongest oxidising agent among the other given options.